concat

String Concat With Same Reference? [duplicate]

纵饮孤独 提交于 2019-12-06 04:44:54
问题 This question already has answers here : a confusion about java String literal pool and String's concatenation (4 answers) When should we use intern method of String on String literals (13 answers) Closed 3 years ago . Here is my code and I am now quite confuse about String pool and Heap storage by this output. public class String1 { public static void main(String[] args) { // TODO Auto-generated method stub String str = "abcd"; String str1 = "" ; str1=str1+"abcd"; if(str.equals(str1)) System

Shifting 2D array Verilog

我的梦境 提交于 2019-12-06 03:17:47
问题 I dont know what doesnt work on the following code, but it wont synthesize: reg [7:0] FIFO [0:8]; always@(posedge clk) begin if(wr & !rd & !full) begin FIFO[0:8] <= {data_in, FIFO[1:8]}; end end I tried to index the FIFO other ways too, but nothing works. Found this topic on a Xilinx forum but I just cant figue out what he wanted to tell with that. Here is the link: http://forums.xilinx.com/t5/General-Technical-Discussion/2-dimensional-array-problem-in-Verilog/td-p/42368 thanks 回答1: You have

Php and MySQL GROUP_CONCAT with separator comma and search where concat by comma

前提是你 提交于 2019-12-06 03:09:04
Is it that possible to select in Group_concat with separator comma and search where concat by comma Here My sample of mysql : products_attributes_id |products_id| options_id| options_values_id 39 | 31 | 3 | 3 35 | 30 | 2 | 2 38 | 30 | 1 | 1 40 | 31 | 2 | 2 41 | 30 | 1 | 4 42 | 30 | 1 | 5 43 | 31 | 1 | 4 I want to GROUP_CONCAT options_values_id SELECT * , GROUP_CONCAT(options_values_id SEPARATOR ',') FROM products_attributes GROUP by products_id products_attributes_id | products_id | options_id | options_values_id | options_values_id 35 | 30 | 2 | 2 | 2,1,4,5 39 | 31 | 3 | 3 | 3,2,4 Now my

JavaScript : unable to merge two arrays

你说的曾经没有我的故事 提交于 2019-12-06 02:19:10
I'm not a veteran of JavaScript and I have a little problem : In an AngularJS controller, I get 2 arrays from a WebService of the form [{"id":"1", "name":"aname1"}, {"id":"2", "name":"aname2"}] . They have both the same structure (this shouldn't be important). With concat() or push() I'm unable to merge these arrays together, and I don't understand why. I tried var arrayS = Service.list(); // Get data from WebService var arrayAE = ActeurExterne.list(); // Idem var arrayRes = arrayS.concat(arrayAE); $scope.acteurs = arrayRes; In my AngularJS app, the array acteurs is empty (if I displays it

mysql - group, but show all row of a column

人盡茶涼 提交于 2019-12-06 01:48:40
问题 I want to group fields but want to show all row of a column called remain : here is current output without grouping: And output with group: And I want This when I group: Here is mysql query: SELECT staff.name, staff.designation_id_designation, staff.status_id_status, Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) AS remain FROM staff INNER JOIN leave_remain ON staff.id_staff = leave_remain.staff_id_staff GROUP BY staff.name 回答1: use GROUP_CONCAT SELECT staff.name,

Why does pd.concat change the resulting datatype from int to float?

柔情痞子 提交于 2019-12-05 17:27:54
I have three dataframes: timestamp (with timestamps), dataSun (with timestamps of sunrise and sunset), dataData (with different climate data). Dataframe timestamp has datatype "int64" . timestamp.head() timestamp 0 1521681600000 1 1521681900000 2 1521682200000 3 1521682500000 4 1521682800000 Dataframe dataSun has also datatype "int64" . dataSun.head() sunrise sunset 0 1521696105000 1521740761000 1 1521696105000 1521740761000 2 1521696105000 1521740761000 3 1521696105000 1521740761000 4 1521696105000 1521740761000 Dataframe with climate data dataData has datatype "float64" . dataData.head()

Rails' concat method and blocks with do…end doesn't work

霸气de小男生 提交于 2019-12-05 08:58:21
I just read about Rails' concat method to clean up helpers that output something here http://thepugautomatic.com/2013/06/helpers/ . I played around with it, and I have found out, that it doesn't react the same way to blocks with curly braces and to blocks with do...end. def output_something concat content_tag :strong { "hello" } # works concat content_tag :strong do "hello" end # doesn't work concat(content_tag :strong do "hello" end) # works, but doesn't make much sense to use with multi line blocks end I didn't know that curly braces and do...end blocks seem to have different meanings. Is

Update mysql field using CONCAT and SELECT

依然范特西╮ 提交于 2019-12-05 06:34:44
问题 EDIT After removing my silly mistake of INTO (I was working with INSERTS and just keep going) the error below is showing. Still not working: Affected rows: 0 [Err] 1093 - You can't specify target table 'tbl' for update in FROM clause I'm trying to create an update where I select all the previous data in the column, add a complementary string and save it as new data. The code is below (with the error) Using only the select, the result: set @id = 3; SELECT tbl_alias.string_id FROM tbl as tbl

SQL Concatenate multiple rows

北战南征 提交于 2019-12-05 06:30:27
I'm using Teradata, I have a table like this ID String 123 Jim 123 John 123 Jane 321 Jill 321 Janine 321 Johan I want to query the table so I get ID String 123 Jim, John, Jane 321 Jill, Janine, Johan I tried partition but there can be many names. How do I get this result. Even, to point me in the right direction would be great. Unfortunately there's no PIVOT in Teradata (only a TD_UNPIVOT in 14.10). If you got luck there's an aggregate UDF at your site to do a group concat (probably low possibility). Otherwise there are two options: recursion or aggregation. If the maximum number of rows per

More than 2 columns in a CONCAT function

时间秒杀一切 提交于 2019-12-05 03:30:15
In SQL Server 2012 I want to concat 5 columns into 1 but in the query it works but when I put in in a view it gives me an error like Msg 174, Level 15, State 1, Line 3 The CONCAT function requires 2 argument(s). What's the problem so I can fix it because concat is a good function for concatenate more than 1 column because if its null they make it empty.. CODE: SELECT 'Aan ' + A.Name AS 'Naam', { fn CONCAT('T.a.v. ', C.Salutation + ' ', C.FirstName + ' ', C.MiddleName + ' ', C.LastName) } AS 'T.a.v.', ISNULL(ISNULL(A.Address1_Line2, A.Address1_Line1), C.Address1_Line2) AS 'Adres', ISNULL(A