conditional-statements

and if yes, what is the syntax? My goal is to prepend an 's' to the word 'comment' when there is more than one. in an jQuery.ejs template in a JMVC app. The following breaks. I can't find any docs for conditionals... <%=commentsNumber%> comment<% if (commentsNumber > 1) { %> s <% } %> For others that stumble on this, you can also use ejs params/props in conditional statements: recipes.js File: app.get("/recipes", function(req, res) { res.render("recipes.ejs", { recipes: recipes }); }); recipes.ejs File: <%if (recipes.length > 0) { %> // Do something with more than 1 recipe <% } %> Conditionals

I have a very basic R question but I am having a hard time trying to get the right answer. I have a data frame that looks like this: ind<-rep(1:4,each=24) hour<-rep(seq(0,23,by=1),4) depth<-runif(length(ind),1,50) df<-data.frame(cbind(species,ind,hour,depth)) df$depth<-as.numeric(df$depth) What I would like it to select AND replace all the rows where depth < 10 (for example) with zero, but I want to keep all the information associated to those rows and the original dimensions of the data frame. I have try the following but this does not work. df[df$depth<10]<-0 Any suggestions? # reassign

So this is from the Eloquent Javascript . I am trying to figure out how this code is actually stepped through. So we are trying to find a way to reach the target number by adding either 5 or multiplying by 3, and we start from the number 1. So, essentially, we are trying to find a sequence of such additions and multiplications that produce the target number? For example, the number 13 could be reached by first multiplying by 3 and then adding 5 twice, whereas the number 15 cannot be reached at all. Here is the code snippet: function findSolution(target) { function find(start, history) { if

This question already has an answer here: How to test multiple variables against a value? 21 answers Why does `a == b or c or d` always evaluate to True? 2 answers What silly mistake am I making here that is preventing me from determining that the first letter of user input is a consonant? No matter what I enter, it allows evaluates that the first letter is a vowel. original = raw_input('Enter a word:') word = original.lower() first = word[0] if len(original) > 0 and original.isalpha(): if first == "a" or "e" or "i" or "o" or "u": print "vowel" else: print "consonant" else: print "empty"

This question already has an answer here: How to test multiple variables against a value? 21 answers I'm learning Python and I'm having a little bit of a problem. Came up with this short script after seeing something similar in a course I'm taking. I've used "or" with "if" before with success (it doesn't show much here). For some reason I can't seem to get this working: test = raw_input("It's the flying circus! Cool animals but which is the best?") x = test.lower() if x == "monkey" or "monkeys": print "You're right, they are awesome!!" elif x != "monkey" or "monkeys": print "I'm sorry, you're