conditional-statements

问题 How to find row by column with null value? It doesn't work: $criteria->condition = '`seller_id` IS NULL'; 回答1: $criteria->addCondition('seller_id IS NULL'); $data= MODEL::model()->find($criteria); tried this? **seller_id** is the mapped column name in Yii , it may not be same as the actual column name in your database. 来源： https://stackoverflow.com/questions/5349788/yii-condition-is-null

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: R: subset() logical-and operator for combining conditions should be & not && I have a simple question, but I don't know how to solve this... I want to select all rows where value_1 > 0 and value_2 > 0. Now I have this code: dataOnBoth<-data[data$value_1 > 0,][data$value_2 > 0,] When I head this data, ordering on log2_fold_change, I have This output: gene_id sample_1 sample_2 status value_1 value_2 log2_fold

问题 i would have to show the table of reservation of 3 biens it should show me 3 line of 3 reservation but it show me just one line in the controllers public function index_hote() { $this->Reservation->recursive = 1; $this->loadModel("BiensPersonne"); if($this->Session->read('Auth.User.0.Personne.id')){ $options = $this->BiensPersonne->findByPersonneId($this->Session- >read('Auth.User.0.Personne.id')); $this->loadModel("Personne"); $biens=$this->Personne->findById( $options['BiensPersonne'][

问题 I use PostgreSQL 9.1.2 and I have a basic table as below, where I have the Survival status of an entry as a boolean (Survival) and also in number of days (Survival(Days)) . I have manually added a new column named 1-yr Survival and now I want to fill in the values of this column for each entry in the table, conditioned on that entry's Survival and Survival (Days) column values. Once , completed the database table would look something like this: Survival Survival(Days) 1-yr Survival ----------

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Check if a variable is empty Simple PHP question: I have this stement: if (isset($_POST["password"]) && ($_POST["password"]=="$password")) { ...//IF PASSWORD IS CORRECT STUFF WILL HAPPEN HERE } Somewhere above this statement I use the following line in my JavaScript to set the username as a variable both in my JavaScript and in my PHP: uservariable = <?php $user = $_POST['user']; print ("\"" . $user . "\"")?>;

问题 I want to only include history and ajaxify if the browser is ie9 or greater, OR is not ie: <!--[if gte IE 9]> <script type="text/javascript" src="assets/js/plugins/history.js"></script> <script type="text/javascript" src="assets/js/plugins/ajaxify.js"></script> <![endif]--> How can I use the OR operator to say this: <!--[if gte IE 9 | !IE ]> ?? Thanks! 回答1: This worked: <!--[if gte IE 9 | !IE ]><!--> <script type="text/javascript" src="assets/js/plugins/history.js"></script> <script type=

问题 I want to only include history and ajaxify if the browser is ie9 or greater, OR is not ie: <!--[if gte IE 9]> <script type="text/javascript" src="assets/js/plugins/history.js"></script> <script type="text/javascript" src="assets/js/plugins/ajaxify.js"></script> <![endif]--> How can I use the OR operator to say this: <!--[if gte IE 9 | !IE ]> ?? Thanks! 回答1: This worked: <!--[if gte IE 9 | !IE ]><!--> <script type="text/javascript" src="assets/js/plugins/history.js"></script> <script type=

问题 So for this program I need to obtain three strings from a user and sort those strings alphabetically. The caveat is that I cannot use arrays. Also if the string does not start with an alphabetic letter than it is not accepted. So far I have managed to get the three strings from the user and am able to determine if they should be accepted on or not. What I can't figure out is how to sort them alphabetically. The main issue I am having is ignoring the strings that weren't accepted when sorting.

问题 I need to filter by conditions when Plan_Year is 1 less than YEAR and all rows of NA in CAT column. I have the following code: Table <- Table %>% filter(YEAR == Plan_Year+1) How can I include/modify the code above to obtain all rows with NA in CAT column? Thanks in advance. Table: YEAR CAT Plan_Year 1998 NA NA 1998 125-1 1997 1998 171-2 1997 1998 NA NA . . 2017 114-1 202 回答1: using | and is.na Table %>% filter(YEAR == Plan_Year+1|is.na(CAT)) YEAR CAT Plan_Year 1 1998 <NA> NA 2 1998 125-1 1997

问题 After searching a lot, I have to ask experts here... Table 1 (attendance) att_id att_date class_id student_id att_status 1 07-11-2013 1 1 P 2 07-11-2013 1 2 L 3 07-11-2013 1 3 P 4 07-11-2013 1 4 P 5 08-11-2013 2 5 P 6 08-11-2013 2 6 P 7 08-11-2013 2 7 A 8 08-11-2013 2 8 P 9 09-11-2013 1 1 L 10 09-11-2013 1 2 P 11 09-11-2013 1 3 A 12 09-11-2013 1 4 P 13 09-11-2013 2 5 P Where in att_status P=Present, A=Absence, L=Leave. Now I want to count individual student Present, Absent and Leave based on