compare

I want to compare two lists and get the valid words into a new list. var words = new List<string>(); var badWords = new List<string>(); //this is just an example list. actual list does contain 700 records words.Add("Apple"); words.Add("Moron"); words.Add("Seafood"); words.Add("Cars"); words.Add("Chicken"); words.Add("Twat"); words.Add("Watch"); words.Add("Android"); words.Add("c-sharp"); words.Add("Fool"); badWords.Add("Idiot"); badWords.Add("Retarded"); badWords.Add("Twat"); badWords.Add("Fool"); badWords.Add("Moron"); I am looking for most efficient way to compare the lists and put all the

i'm developing a PHP program and i must compare a date variable and a string variable . I've tried strcmp but it doesn't work... suggests? Thank's Best way of comparing dates is using time-stamps : $string = '11/05/2016';//string variable $date = date('Y-m-d',time());//date variable $time1 = strtotime($string); $time2 = strtotime($date); if($time1>$time2){ //do this } else{ //do this } I hope it helps Ronak $time = strtotime('10/16/2003'); $newformat = date('Y-m-d',$time); //my date format is Y-m-d,usw your date format there $newformat variable also a date this way you can compare date and

What I want to do is more or less a combination of the problems discussed in the two following threads: Perform non-pairwise all-to-all comparisons between two unordered character vectors --- The opposite of intersect --- all-to-all setdiff Merge data frames based on numeric rownames within a chosen threshold and keeping unmatched rows as well I have two numeric vectors: b_1 <- c(543.4591, 489.36325, 12.03, 896.158, 1002.5698, 301.569) b_2 <- c(22.12, 53, 12.02, 543.4891, 5666.31, 100.1, 896.131, 489.37) I want to compare all elements in b_1 against all elements in b_2 and vice versa. If

What is the fastest and best way to compare 2 lists and return a match. Only one match is possible. List1 contains dynamic data from a database. The way I do it now : foreach (var item1 in List1) { foreach (var item2 in List2 ) { if(item2 == item1) string match = item1; } } I have a feeling like it can be done a lot faster. Use Enumerable.Intersect . var matchItem = List1.Intersect(List2).First(); Not really sure how much it is faster to your current code, you can measure it using Stopwatch. But in your current code you should break your inner as well as outer loop on finding the match.

Can I check in C(++) if an array is all 0 (or false) without iterating/looping over every single value and without allocating a new array of the same size (to use memcmp )? I'm abusing an array of bools to have arbitrary large bitsets at runtime and do some bitflipping on it You can use the following condition: (myvector.end() == std::find(myvector.begin(), myvector.end(), true)) Obviously, internally, this loops over all values. The alternative (which really should avoid looping) is to override all write-access functions, and keep track of whether true has ever been written to your vector.

lambda 功能语法介绍 Java8 引入了一个新的操作符 “->” ,该操作符称为 箭头操作符,lambda 操作符 , 该箭头将表达试分为俩部分,分别是操作符左边,和操作符右边, 左边:方法参数() 右边:所需执行的功能,一般我们称为操作体 需要注意的是,lambda 只支持一个抽象方法的接口,列如 Runnable 接口 从今以后,这部分接口我们可以不用在使用接口的匿名内布类了,可以使用Lambda 来代替, 下面演示一个案例,让我们更直观的感受Lambda给我们带来的好处 @Test public void Test_Lambda (){ /** * 创建一个线程,以前的写法 */ Runnable r1 = new Runnable() { @Override public void run () { System.out.println( "这是匿名内不类的写法" ); } }; // 调用方法r1 r1.run(); /** * * 这是lambda 表达式的写法 */ Runnable r2 = () -> System.out.println( "这是lambda 表达式的写法" ); //调用r2 r2.run(); } 方法执行输出结果如下 我们发现,虽然功能一摸一样,但是lambda 的代码简洁了很多,我们来分析刚刚的Lambda 表达式 //

I don't know about you guys but at least I expected that f1 would be equal to f2 in the below code but apparently that's not the case! What's your thoughts about this? It seems like I have to write my own equals method to support it, right? import java.io.*; public class FileEquals { public static void main(String[] args) { File f1 = new File("./hello.txt"); File f2 = new File("hello.txt"); System.out.println("f1: " + f1.getName()); System.out.println("f2: " + f2.getName()); System.out.println("f1.equals(f2) returns " + f1.equals(f2)); System.out.println("f1.compareTo(f2) returns " + f1

因为工作需要，经常会用到BeyondCompare4这个软件，但是从官方下载的BeyondCompare4只有一个月的试用期，点击输入密钥又一直打开购买软件的页面，所以就一开始就用了最笨的方法，软件的试用期一到就卸载，然后重装一次软件。 方法一：后来在网上查了一下，发现我们可以通过修改 C:\Users\Administrator\AppData\Roaming\BCompare\BCompare.ini这个配置文件中的时间戳来使软件一直处于试用期。 BCompare.ini文件的内容大致如下： [BCompare] InstallTime=1534816784 LastLoading=1538200843 如果软件试用期过了的话，可以通过修改InstallTime和LastLoading这两个参数来使软件处于使用期，比起卸载软件然后重装要方便得多。如果想一次性解决这个问题的话，也可以选择写一个脚本文件，然后选择开机启动，每次开机前将InstallTime改为当前的时间，这样便可以一劳永逸了。 脚本文件的内容如下： import time f = open("C:\\Users\\Administrator\\AppData\\Roaming\\BCompare\\BCompare.ini","r+") f_content = f.readlines() f.seek(0,0) f