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I have a system that accepts user submissions, and upon receiving a submission the system will go through all timeslots to find the appropriate timeslot. The problem is that it needs to be able to check against the start & end times if the end time laps to the next day. Take the following example: A timeslot begins at 10:30 PM on the current day and ends at 4:00 PM the next day. If the current time is between 10:30 PM and 11:59:59 PM, the submission will be assigned to that timeslot. However, if the current time is between 12:00 AM and 4:00 PM then it will skip the timeslot. This is what I

What is the correct way to compare, or test, for a particular color attribute of an NSAttributed string? As an example, I'd like to know if the text selection has red text. I have tried several approaches, as you can see below, but none of them ever results in a match. I see the text turn red on screen, and logging the attribute returns: UIDeviceRGBColorSpace 1 0 0 1 - (BOOL)isRedWithAttributes:(NSDictionary *)attributes { BOOL isRedWithAttributes = NO; if (attributes != nil) { // if ( [attributes objectForKey:NSForegroundColorAttributeName] == [UIColor redColor] ) // if ( [attributes

Is there possibility of copy ONLY difference of two files? Like in winmerge, but, I can't find this option Just like on this screen- i want to copy only 'yellow part' . Of course I can do that manually, but in big file it's not too funny :-) WinMerge has a built-in and simple way to generate such "diff only" files, that they called "patches". Click on "Tool", then on "Generate Patch...", and enter where you want to store the result: You will obtain (for your example) the file 4,8c4,8 < HELLO WORLD < HELLO WORLD < HELLO WORLD < HELLO WORLD < HELLO WORLD --- > > > > > That uses the standard,

This question already has answers here : How do I determine whether an array contains a particular value in Java? (28 answers) Given : String[] directions = {"UP","DOWN","RIGHT","LEFT","up","down","right","left"}; String input = "Up"; How can I verify that an input from stdin is within the directions array or not ? I can make a loop and check each item with input using equal ,but I'm looking for a more elegant way. Regards,Ron Convert the array of valid directions to a list: List valid = Arrays.asList(directions) Or just declare it directly as: List valid = Arrays.asList("UP", "DOWN", "RIGHT",

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to compare two dates with time, I want all the results from tbl where date1 > date2 Select * From temp where mydate > '2009-06-29 04:00:44'; but it is just comparing dates not time. it is giving me all the result set of today's date '2009-06-29 11:08:57' '2009-06-29 11:14:35' '2009-06-29 11:12:38' '2009-06-29 11:37:48' '2009-06-29 11:52:17' '2009-06-29 12:12:50' '2009-06-29 12:13:38' '2009-06-29 12:19:24' '2009-06-29 12:27:25' '2009-06-29 12:28:49' '2009-06-29 12:35:54' '2009-06-29 12:36:54' '2009-06-29 12:49:57' '2009-06-29 12:58:04'

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have implemented an ANN character classifier in opencv C++. I have created a model: cv::Mat layers(3,1,CV_32S); layers.at<int>(0,0) = ATTRIBUTES;//400 layers.at<int>(1,0)=25;//hidden layer layers.at<int>(2,0) =CLASSES;// eg. 10 CvANN_MLP nnetwork(layers, CvANN_MLP::SIGMOID_SYM,0.6,1); CvANN_MLP_TrainParams params( cvTermCriteria(CV_TERMCRIT_ITER+CV_TERMCRIT_EPS, 1000, 0.000001), CvANN_MLP_TrainParams::BACKPROP, 0.1, 0.1); int iterations = nnetwork.train(training_set, training_set_classifications,cv::Mat(),cv::Mat(),params); CvFileStorage*

I want to check if two references point to the same object. It seems I can simply use if ($ref1 == $ref2) { # cheap numeric compare of references print "refs 1 and 2 refer to the same thing\n"; } as mentioned in perlref , but I vaguely remember seeing the use of some function for the same purpose. Is there any reason I shouldn't use the simple numerical equality test? Note I only want to know whether the references point to the exact same object. I don't look for a way to compare the content of the object(s). References, by default, numify to their addresses. Those reference addresses are