compare

I have a situation where I have one VERY large file that I'm using the linux "split" command to break into smaller parts. Later I use the linux "cat" command to bring the parts all back together again. In the interim, however, I'm curious... If I get an MD5 fingerprint on the large file before splitting it, then later get the MD5 fingerprints on all the independent file parts that result from the split command, is there a way to take the independent fingerprints and somehow deduce that the sum or average (or whatever you like to all it) of their parts is equal to the fingerprint of the single

I have a generic function that I want to know how to write. List<Something> something; public int countItems<T>(List<T> Items) { // Here I would like to compare the type of "Items" with the type of "something" to see if they are compatible. How do I do it? return 0; } do you mean: if(typeof(T) == typeof(Something)) {...} ? Note that having generics depend hugely on the T (and act differently) may mean what you are trying to do isn't actually very generic ... if (something.GetType() == items.GetType()) ... This will compare the types of the actual objects. The question is poorly stated and more

I am looking for the best way to compare 2 text files (+-15000lines) quickly and get as output strings that are differents in the two files. 1st one is an old inventory, new one is the current inventory and I would like to generate an third one containing strings that are different between file2 & file1. (95% of the 2 files will be similar). Very simple approach, assuming that similar means equal : var file1Lines = File.ReadLines(file1Path); var file2Lines = File.ReadLines(file2Path); IEnumerable<String> inFirstNotInSecond = file1Lines.Except(file2Lines); IEnumerable<String> inSecondNotInFirst

I need to compare 2 strings, looking at the first letter only. Is there a method to compare A to Á, and recognize it as A, without the ´ ? NSString has a diacritic-insensitive comparison mode which will do what you're after. // should return NSOrderedSame, i.e. identical [@"Apple" compare:@"Ápple" options:NSDiacriticInsensitiveSearch] If you want it to be case-insensitive as well: // ditto [@"APPLE" compare:@"Ápple" options:NSDiacriticInsensitiveSearch | NSCaseInsensitiveSearch] 来源： https://stackoverflow.com/questions/4418997/how-to-compare-a-to-%c3%81-on-the-iphone

为什么要使用lambda表达式 从函数式接口说起 理解Functional Interface（函数式接口）是学习Java8 lambda表达式的关键所在。 函数式接口的定义其实很简单：任何接口，如果只包含唯一一个抽象方法，那么它就是一个函数式接口。对于函数式接口，我们可以通过lambda表达式来创建该接口的对象。 为了让编译器帮助我们确保一个接口满足函数式接口的要求，也就是说有且仅有一个抽象方法。Java8提供了@FunctionalInterface注解。举个简单的例子，Runnable接口就是一个FI，下面是它的源代码： @FunctionalInterface public interface Runnable { public abstract void run(); } 使用@FunctionalInterface注解并不强制要求。但是使用注解会让代码看上去更清楚。 lambda表达式的语法糖 语法糖 Java中lambda表达式的格式：参数、箭头->、一个表达式。 为了演示lambda表达式的语法糖，我们通过Comparator作为例子。在Java8之前，可以借助匿名内部类来实现。 public static List<String> compareTest1(){ List<String> wordList = Arrays.asList("lianggzone",

Right now, I have two char arrays, foo1[] and foo2[] . When I convert them to string and output to the console, they BOTH appear as bar . I know that I can do something like this: int g; for (int i=0;i<length.foo1;i++) { // loop from 0 to length of array if (foo1[i]=foo2[i]) { // if foo1[0] and foo2[0] are the same char g++; // increment a counter by 1 } else // otherwise... { i=100; // set i to something that will halt the loop } if (g = length.foo1) { // if the incremented counter = length of array return true; // arrays are equal, since g only increments } // in the case of a match, g can