concatenation

问题 I am having a hard time understanding the following syntax in verilog: input [15:0] a; // 16-bit input output [31:0] result; // 32-bit output assign result = {{16{a[15]}}, {a[15:0]}}; I know the assign statement will wire something up to the result bus using wires and combinational logic, but what's up with the curly braces and 16{a[15]}? 回答1: The curly braces mean concatenation, from most significant bit (MSB) on the left down to the least significant bit (LSB) on the right. You are creating

问题 I have a number of ranges to concatenate independently and put the values of the concatenated ranges into different cells. I want to: concatenate values in Range A1:A10 and put the result in F1 then concatenate the Range B1:B10 and put the result in F2 then concatenate the Range C1:C10 and put the result in F3 etc. The following macro concatenates range A1:A10 and then puts the results into F1 (which is what I want). However it also stores the information from the first concatenation into

问题 I am using this var abc = jQuery('#pl_hid_addon_name').val(); alert(abc); var atLeastOneIsChecked = jQuery('input[name="addon-"'+abc+']:checked').length ; alert(atLeastOneIsChecked); But it not worked It should be after concatenate like below var atLeastOneIsChecked = jQuery('input[name="addon-base-bar2[]"]:checked').length; 回答1: var atLeastOneIsChecked = jQuery('input[name="addon-"'+abc+']:checked').length; ^ | You used the closing " at the wrong place var atLeastOneIsChecked = jQuery('input

问题 Given two dataframes a and b : > a a b c 1 -0.2246894 -1.48167912 -1.65099363 2 0.5559320 -0.87898575 -0.15634590 3 1.8469466 -0.01487524 -0.53098215 4 -0.6875051 0.23880967 0.01824621 5 -0.6735163 0.75485292 0.44154092 > b a c 1 0.4287284 -0.3295925 2 0.5201492 0.3341251 3 -2.6355570 1.7916780 4 -1.3645337 1.3642276 5 -0.4954542 -0.6660001 Is there a simple way to concatenate these so as to return a new data frame of the form below? > new a b c 1 -0.2246894 -1.48167912106676 -1.65099363 2 0

问题 Given two dataframes a and b : > a a b c 1 -0.2246894 -1.48167912 -1.65099363 2 0.5559320 -0.87898575 -0.15634590 3 1.8469466 -0.01487524 -0.53098215 4 -0.6875051 0.23880967 0.01824621 5 -0.6735163 0.75485292 0.44154092 > b a c 1 0.4287284 -0.3295925 2 0.5201492 0.3341251 3 -2.6355570 1.7916780 4 -1.3645337 1.3642276 5 -0.4954542 -0.6660001 Is there a simple way to concatenate these so as to return a new data frame of the form below? > new a b c 1 -0.2246894 -1.48167912106676 -1.65099363 2 0

问题 I need to concatenate an integer to a system call string: status = system("./run test.txt " + integer); integer here can be any int. What is the best way of doing this? 回答1: Use snprintf (or sprintf if you don't have snprintf or need your code to run on systems without it) to print to a char buffer, and pass that to the system call. e.g. #define MAX_LEN 128 char buffer[MAX_LEN]; int val = 0; snprintf(buffer, MAX_LEN, "./run test.txt %d", val); // you would be wise to check that snprintf has

问题 I'm trying to write a procedure that concatenates all rows in a table in the case in which the row number is unknown. I have this code but it is not working. CREATE PROCEDURE Test (OUT r VARCHAR(3000)) BEGIN DECLARE RowCnt INT; DECLARE CurrRow INT ; SET CurrRow = 1, r = 'SELECT ', RowCnt = (SELECT COUNT(*) FROM tableWithSQLStmnts ) WHILE CurrRow <= RowCnt DO BEGIN SET r = r + CASE WHEN CurrRow = 1 THEN 'MAX( CASE Seq WHEN ' + CAST( CurrRow AS VARCHAR ) + ' THEN SqlStmnt ELSE SPACE(0) END ) +

问题 Consider the following text file (test.txt) : 1 1 1 7 7 6 and the awk script (test.awk) { print "$0 : ", $0 lines=(lines $0) print "lines : ", lines } Then running: awk -f test.awk test.txt gives output $0 : 1 1 1 lines : 1 1 1 $0 : 7 7 6 7 7 6 : 1 1 1 while the expected output should (as far as I can see) have been: $0 : 1 1 1 lines : 1 1 1 $0 : 7 7 6 lines : 1 1 17 7 6 what am I missing here? (I am using GNU Awk 3.1.8 on Ubuntu 12.04) 回答1: You've got DOS line endings in test.txt (CRLF, or

问题 Assume a text file ( file1 ) that contains m lines of alphabetic strings S ( S_1 , S_2 , ..., S_m ). Each S is preceded by a short alphanumeric string that acts as a barcode (here: foo1 , bar7 , baz3 ). The alphabetic strings S are all identical in length. Each S and its preceding barcode is separated by a whitespace. $ cat file1 foo1 abcdefghijklmnopqrstuvwxyz bar7 abcdefghijklmnopqrstuvwxyz baz3 abcdefghijklmnopqrstuvwxyz Assume a second file ( file2 ) that contains n specifications of

问题 I have cells saved as Data , Date , Lat , Lon , and uID . There are 1210 cells and each cell has either 365 or 366 days. The 1210 cells are the total number of sites for 2008-2014 (so there are a lot of repeats - for a site that has data from 2008-2014, it would show up 7 times). The 365 or 366 rows in each of these cells are the data for one year for that location for the years. How can I find the indexes where the the Date matches and concatenate all the Data , uID , Lat , and Lon into on