compare

compare two arrays Laravel

主宰稳场 提交于 2019-12-11 17:07:31
问题 I have articles that can contain different tags. For example, 5 pieces: (php, html, css, laravel, js) And I have groups that can also contain different tags. For example 4 pieces: (laravel, php, html, css) I have already defined the relationships and it works. What I still lack is the linkage of article to the group. In the Articlecontroller i use this so sync: $article->groups()->sync($group->id); Article Model public function groups() { return $this->belongsToMany('App\Group'); } public

Compare_DF in R truncating trailing zero

梦想与她 提交于 2019-12-11 16:58:37
问题 I have two dataframes: df1 score id 59.09 1 65.27 2 65.05 3 60.15 4 65.30 5 65.61 6 59.21 7 59.70 8 And the other dataframe df2 score id 59.10 1 65.27 2 65.05 3 60.15 4 65.30 5 65.62 6 59.21 7 59.70 8 Now when I use compare_df and output it dropped the trailing 0 in df2 score` 59.10. I need this trailing zero to be always displayed. I have a contraint to use compareDF only. 来源: https://stackoverflow.com/questions/54880218/compare-df-in-r-truncating-trailing-zero

Regex for number comparison?

泄露秘密 提交于 2019-12-11 16:32:22
问题 I would like to perform regex to return true/false if the input 5 digit from input matching data in database, no need to cater of the sequence, but need the exact numbers. Eg: In database I have 12345 When I key in a 5 digit value into search, I want to find out whether it is matching the each number inside the 12345. If I key in 34152- it should return true If I key in 14325- it should return true If I key in 65432- it should return false If I key in 11234- it should return false Eg: In

how to recursively compare 2 lists in python (unsorted, order-independent)

心已入冬 提交于 2019-12-11 15:42:27
问题 The last issue I have is being able to accurately compare two lists of the same size that have no elements in common. I cannot use any built in Python functions (i.e., sort, compare, Counter) except for list methods len, del, index. My code: def SameStuff(l1, l2): if len(l1) <= 1 or len(l2) <= 1 or len(l1) != len(l2): if len(l1) == 0 or len(l2) == 0: return len(l1) == len(l2) else: return len(l1) == len(l2) and l1[0] == l2[0] else: if l1[0] == l2[0]: return SameStuff(l1[1:], l2[1:]) else:

Comparing values in Array fails

旧街凉风 提交于 2019-12-11 15:36:02
问题 Sometimes comparing two strings within arrays fails. Failing occurs occasionally only in looped if s. Example code below stands for implementing the problem. searchTable.sort(); for(n=1;n<searchTable.length;n++){ // alert(searchTable[n-1]!=searchTable[n]); if(searchTable[n-1]!=searchTable[n]){ idx++; memTable[idx]=searchTable[n]; } } Values in the searchTable are strings for sure, and all values are not similar either. In loop, all values are set in memTable[idx], despite of the similar

好程序员大数据教程分享实用的大数据之数组

别等时光非礼了梦想. 提交于 2019-12-11 15:28:48
好程序员大数据教程分享实用的大数据之数组 1.5.1 数组的定义与元素访问 数组是一个容器, 是一个用来存储指定数据类型的容器 注意事项: 数组是一个定长的容器, 一旦实例化完成, 长度不能修改 名词解释: 数组长度: 指的就是这个容器的容量, 表示这个数组中能存储多少个数据 元素: 指的就是数组中存储的数据 下标: 某一个元素在数组中的一个位置索引 遍历数组: 依次获取到数组中的每一个元素 数组的元素访问 通过下标来访问的, 数组中元素的下标是从0开始的 数组中元素的下标: [0, 数组.length - 1] 注意: 在访问数组中元素的时候, 注意下标的范围, 不要越界!!! 遍历数组: 使用循环遍历下标的方式 int[] array = {1, 2, 3}; for (int index = 0; index < array.length; index++) { System.out.println(array[index]); } 使用增强for循环 int[] array = {1, 2, 3}; for (int ele : array) { System.out.println(ele); } 1.5.2 数组的内存分析 1.5.3 数组的常见操作 1.5.4 数组排序 选择排序 固定一个下标, 然后用这个下标对应的元素依次和后面每一个下标的元素进行比较 int[]

Why does Prolog does not backtrack on comparison?

让人想犯罪 __ 提交于 2019-12-11 14:47:30
问题 I would expect that the following should always be true if a comparison backtrack, right? unless it goes into an infinite loop! ?- Y=2 , random:random(1,3,X), X =\= Y. Y = 2, X = 1. ?- Y=2 , random:random(1,3,X), X =\= Y. false. but I got false! In general, my question is why doesn't comparison backtrack? Thanks for all the answers. My confusion seemed to come primarily from my expectation of random keep generating new-random numbers, so I confused that comparison was not backtracking,

Sql Server Compare Application

倖福魔咒の 提交于 2019-12-11 13:57:22
问题 I want to know is what is the best sql server comparison tool application on the market? I recently noticed an app which I loved and posted a question about BUT with a link to the website. Bad mistake, was naive. I do a lot of programming and database development at home and have been using Red Gate (licence supplied by work while I work at h0me) but as I am leaving in 2 weeks time, I am desperate for a replacement BUT cheap replacement. I apologise for recent posting where I typed in the url

Comparing string date with today's date

ぐ巨炮叔叔 提交于 2019-12-11 13:20:04
问题 So I have a string which is "2014-06-30 15:27" and if it is today's date it should only return "15:27" else "30/06/2014". I've already tried simpleDateFormat.parse but it didn't work very well. holder.data.setText(mensagem.getDate()); 回答1: final String stringDate = "2014-07-17 23:59"; SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm"); Date date = inputFormat.parse(stringDate); Calendar calendarDate = Calendar.getInstance(); calendarDate.setTime(date); Calendar midnight =

C++ comparing a char to a string literal [duplicate]

落爺英雄遲暮 提交于 2019-12-11 13:19:52
问题 This question already has answers here : c++ compile error: ISO C++ forbids comparison between pointer and integer (5 answers) Closed 2 years ago . Beginning programmer here... I'm writing a very simply program for my computer science class and I ran into an issue that I'd like to know more about. Here is my code: #include <iostream> using namespace std; int main(int argc, const char * argv[]) { char courseLevel; cout << "Will you be taking graduate or undergraduate level courses (enter 'U'"