comparison

问题 Why does 4 < '3' return True in Python 2? Is it because when I place single quotes around a number Python sees it as a string and strings are bigger than numbers? 回答1: Yes, any number will be less than any string (including the empty string) in Python 2. In Python 3, you can't make arbitrary comparisons. You'll get a TypeError. From the link in eryksun's comment: if (PyNumber_Check(v)) vname = ""; else vname = v->ob_type->tp_name; if (PyNumber_Check(w)) wname = ""; else wname = w->ob_type->tp

问题 I want to know the most efficient way of comparing two entities of the same type. One entity is created from an xml file by hand ( ie new instance and manually set properties) and the other is retvied from my object context. I want to know if the property values are the same in each instance. My first thoughts are to generate a hash of the property values from each object and compare the hashes, but there might be another way, or a built in way? Any suggestions would be welcome. Many thanks,

问题 I want to know the most efficient way of comparing two entities of the same type. One entity is created from an xml file by hand ( ie new instance and manually set properties) and the other is retvied from my object context. I want to know if the property values are the same in each instance. My first thoughts are to generate a hash of the property values from each object and compare the hashes, but there might be another way, or a built in way? Any suggestions would be welcome. Many thanks,

问题 I want to know the most efficient way of comparing two entities of the same type. One entity is created from an xml file by hand ( ie new instance and manually set properties) and the other is retvied from my object context. I want to know if the property values are the same in each instance. My first thoughts are to generate a hash of the property values from each object and compare the hashes, but there might be another way, or a built in way? Any suggestions would be welcome. Many thanks,

问题 I noticed I can use the == operator to compare all the native data types (integers, strings, booleans, floating point numbers etc) and also lists, tuples, sets and dictionaries which contain native data types. In these cases the == operator checks if two objects are equal. But in some other cases (trying to compare instances of classes I created) the == operator just checks if the two variables reference the same object (so in these cases the == operator is equivalent to the is operator) My

问题 What's the easiest way to compute the amount of working days since a date? VB.NET preferred, but C# is okay. And by "working days", I mean all days excluding Saturday and Sunday. If the algorithm can also take into account a list of specific 'exclusion' dates that shouldn't count as working days, that would be gravy. Thanks in advance for the contributed genius. 回答1: This'll do what you want it to. It should be easy enough to convert to VB.NET, it's been too long for me to be able to do it

问题 An attempt to compare two objects of AnyObject type using '==' operator defined in Equatable protocol result in a compile error in Swift. Did anyone find a way to compare such objects, without knowing the real type of objects that can be used for downcasting? The background for this question is that I have a dictionary Dictionary<String, AnyObject> where values are supposed to be provided though a subscript, then at some point I need to compare the values in the dictionary to make sure that

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . So since Steve Jobs said Flash sucks and implied that HTML5 can do everything Flash can without the need for a Plugin, I keep hearing those exact words from a lot of People. I would really like to have a Chart somewhere (similar to http://en.wikipedia.org/wiki/Comparison_of_layout_engines_%28HTML5%29#Form

问题 I want to check a char variable is one of 21 specific chars, what is the shortest way I can do this? For example: if(symbol == ('A'|'B'|'C')){} Doesn't seem to be working. Do I need to write it like: if(symbol == 'A' || symbol == 'B' etc.) 回答1: If your input is a character and the characters you are checking against are mostly consecutive you could try this: if ((symbol >= 'A' && symbol <= 'Z') || symbol == '?') { // ... } However if your input is a string a more compact approach (but slower)

问题 I want to check a char variable is one of 21 specific chars, what is the shortest way I can do this? For example: if(symbol == ('A'|'B'|'C')){} Doesn't seem to be working. Do I need to write it like: if(symbol == 'A' || symbol == 'B' etc.) 回答1: If your input is a character and the characters you are checking against are mostly consecutive you could try this: if ((symbol >= 'A' && symbol <= 'Z') || symbol == '?') { // ... } However if your input is a string a more compact approach (but slower)