concatenation

问题 I'm looking for an easy way to assign to a variable depending on the value of another variable. device.slot2_clipList[clipNumber] = singleClipDetails; what I'm trying to do is: replace the "2" with another variable, so that i can run the same operation while just changing the var slotNumber, and write to the corresponding variable. i tried device.slot + device.slotNumber + _clipList[clipNumber] but (obviously?), this doesn't work. How can this be done? (Maybe I named the Question incorrectly,

问题 I have a issue with my java code. i asked the same question yesterday. I got answer but sorry it was my fault. My question is not clear. I have code looks like this: for(i = 0; i < geo.getTargets().length ; i++ ) { if(geo.getTargets(i).getTargetType().equalsIgnoreCase("ProximityTarget")) { final ProximityTarget prox = (ProximityTarget)geo.getTargets(i); prox.getGeoPoint().getLatitudeInMicroDegrees(); prox.getGeoPoint().getLongitudeInMicroDegrees(); prox.getRadiusDistanceUnits(); } } The above

问题 I'm trying to play a few WAV files after each other. I tried this method: for (String file : audioFiles) { new AePlayWave(file).start(); } But that plays them all at the same time. So I need a function that looks like this: public void play(Vector<String> audioFiles); The vector contains the files, for example: "test1.wav" , "test2.wav" I have been looking for over four hours, but I can't seem to find a working solution :( I also tried concatenating the WAV files to one AudioInputStream. It

问题 I am trying to generate a numpy array with elements as two other numpy arrays, as below. W1b1 = np.zeros((256, 161)) W2b2 = np.zeros((256, 257)) Wx = np.array([W1b1, W2b2], dtype=np.object) this gives an error: ValueError: could not broadcast input array from shape (256,161) into shape (256). However, if I take entirely different dimensions for of W1b1 and W2b2 then I do not get an error, as below. A1 = np.zeros((256, 161)) A2 = np.zeros((257, 257)) A3 = np.array([A1, A2], dtype=np.object) I

问题 I want equivalent to GROUP_CONCAT functionality of MySql in DB2. I have tried XML Aggrigate functon of DB2 for cocating murows. SELECT a.ID, substr(xmlserialize(xmlagg(xmltext( concat(',', SPECIALISATION)))as varchar( 1024 )),2), substr(xmlserialize(xmlagg(xmltext(concat(',,, BASIC_SKILL2)))as varchar( 1024 )),2), substr(xmlserialize(xmlagg(xmltext(concat(',', BASIC_SKILL1)))as varchar( 1024 )),2) FROM candidate_resume_data a,candidate_skills_info b,skill_special_master c,skill_master_basic2

问题 Consider the following scenario: std::vector<int> A; std::vector<int> B; std::vector<int> AB; I want AB to have contents of A and then the contents of B in the same order. Approach 1: AB.reserve( A.size() + B.size() ); // preallocate memory AB.insert( AB.end(), A.begin(), A.end() ); AB.insert( AB.end(), B.begin(), B.end() ); Approach 2: std::vector<int> AB ( A.begin(), A.end() ); // calling constructor AB.insert ( AB.end(), B.begin(), B.end() ); Which one of the above methods is more

问题 Consider the following scenario: std::vector<int> A; std::vector<int> B; std::vector<int> AB; I want AB to have contents of A and then the contents of B in the same order. Approach 1: AB.reserve( A.size() + B.size() ); // preallocate memory AB.insert( AB.end(), A.begin(), A.end() ); AB.insert( AB.end(), B.begin(), B.end() ); Approach 2: std::vector<int> AB ( A.begin(), A.end() ); // calling constructor AB.insert ( AB.end(), B.begin(), B.end() ); Which one of the above methods is more

问题 i was wondering if there was a way to add a value to a string, not like 1 + 1 = 2 but like 1 + 1 = 11. 回答1: I think you need string concatenation: #include <stdio.h> #include <string.h> int main() { char str1[50] = "Hello "; char str2[] = "World"; strcat(str1, str2); printf("str1: %s\n", str1); return 0; } from: http://irc.essex.ac.uk/www.iota-six.co.uk/c/g6_strcat_strncat.asp 回答2: To concatenate more than two strings, you can use sprintf, e.g. char buffer[101]; sprintf(buffer, "%s%s%s%s",

问题 I have three matrices, each of size 4x1 . I want to copy all of these matrices to another matrix of size 4x3 and call it R . Is there a smart way to do it? 回答1: You can just use hconcat for horizontal concatenation. You can use it per matrix, e.g. hconcat( mat1, mat2, R ), or apply it directly on a vector or array of matrices. Here's a sample code: vector<Mat> matrices = { Mat(4, 1, CV_8UC1, Scalar(1)), Mat(4, 1, CV_8UC1, Scalar(2)), Mat(4, 1, CV_8UC1, Scalar(3)), }; Mat R; hconcat( matrices,

问题 I just wanted to concatenate multiple arrays in Ruby and couldn't find a satisfying way to do so. Example input: foo = [1, 2, 3] bar = [4, 5, 6] baz = [7, 8, 9] Expected result: (without modifying the existing arrays) [1, 2, 3, 4, 5, 6, 7, 8, 9] My actual arrays are much larger, so I'm interested in an efficient solution. There may also be more than three arrays, so a short syntax is preferred. What I have tried so far foo + bar + baz is the obvious one, it's concise and clear. But it is