concatenation

问题 I'm looking a way to join every two elements together using XPath2.0: <item> <element class='1'>el1</element> <element class='2'>el2</element> <break>break</break> <element class='1'>el3</element> <element class='2'>el4</element> <break>break</break> <element class='1'>el5</element> <element class='2'>el6</element> <break>break</break> <element class='1'>el7</element> <element class='2'>el8</element> </item> I am hoping the result will be like: el1el2 el3el4 el5el6 el7el8 The are "breaks"

问题 I'm looking a way to join every two elements together using XPath2.0: <item> <element class='1'>el1</element> <element class='2'>el2</element> <break>break</break> <element class='1'>el3</element> <element class='2'>el4</element> <break>break</break> <element class='1'>el5</element> <element class='2'>el6</element> <break>break</break> <element class='1'>el7</element> <element class='2'>el8</element> </item> I am hoping the result will be like: el1el2 el3el4 el5el6 el7el8 The are "breaks"

问题 I have a form that submits a report about checkpoints. Each checkpoint has a "status" and a "comment". The form is set up so it returns a multi-dimensional array with the key being the checkpoint ID like this: array(3) { ["status"]=> array(2) { ["000046"]=> string(1) "S" ["000047"]=> string(1) "S" } ["comment"]=> array(2) { ["000046"]=> string(6) "Flarg." ["000047"]=> string(0) "" } ["submit"]=> string(13) "SUBMIT REPORT" } In the above, checkpoint 000046 has a status of "S" and a comment of

问题 I have two lists of end points that look like this: t1 = [0,13,22] t2 = [4,14,25] I am looking for the most efficient way to generate an output that looks like this: [0,1,2,3,4,13,14,22,23,24,25] Thank you guys in advance 回答1: You can use a nested list commprehension: [i for a, b in zip(t1, t2) for i in range(a, b + 1)] 来源： https://stackoverflow.com/questions/55877743/selecting-a-subset-of-integers-given-two-lists-of-end-points

问题 To concatenate results from xpath, i'm using concat(normalize-space(.), ' ') (Thanks to Dimitre Novatchev). Now i'm wondering how to avoid adding after the last element... I'm thinking about something like: concat(normalize-space(.), if(XXXXX) then ' ' else '') but I couldn't figure out what condition do I have to use. For example, If I'm using xpathExpression/concat(normalize-space(.), ',') and the values requested are (strings) A & B & C & D, the output I'm expecting is A,B,C,D instead of

问题 I just recently started learning Basics in Java, and was testing around initializing a string variable by concatenating primitive variables. public class Main{ public static void main(String[] args){ byte lbyte = 3; short lshort = 1; int lint = 1; long llong = 0; float lfloat = 2.0f; double ldouble = lfloat; char lchar = 'H'; boolean lbool = true; String lstring = " w0r1d "; String lOutput = lchar+lbyte+lshort+lint+llong+lstring+ldouble+' '+lbool; System.out.println(lOutput); } } In this code

问题 If I have a string array, for example: var array = new[] { "the", "cat", "in", "the", "hat" } , and I want to join them with a space between each word I can simply call String.Join(" ", array) . But, say I had an array of integer arrays (just like I can have an array of character arrays). I want to combine them into one large array (flatten them), but at the same time insert a value between each array. var arrays = new[] { new[] { 1, 2, 3 }, new[] { 4, 5, 6 }, new { 7, 8, 9 }}; var result =

问题 I have a dataframe where I would like to concatenate certain columns. My issue is that the text in these columns may or may not contain duplicate information. I would like to strip out the duplicates in order to retain only the relevant information. For example, if I had a data frame such as: Animal1 Animal2 Label 1 cat dog dolphin 19 2 dog cat cat 72 3 pilchard 26 koala 26 4 newt bat 81 bat 81 You can see that in row 2, 'cat' is contained in both columns 'Animal1' and 'Animal2'. In row 3,

问题 in order to become familar with Erlang, i'm trying to write my own Bubblesort Algorithm. Right now, i have the following code in my module: -module(mysort). -export([bubblesort/1]). bubblesort(L) -> sort_sequence(L, []). sort_sequence([H1|[H2|T]], Sorted) -> if H2 >= H1 -> sort_sequence(T, Sorted ++ [H1, H2]); H2 < H1 -> sort_sequence(T, Sorted ++ [H2, H1]) end; sort_sequence([H|T], Sorted) -> Sorted ++ H; sort_sequence([], Sorted) -> Sorted. first of all: please don't give me suggestions to

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . I'm getting this error: Parse error: syntax error, unexpected '.', expecting ',' or ';' in /var/(...)/config.php on line 5 With this (simplified) code: <