comparison-operators

Comparing different strings in PHP with == returns true

寵の児 提交于 2019-12-04 14:15:14
I was just debugging a script and found that an if-statement wasn't working the way I expected it to. var_dump("6064365413078728979" == "6064365413078728452"); die(); The code above will result in the following: bool(true) With the === operator it works as expected. Anyone got any ideas why? I'm using PHP Version 5.3.13 with a wamp installation on a x64 windows machine. Hanky Panky <?php $a=6064365413078728979; $b=6064365413078728452; echo $a."<br>".$b; //var_dump( $a==$b ); die(); ?> When you run that, then on your machine that might be exceeding limit for a number and that is a numeric

Chaining of Relational operators is giving wrong output [closed]

被刻印的时光 ゝ 提交于 2019-12-04 07:37:19
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . Can anyone explain this to me? Did I do something wrong? When I run the program it doesn't show me the right answer. ex : when I type weight = 50 kg and height = 130 cm the answer should be "Your BMI is 29.58. You are overweight2.You will have a chance to cause high blood pressure and diabetes need to control

comparing, !== versus !=

我们两清 提交于 2019-12-04 03:24:21
问题 I know that !== is used to compare variable types too, while != only compares values. But I see that many people use !== when they compare values, for example: $stuff = 'foo'; if($stuff !== 'foo') // do... Is there any reason they do this? Is !== faster than != or what? 回答1: If you do know in advance that both variables are of the same type, then it won't make any difference. I think the speed difference is just so negligible that the speed argument can (and should) be completely ignored, and

What does “compares less than 0” mean?

本小妞迷上赌 提交于 2019-12-03 14:45:56
Context While I was reading Consistent comparison , I have noticed a peculiar usage of the verb to compare : There’s a new three-way comparison operator, <=> . The expression a <=> b returns an object that compares <0 if a < b , compares >0 if a > b , and compares ==0 if a and b are equal/equivalent. Another example found on the internet (emphasis mine): It returns a value that compares less than zero on failure. Otherwise, the returned value can be used as the first argument on a later call to get. One last example , found in a on GitHub (emphasis mine): // Perform a circular 16 bit compare.

How does Ruby's sort method work with the combined comparison (spaceship) operator?

◇◆丶佛笑我妖孽 提交于 2019-12-03 14:31:26
Beginning programmer here, just wanting to understand the process behind Ruby's sort method when using the spaceship operator <=> . Hope someone can help. In the following: array = [1, 2, 3] array.sort { |a, b| a <=> b } ... I understand that sort is comparing a pair of numbers at a time and then returning -1 if a belongs before b , 0 if they're equal, or 1 if a should follow b . But in the case of sorting in descending order, like so: array.sort { |a, b| b <=> a } ... what exactly is happening? Does sort still compare a <=> b and then flip the result? Or is it interpreting the return s of -1

Does C++ have comparison operator that specify a range of values? (like 'in' in E language)?

假如想象 提交于 2019-12-03 06:42:22
问题 I need to write a condition that checks if an enum variable in range of values, like it can be done in E language: enum EnumVariable {a, b, d, g, f, t, k, i}; if (EnumVariable in [ a, g, t, i]) { ... } Is there a better way in C++ than ask 4 times if EnumVariable==a or EnumVariable==b etc.? 回答1: It appeared, that several people liked my comment and asked to post it as an answer, so: You can actually use switch for integral types without break -s between some values. For example, your code

Combined Comparison / “Spaceship” Operator (<=>) in Javascript?

心已入冬 提交于 2019-12-03 05:09:55
Ruby has something called a Combined Comparison or "Spaceship" Operator, it looks like this: <=> It does the following: a <=> b := if a < b then return -1 if a = b then return 0 if a > b then return 1 Credit Is there a similar Operator in Javascript? If not, how can I end up with the same result? @madox2 suggested using Math.sign(a - b) , which works for number, but not arrays (to compare arrays you need to use array.length ). It also does not work in Internet Explorer, Safari or all Mobile Browsers (see MDN ) @duques_l found a function here . It works very well, you can test it on JSFiddle

Difference between “!==” and “==!” [closed]

风格不统一 提交于 2019-12-03 02:07:57
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . Yesterday I stumbled over this when I modified PHP code written by someone else. I was baffled that a simple comparison ( if ($var ==! " ") ) didn't work

Double comparison

喜欢而已 提交于 2019-12-02 20:04:41
问题 Can I do this in C++? if (4<5<6) cout<<"valid"<<endl; i.e a double comparison? Since I know that I can bool a; a = 1+2<3+4<5>6;//etc 回答1: Yes, you can do it, but it won't be what you expect. It's parsed as if ( (4<5) < 6 ) which yields if ( 1 < 6 ) because 4<5 evaluates to true which is promoted to 1 , which yields, obviously, true. You'll need if ( (4<5) && (5<6) ) Also, yes, you can do a = 1+2<3+4<5>6; but that as well is parsed as a = ((1+2)<((3+4)<5))>6; which will evaluate to false since

assignment operator String object

时光总嘲笑我的痴心妄想 提交于 2019-12-02 19:17:22
问题 I am new to JAVA programming. I have read it in my book String a="Hello"; String b="Hello"; System.out.println(a==b); This should return false as a & b refer to different instances of String objects. Bcoz the assignments operator compares the instances of objects but Still I am getting a true . I am using Eclipse IDE. Example in book goes as this: String s = "s"; String sToo = "s"; System.out.println(a == b); System.out.println(s == sToo); That bit of code prints “false” for s == sToo. That's