confidence-interval

How to calculate confidence interval using the “bootstrap function” in R

丶灬走出姿态 提交于 2019-12-01 12:39:52
I am trying to calculate the confidence interval in R. Due to some special reasons, I have to do it with the functions in "bootstrap" package.(which means I can't use the functions in "boot" package.) Here is my code. And what I am doing is trying to calculate the Pearson correlation coefficient, and then apply the Bootstrap method (with B = 100) to obtain the estimate of the correlation coefficient. But I don't know how to construct the 95% confidence intervals. library(bootstrap) data('law') set.seed(1) theta <- function(ind) { cor(law[ind, 1], law[ind, 2], method = "pearson") } law.boot <-

How to calculate confidence interval using the “bootstrap function” in R

你离开我真会死。 提交于 2019-12-01 10:49:30
问题 I am trying to calculate the confidence interval in R. Due to some special reasons, I have to do it with the functions in "bootstrap" package.(which means I can't use the functions in "boot" package.) Here is my code. And what I am doing is trying to calculate the Pearson correlation coefficient, and then apply the Bootstrap method (with B = 100) to obtain the estimate of the correlation coefficient. But I don't know how to construct the 95% confidence intervals. library(bootstrap) data('law')

How do I plot confidence intervals in MATLAB?

喜夏-厌秋 提交于 2019-12-01 08:09:19
I want to plot some confidence interval graphs in MATLAB but I don't have any idea at all how to do it. I have the data in a .xls file. Can someone give me a hint, or does anyone know commands for plotting CIs? I'm not sure what you meant by confidence intervals graph, but this is an example of how to plot a two-sided 95% CI of a normal distribution: alpha = 0.05; % significance level mu = 10; % mean sigma = 2; % std cutoff1 = norminv(alpha, mu, sigma); cutoff2 = norminv(1-alpha, mu, sigma); x = [linspace(mu-4*sigma,cutoff1), ... linspace(cutoff1,cutoff2), ... linspace(cutoff2,mu+4*sigma)]; y

Gnuplot smooth confidence interval lines as opposed to error bars

房东的猫 提交于 2019-11-30 20:40:41
I'd like a 95% confidence interval line above and below my data line - as opposed to vertical bars at each point. Is there a way that I can do this in gnuplot without plotting another line? Or do I need to plot another line and then label it appropriately? You can use the filledcurves style to fill the region of 95% confidence. Consider the example data file data.dat with the content: # x y ylow yhigh 1 3 2.6 3.5 2 5 4 6 3 4 3.2 4.3 4 3.5 3.3 3.7 and plot this with the script set style fill transparent solid 0.2 noborder plot 'data.dat' using 1:3:4 with filledcurves title '95% confidence', \ '

Dotplot with error bars, two series, light jitter

北城以北 提交于 2019-11-30 08:57:38
I have a collection of data over several studies. For each study I am interested about the mean of a variable by gender, and if this significantly differs. For each study I have the mean and 95% confidence intervals for both males and females. What I would like to do is something similar to this: I have used several flavours of dotplots (dotplot, dotplot2, Dotplot) but did not quite get there. Using Dotplot from Hmisc I managed to have one series and its errorbars, but I am at a loss on how to adding the second series. I used Dotplot and got the vertical ending of the error bars following

Correct way to obtain confidence interval with scipy

余生颓废 提交于 2019-11-29 20:18:08
I have a 1-dimensional array of data: a = np.array([1,2,3,4,4,4,5,5,5,5,4,4,4,6,7,8]) for which I want to obtain the 68% confidence interval (ie: the 1 sigma ). The first comment in this answer states that this can be achieved using scipy.stats.norm.interval from the scipy.stats.norm function, via: from scipy import stats import numpy as np mean, sigma = np.mean(a), np.std(a) conf_int = stats.norm.interval(0.68, loc=mean, scale=sigma) But a comment in this post states that the actual correct way of obtaining the confidence interval is: conf_int = stats.norm.interval(0.68, loc=mean, scale=sigma

How to calculate the 95% confidence interval for the slope in a linear regression model in R

牧云@^-^@ 提交于 2019-11-29 20:15:35
Here is an exercise from Introductory Statistics with R: With the rmr data set, plot metabolic rate versus body weight. Fit a linear regression model to the relation. According to the fitted model, what is the predicted metabolic rate for a body weight of 70 kg? Give a 95% confidence interval for the slope of the line. rmr data set is in the 'ISwR' package. It looks like this: > rmr body.weight metabolic.rate 1 49.9 1079 2 50.8 1146 3 51.8 1115 4 52.6 1161 5 57.6 1325 6 61.4 1351 7 62.3 1402 8 64.9 1365 9 43.1 870 10 48.1 1372 11 52.2 1132 12 53.5 1172 13 55.0 1034 14 55.0 1155 15 56.0 1392 16

Get Confidence Interval For One Point On Regression Line In R?

泪湿孤枕 提交于 2019-11-29 08:35:34
How do I get the CI for one point on the regression line? I'm quite sure I should use confint() for that, but if I try this confint(model,param=value) it just gives me the same number as if I just type in confint(model) if I try without a value, it does not give me any values at all. What am I doing wrong? You want predict() instead of confint() . Also, as Joran noted, you'll need to be clear about whether you want the confidence interval or prediction interval for a given x. (A confidence interval expresses uncertainty about the expected value of y-values at a given x. A prediction interval

Dotplot with error bars, two series, light jitter

▼魔方 西西 提交于 2019-11-29 07:57:10
问题 I have a collection of data over several studies. For each study I am interested about the mean of a variable by gender, and if this significantly differs. For each study I have the mean and 95% confidence intervals for both males and females. What I would like to do is something similar to this: I have used several flavours of dotplots (dotplot, dotplot2, Dotplot) but did not quite get there. Using Dotplot from Hmisc I managed to have one series and its errorbars, but I am at a loss on how

Correct way to obtain confidence interval with scipy

折月煮酒 提交于 2019-11-28 15:59:06
问题 I have a 1-dimensional array of data: a = np.array([1,2,3,4,4,4,5,5,5,5,4,4,4,6,7,8]) for which I want to obtain the 68% confidence interval (ie: the 1 sigma). The first comment in this answer states that this can be achieved using scipy.stats.norm.interval from the scipy.stats.norm function, via: from scipy import stats import numpy as np mean, sigma = np.mean(a), np.std(a) conf_int = stats.norm.interval(0.68, loc=mean, scale=sigma) But a comment in this post states that the actual correct