conditional-statements

Jenkins does not show variables output in ECHO request in the groovy-pipeline

吃可爱长大的小学妹 提交于 2021-01-29 17:46:05
问题 just for example. I have this part of code in groovy-pipeline: echo "${GIT_BRANCH}" if ("${GIT_BRANCH}" == 'origin/mysuperbranch') { echo 'Branch name is "${GIT_BRANCH}". We can continue' } else { echo 'Branch name is "${GIT_BRANCH}". We can not continue' isValid = false return true } And let's look on output: [Pipeline] echo origin/mysuperbranch [Pipeline] echo Branch name is "${GIT_BRANCH}". We can continue Why in first output i can see what is in the variable ${GIT_BRANCH} , but in the

Adapting existing excel function to find a match in a different column and remove digits

半世苍凉 提交于 2021-01-29 15:08:51
问题 I have the following example data set in excel. Currently, for reference, John,Smith is in A4 and Smith Johnson is in B4. Column 1 = Names of Members Column 2 = Attended (list of members that attended a meeting). Applied to column 1, I would like to add a function that turns GREEN any members that are in column 2 (attended) that are also in column 1. Like so: The solution used in the end was to use this formula, which does the trick: =SUMPRODUCT(--(MID($A4&" "&$A4,FIND(",",$A4)+2,FIND(",",$A4

Select entries that fulfil requirements laid out by dynamic table

爷,独闯天下 提交于 2021-01-29 08:18:54
问题 I'm attempting to do a keyword search which requires all conditions to be met for a result to be shown. I've created a method of making a custom table from a string which stores all of the keywords which are currently required for this search. I've been able to get it to happen for 'or' using the following dbo.MultipleTextSearchValuesOR - Is used to make the table of keywords select Title from vwIncidentSearchView inner join dbo.MultipleTextSearchValuesOR('Testing|Check') on Title Like id

Pandas DataFrames If else condition on multiple columns [duplicate]

核能气质少年 提交于 2021-01-29 07:36:07
问题 This question already has answers here : Multiple logical comparisons in pandas df (3 answers) Closed 8 months ago . I have a Data frame as shown below import pandas as pd df = pd.DataFrame({ "name": ["john","peter","john","alex"], "height": [6,5,4,4], "shape": ["null","null","null","null"] }) I want to apply this--- If name == john and height == 6 return shape = good else if height == 4 return shape = bad else change the shape to middle so the final Dataframe should look like this df = ({

Vba Numberformat muliple condtions to format cell value

元气小坏坏 提交于 2021-01-29 07:11:50
问题 Dear all i want to format my cell based on the Cell value. There are 3 possible Conditions: Cell is larger than 0.05 -> the Value should stay the same but be fromated to 0.0 Cell is smaller than 0.05 -> the Value should be replaced with a String "a.C." Cell is Zero -> the Value should be replaced with a Dash" I found thisSolution for the dashes and could combine it with the number formating .NumberFormat = "0.0;[=0]---" This works. but if i add an additonal argument the vba code breaks.

How to have vectorize calculation between a 1D and 2D numpy array with if conditions

和自甴很熟 提交于 2021-01-28 22:47:58
问题 I have a calculation using a 1D and a 2D numpy array. It has two levels of if -conditions. I was able to use np.where to avoid one if -statement and further use the slow list comprehension to iterate through each row. Ideally, I would like to vectorize the whole calculation process. Is it possible? Here is my code: import numpy as np r_base = np.linspace(0, 4, 5) np.random.seed(0) r_mat = np.array([r_base * np.random.uniform(0.9, 1.1, 5), r_base * np.random.uniform(0.9, 1.1, 5), r_base * np

R Ifelse: Find if any column meet the condition

守給你的承諾、 提交于 2021-01-28 18:00:51
问题 I'm trying to apply the same condition for multiple columns of an array and, then, create a new column if any of the columns meet the condition. I can do it manually with an OR statement, but I was wondering if there is an easy way to apply it for more columns. An example: data <- data.frame(V1=c("A","B"),V2=c("A","A","A","B","B","B"),V3=c("A","A","B","B","A","A")) data[4] <- ifelse((data[1]=="A"|data[2]=="A"|data[3]=="A"),1,0) So the 4th row is the only that doesn't meet the condition for

R Ifelse: Find if any column meet the condition

北慕城南 提交于 2021-01-28 17:53:36
问题 I'm trying to apply the same condition for multiple columns of an array and, then, create a new column if any of the columns meet the condition. I can do it manually with an OR statement, but I was wondering if there is an easy way to apply it for more columns. An example: data <- data.frame(V1=c("A","B"),V2=c("A","A","A","B","B","B"),V3=c("A","A","B","B","A","A")) data[4] <- ifelse((data[1]=="A"|data[2]=="A"|data[3]=="A"),1,0) So the 4th row is the only that doesn't meet the condition for

Python: exception of type index error?

爷,独闯天下 提交于 2021-01-28 15:29:31
问题 I have to write small sections of code for an introductory programming class I'm taking - I had no trouble until I tried this one. The code works fine so far as I can tell but I keep getting the IndexError, can anyone tell me what I'm missing? vowel = {"a", "e", "o", "i", "u", "A", "E", "I", "O", "U"} word = input("Enter a phrase: ") if word[0] in vowel: print("an", word) else: print("a", word) EDIT: The code's working perfectly now, all I needed was the additional if statement for an empty

How do you “pivot” using conditions, aggregation, and concatenation in Pandas?

核能气质少年 提交于 2021-01-28 14:05:13
问题 I have a dataframe in a format such as the following: Index Name Fruit Quantity 0 John Apple Red 10 1 John Apple Green 5 2 John Orange Cali 12 3 Jane Apple Red 10 4 Jane Apple Green 5 5 Jane Orange Cali 18 6 Jane Orange Spain 2 I need to turn it into a dataframe such as this: Index Name All Fruits Apples Total Oranges Total 0 John Apple Red, Apple Green, Orange Cali 15 12 1 Jane Apple Red, Apple Green, Orange Cali, Orange Spain 15 20 Question is how do I do this? I have looked at the groupby