compare

问题 Hey, I have an excel document with columns A and B. Row A has 2595 values. Row B has 411 values. I'm trying to figure out how I can compare these two columns by marking column C with the number of times we find a value(s) from row a. For Example COLUMN A COLUMN B COLUMN C 1 1 1 (because we have one value of 1 from column A) 2 2 1 (because we have one value of 2 from column A) 3 3 2 (because we have 2 threes from column A) 3 4 4 5 5 6 2 (because there are two 6's in column A) 6 7 0 (because

问题 I want to compare two pictures similarity Code: Mat mat1=Highgui.imread("/mnt/sdcard/91.png"); Mat mat2=Highgui.imread("/mnt/sdcard/92.png"); double distance = Imgproc.compareHist(mat1, mat2, Imgproc.CV_COMP_CORREL); //(this line throws an exception) Exception information: 01-30 10:48:20.203: E/AndroidRuntime(3540): Caused by: CvException [org.opencv.core.CvException: /home/andreyk/OpenCV2/trunk/opencv/modules/imgproc/src/histogram.cpp:1387: error: (-215) H1.type() == H2.type() && H1.type() =

问题 I have multiple date ranges. I want to check if they are overlapping in javascript. When there are only two it is easy, I use: if(start_times1 <= end_times2 && end_times1 >= start_times2) {} But what is the formula when there are more than 2 date ranges? 回答1: You can use nested for loops with arguements function dateRangeOverlaps(a_start, a_end, b_start, b_end) { if (a_start <= b_start && b_start <= a_end) return true; // b starts in a if (a_start <= b_end && b_end <= a_end) return true; // b

问题 Suppose you have a list of acronym's that define a value (ex. AB1,DE2,CC3) and you need to check a string value (ex. "Happy:DE2|234") to see if an acronym is found in the string. For a short list of acronym's I would usually create a simple RegEx that used a separator (ex. (AB1|DE2|CC3) ) and just look for a match. But how would I tackle this if there are over 30 acronym's to match against? Would it make sense to use the same technique (ugly) or is there a more effecient and elegant way to

问题 I have two XML-files similar to this: 1. <data> <object ID="1"> <ID>1</ID> <name>abc</name> <weight>50</weight> </object> <object ID="2"> <ID>2</ID> <name>def</name> <weight>75</weight> </object> </data> 2. <data> <object ID="2"> <ID>2</ID> <name>def</name> <weight>75</weight> </object> <object ID="3"> <ID>3</ID> <name>ghi</name> <weight>100</weight> </object> </data> And now I want to compare them. Either with an additional element (something like both) or a new files (in_both_files.xml,

问题 I am currently working on comparing two complex objects of the same type, with multiple fields consisting of data structures of custom object types. Assuming that none of the custom objects has overriden the hashCode() method, if I compare the hashcodes of every field in the objects, and they will turn out to be the same, do I have a 100% confidence that the content of the compared objects is the same? If not, which method would you recommend to compare two objects, assuming I can't use any

问题 /** * A method to compare Strings * @param arg1 * @param arg2 * @return */ public boolean myQuickCompare(String arg1, String arg2) { boolean a = arg1.length() == arg2.length(); if (a) { for (int b = 0; b > arg1.length(); b++) { if (arg1.charAt(b) != arg2.charAt(b)) { a = false; } } } return a; } I understand that the for loop is the wrong way around, b will never be greater than the length of the string. How would you correct this problem? What sensible variable names would you give for a and

问题 How do I make this piece of code to order in descending order. This code always gives me the array in ascending order: NSArray *sortedProductsByStyle = [unsortedProducts sortedArrayUsingComparator: ^(Product *p1, Product *p2) { return [p1.productStyle compare:p2.productStyle options:NSNumericSearch]; }]; I thought that using NSOrderedDescending would work but it didn't: NSArray *sortedProductsByStyle = [unsortedProducts sortedArrayUsingComparator: ^(Product *p1, Product *p2) { return [p1

问题 My requirement is to compare two objects of the same unknown/generic type. The objects are complex. They can contain Lists which can themselves contain Lists. So, my initial thoughts are to use a Comparator for comparing objects, reflection for discovering all properties of the bean and some recursion to handle any nested lists the objects may contain. or, is there a utility that will do all of that for me, in java? 回答1: I'm currently working on a similar problem. I can confirm that using

问题 Java's PriorityQueue places the least element at the head of the list, however I need it to place the greatest element at the head. What what's the neatest way to get a priority queue that behaves like that. Since I wrote the class stored in this queue I could simply reverse the results of compareTo , its not used outside this queue. However I like to make the code an accurate representation of what I'm modeling, what I'm trying to do is get the greatest first so the code should say that