compression

问题 I am using Axios to get the JSON response from the web server. The response is in compressed gzip format. How can I decompress the response and get the Json Data. 回答1: const zlib = require('zlib') let url = "https://example.com/GZ_FILE.gz" const { data } = await axios.get(url, { responseType: 'arraybuffer' }) zlib.gunzip(data, function (_err, output) { console.log(output.toString()) }) 来源： https://stackoverflow.com/questions/62882796/how-to-decompress-gzip-json-response-via-axios

问题 I am using Axios to get the JSON response from the web server. The response is in compressed gzip format. How can I decompress the response and get the Json Data. 回答1: const zlib = require('zlib') let url = "https://example.com/GZ_FILE.gz" const { data } = await axios.get(url, { responseType: 'arraybuffer' }) zlib.gunzip(data, function (_err, output) { console.log(output.toString()) }) 来源： https://stackoverflow.com/questions/62882796/how-to-decompress-gzip-json-response-via-axios

问题 Assume that the gzip file and zip archive both use DEFLATE. Since both would store the same raw compressed data for the specific file, is it possible to add a pre-compressed .gz file to an existing .zip archive? Some metadata would likely be lost (or not available), but I am more concerned with the raw file data. 回答1: Yes. I don't remember why I wrote this, but I'm sure there was a very good reason. Make sure you read the caveats in the comments. /* gz2zip.c version 1.0, 31 July 2018

问题 Assume that the gzip file and zip archive both use DEFLATE. Since both would store the same raw compressed data for the specific file, is it possible to add a pre-compressed .gz file to an existing .zip archive? Some metadata would likely be lost (or not available), but I am more concerned with the raw file data. 回答1: Yes. I don't remember why I wrote this, but I'm sure there was a very good reason. Make sure you read the caveats in the comments. /* gz2zip.c version 1.0, 31 July 2018

问题 Assume that the gzip file and zip archive both use DEFLATE. Since both would store the same raw compressed data for the specific file, is it possible to add a pre-compressed .gz file to an existing .zip archive? Some metadata would likely be lost (or not available), but I am more concerned with the raw file data. 回答1: Yes. I don't remember why I wrote this, but I'm sure there was a very good reason. Make sure you read the caveats in the comments. /* gz2zip.c version 1.0, 31 July 2018

问题 I'm an intern doing research into whether using Brotli compression in a piece of software provides a performance boost over the current release, which uses GZip. My task is to change anything using GZip to use Brotli compression instead. One function I need to replace does a check to test if a buffer contains data that was compressed using GZip. It does this by checking the stream identifier at the beginning and end: bool isGzipped() const { // Gzip file signature (0x1f8b) return (_bufferEnd

问题 I'm an intern doing research into whether using Brotli compression in a piece of software provides a performance boost over the current release, which uses GZip. My task is to change anything using GZip to use Brotli compression instead. One function I need to replace does a check to test if a buffer contains data that was compressed using GZip. It does this by checking the stream identifier at the beginning and end: bool isGzipped() const { // Gzip file signature (0x1f8b) return (_bufferEnd

问题 I have the following code in PHP: $text = gzcompress($text); // send $text to a python server Then in python I have the following code: text = request.POST.get('text', '') new_text = zlib.decompress(text) But this fails because the decompress function needs bytes and I am passing it a string. Does anyone know how to decompress a string in python that was compressed in php? PS: I am not particularly interested in a specific algorithm or function. 来源： https://stackoverflow.com/questions

问题 I don't understand in 2.X it worked : import zlib zlib.compress('Hello, world') now i have a : zlib.compress("Hello world!") TypeError: must be bytes or buffer, not str How can i compress my string ? Regards Bussiere 回答1: This is meant to enforce that you actually have a defined encoding. zlib.compress("Hello, world".encode("utf-8")) b'x\x9c\xf3H\xcd\xc9\xc9\xd7Q(\xcf/\xcaI\x01\x00\x1b\xd4\x04i' zlib.compress("Hello, world".encode("ascii")) b'x\x9c\xf3H\xcd\xc9\xc9\xd7Q(\xcf/\xcaI\x01\x00\x1b

问题 Ruby Zlib::GzipReader should be created passing an IO-like object (must have a read method that behaves same as the IO#read ). My problem is that I can't get this IO-like object from AWS::S3 lib. As far as I know, the only way of having a stream from it is passing a block to S3Object#stream . I already tried: Zlib::GzipReader.new(AWS::S3::S3Object.stream('file', 'bucket')) # Wich gaves me error: undefined method `read' for #<AWS::S3::S3Object::Value:0x000000017cbe78> Does anybody know how can