comparison

问题 I have functions which allow the user to compare two teams contained within a map. The data contained in the map is read in from a text file which contains information about football teams and their points tallies for the past 5 seasons. The data is stored as Map[String, List[Int]]: Manchester United, 72, 86, 83, 90, 94 Manchester City, 80, 84, 91, 77, 88 Chelsea, 76, 85, 92, 87, 84 Arsenal, 70, 79, 81, 76, 83 Liverpool, 69, 77, 80, 73, 79 The functions below allow the user to enter the names

问题 I've got two objects of different classes that share some fields with the same name and type. These two objects are not related to each other. There's no possibility for me to create an interface or a parent class. Now I want to compare those shared fields and as far as I know this should be possible using reflection. These are the steps I've written for such a compare method: Field[] inputFields = input.getClass().getDeclaredFields(); for (Field field : inputFields ) { log.info(field.getName

问题 I'm using python 2.7.2 with built-in IDLE on windows 7 x64, and found a very strange thing: >>> a = "aaa" >>> b = "aaa" >>> print a is b True >>> print a == b True >>> print "%s , %s" % (id(a), id(b)) 43872224 , 43872224 >>> This is normal, but, if the string contains a space: >>> x = "x x" >>> y = "x x" >>> print x is y False >>> print x == y True >>> print "%s , %s" % (id(x), id(y)) 43872008 , 43872128 >>> Notice x is y is False ! And they have different ids! I tried these code in PyCharm,

问题 This question is the culmination of two pieces of code guided by two answers here on SO. The first question I had was how to compare similarity between two strings and I got a good answer as seen here with the following code: code 1 def get_bigrams(string): ''' Takes a string and returns a list of bigrams ''' s = string.lower() return { s[i:i+2] for i in range(len(s) - 1) } def string_similarity(str1, str2): ''' Perform bigram comparison between two strings and return a percentage match in

问题 I'm trying to find matches within two tables. first I'll compare the phone number then the last name etc. I'll insert the matches in a new table. My question is first if it'll be faster and better if I do it directly in SQLServer or in my .net program? If SQL is better I need some help; I want to check if that record exist in the match table, if it does it should only modify this record t specify that there's an other match. I could do a separate insert and modify query for each type of match

问题 I have a Discriminated Union, and I hope to use built in operators like > < compare max for it. [<CustomComparison>] type SymbolType = | A | B | C | D interface IComparable<SymbolType> with member x.CompareTo y = match x, y with | A, A-> 0 | A, _ -> 1 | _, A-> -1 | _, _ -> 0 I understand I can use IComparable , but then i have to do a null check, what's worse is that I have to cast it like (SymbolType) y which I assume would be time consuming. 回答1: You can just implement the required methods

问题 If there are two array variable which contains exact same digits(no duplicate) but shuffled in position. Input arrays arr1={1,4,6,7,8}; arr2={1,7,7,6,8}; Result array arr2={true,false,false,false,true}; Is there a function in php to get result as above or should it be done using loop(which I can do) only. 回答1: This is a nice application for array_map() and an anonymous callback (OK, I must admit that I like those closures ;-) $a1 = array(1,4,6,7,8); $a2 = array(1,7,7,6,8); $r = array_map

问题 Is there a way that compares histograms but for example white color to be excluded and so white color doesn't affect onto the comparison. 回答1: White pixels have Saturation , S = 0 . So, it is very easy to remove the white pixels from being counted while creating histogram. Do the following: Convert your image from BGR to HSV Then split your HSV image into three individual channels i.e. H , S and V Then, access each pixel of channel S and if the pixel value = 0 (means S = 0) then it mean that

问题 Perhaps an odd question.. I'm currently struggling to understand why the following equates to true i.e. "Hello World" is printed to the console? I've always thought that string comparison in C had to be done using strcmp or similar. char *a = "Hello"; char *b = "Hello"; if(a == b) { printf("Hello World\n"); } I also thought that this would only equate to true if the addresses were equivalent? Is it the fact that they're literals? PS. Yes, this is scarcely related to an assignment, but I've

问题 What I am trying to do is equivalent to a "music charts" table. I have a table of video plays, and i want to rank the videos that have been played in the last 24 hours, and compare them to the rank they were the 24 hours before that. So the output should be the VideoID, The current Rank of the ID, and the rank the day previous of the ID The table consists of: PlayID (the specific id to the play table) IP (IP address of the user who played the video) VIDEOID (ID of the specific video, what