concatenation

Concatenating a string and byte array in to unmanaged memory

老子叫甜甜 提交于 2020-01-16 18:30:27
问题 This is a followup to my last question. I now have a byte[] of values for my bitmap image. Eventually I will be passing a string to the print spooler of the format String.Format("GW{0},{1},{2},{3},", X, Y, stride, _Bitmap.Height) + my binary data; I am using the SendBytesToPrinter command from here. Here is my code so far to send it to the printer public static bool SendStringPlusByteBlockToPrinter(string szPrinterName, string szString, byte[] bytes) { IntPtr pBytes; Int32 dwCount; // How

Concatenating a string and byte array in to unmanaged memory

*爱你&永不变心* 提交于 2020-01-16 18:30:07
问题 This is a followup to my last question. I now have a byte[] of values for my bitmap image. Eventually I will be passing a string to the print spooler of the format String.Format("GW{0},{1},{2},{3},", X, Y, stride, _Bitmap.Height) + my binary data; I am using the SendBytesToPrinter command from here. Here is my code so far to send it to the printer public static bool SendStringPlusByteBlockToPrinter(string szPrinterName, string szString, byte[] bytes) { IntPtr pBytes; Int32 dwCount; // How

Concatenating Multiple DataFrames with Non-Standard Columns

血红的双手。 提交于 2020-01-16 18:18:20
问题 Is there a good way to concatenate a list of DataFrames where the columns are not regular between DataFrames? The desired outcome is to match up all columns that are a match but to keep the ones that have no match off to the side. The reason you would want to keep the unmatched columns is because while there may not be a match on a given column between the 1st and 2nd dataframes in the list there may be a match between the 1st and 3rd. Thus discarding prematurely on the first lack of match

Concatenating Multiple DataFrames with Non-Standard Columns

孤街醉人 提交于 2020-01-16 18:18:10
问题 Is there a good way to concatenate a list of DataFrames where the columns are not regular between DataFrames? The desired outcome is to match up all columns that are a match but to keep the ones that have no match off to the side. The reason you would want to keep the unmatched columns is because while there may not be a match on a given column between the 1st and 2nd dataframes in the list there may be a match between the 1st and 3rd. Thus discarding prematurely on the first lack of match

Concatenate alternate characters from different columns in R programming

送分小仙女□ 提交于 2020-01-16 15:25:43
问题 I have a df with 2 columns. I need to combine Col1 and Col2 in Col3 - alternate text separated by ">" a1-b1;a2-b2;a3-b3;... Example | Col1 | Col2 | Col3 | | abcd > de > efg | ppppp > ppt > pp | abcd-ppppp > de-ppt > efg-pp | | hij > kl > iiii | aaa > bbb > hhh | hij-aaa > kl-bbb > iiii-hhh | | aa | fff | aa-fff | | a > bbb | pp > a | a-pp > bbb-a | .... How can I do that in R programming? Thanks 回答1: This was a pain in the ass to solve. In the future, for our sanity please consider how you

Concatenating dictionaries of numpy arrays of different lengths (avoiding manual loops if possible)

有些话、适合烂在心里 提交于 2020-01-15 06:02:05
问题 I have a question similar to the one discussed here Concatenating dictionaries of numpy arrays (avoiding manual loops if possible) I am looking for a way to concatenate the values in two python dictionaries that contain numpy arrays of arbitrary size whilst avoiding having to manually loop over the dictionary keys. For example: import numpy as np # Create first dictionary n1 = 3 s = np.random.randint(1,101,n1) n2 = 2 r = np.random.rand(n2) d = {"r":r,"s":s} print "d = ",d # Create second

How to append a sequential number for every element in a data frame?

安稳与你 提交于 2020-01-14 14:24:26
问题 This question is a follow-up to How to append column number in front of every element? V1 <- c("a", "a", "b", "b", "b") V2 <- c("c" ,"d", "e" ,"e", "f") V3 <- c("i", "j", "k", "l", "m") df <- data.frame(V1, V2, V3) df[] <- Map(paste0, seq_along(df), df) OUTPUT V1 V2 V3 1 1a 2c 3i 2 1a 2d 3j 3 1b 2e 3k 4 1b 2e 3l 5 1b 2f 3m How can I create the following output instead? V1 V2 V3 1 1.1.a 2.1.c 3.1.i 2 1.1.a 2.2.d 3.2.j 3 1.2.b 2.3.e 3.3.k 4 1.2.b 2.3.e 3.4.l 5 1.2.b 2.4.f 3.5.m 回答1: Another

How should I modify this SQL statement?

走远了吗. 提交于 2020-01-14 13:29:19
问题 My SQL Server view SELECT geo.HyperLinks.CatID, geo.Tags.Tag, geo.HyperLinks.HyperLinksID FROM geo.HyperLinks LEFT OUTER JOIN geo.Tags INNER JOIN geo.TagsList ON geo.Tags.TagID = geo.TagsList.TagID ON geo.HyperLinks.HyperLinksID = geo.TagsList.HyperLinksID WHERE HyperLinksID = 1 returns these... HyperLinksID CatID Tags 1 2 Sport 1 2 Tennis 1 2 Golf How should I modify the above to have results like HyperLinksID CatID TagsInOneRowSeperatedWithSpaceCharacter 1 2 Sport Tennis Golf UPDATE: As

MS Access - How do I display two fields from separate records on the same line based on their ID and Date?

Deadly 提交于 2020-01-13 18:19:21
问题 I don't know if this is even possible or perhaps my database is designed poorly and I could have done it a better way? Anyway here goes, I have database with two tables as follows " General Data " and " Assessment Data " - they're set up so that a patient can have a few basic details entered into "General Data" and then each time they have an assessment they have data relevant to that assessment entered into the "Assessment Data" table Sorry about the dodgy formatting! Not enough reputation

PHP/mySQL: How do a concatenate a variable in a mysql query?

懵懂的女人 提交于 2020-01-13 18:09:52
问题 What is the proper way to concatenate text and a variable in PHP inside a mysql_query? Here is my attempt: page.'$pageID' I want it to output page3 . Here is all of the code (simplified to focus on the mysql_query): if ($_POST['pageProgress']) { $pageProgress = $_POST['pageProgress']; $pageID = 3; $userID = 1; $updateUserProgress = mysql_query("UPDATE test SET page.'$pageID'='$pageProgress' WHERE userID='$userID'") or die(mysql_error()); } All of the code works perfectly if I simply replace