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This question already has an answer here: Java 8 stream's .min() and .max(): why does this compile? 5 answers I'm studying for 1z0-809 : Java SE 8 Programmer II using Enthuware's mocktests. Encountering this question. List<Integer> ls = Arrays.asList(3,4,6,9,2,5,7); System.out.println(ls.stream().reduce(Integer.MIN_VALUE, (a, b)->a>b?a:b)); //1 System.out.println(ls.stream().max(Integer::max).get()); //2 System.out.println(ls.stream().max(Integer::compare).get()); //3 System.out.println(ls.stream().max((a, b)->a>b?a:b)); //4 Which of the above statements will print 9? Answer is 1 and 3 But

in a DB2 trigger, I need to compare the value of a CLOB field. Something like: IF OLD_ROW.CLOB_FIELD != UPDATED_ROW.CLOB_FIELD but "!=" does not work for comparing CLOBs. What is the way to compare it? Edited to add: My trigger needs to do some action if the Clob field was changed during an update. This is the reason I need to compare the 2 CLOBs in the trigger code. I'm looking for some detailed information on how this can be done In Oracle 10g you can use DBMS_LOB.compare() API. Example: select * from table t where dbms_lob.compare(t.clob1, t.clob2) != 0 Full API: DBMS_LOB.COMPARE ( lob_1 IN

I always assumed that .Net compares strings lexicographically, according to the current culture. But there is something strange when one of the strings ends on '-': "+".CompareTo("-") Returns: 1 "+1".CompareTo("-1") Returns: -1 I get it an all cultures I tried, including the invariant one. Can anyone explain what is going on, and how can I get the consistent character-by-character ordering for the current locale? LukeH There isn't necessarily a consistent character-by-character ordering for any particular locale. From the MSDN documentation : For example, a culture could specify that certain

I am using var win1 = open.window(...); var win2 = open.window(...); to open 2 tabs/windows in Firefox - now I want to compare the two DOMs (document object models) for similarity. So I have got two DOMs containing a very similar page. The pages have the same HTML but executed different JavaScript files. In general I check if HTML and CSS is the same: var html1 = win1.document.body.innerHTML; var html2 = win2.document.body.innerHTML; if (html1 == html2) { ... } var css1 = win1.document.body.style.cssText var css2 = win2.document.body.style.cssText if (css1 == css2) { ... } But comparing all

Possible Duplicate: Comparing the values of two generic Numbers I would like to compare two arbitrary instances of Number to find out which is greater. As you know, those may be Integers, Longs or Doubles but also BigIntegers or BigDecimals. So what to do? Number does not implement Comparable . Can't use doubleValue() as there might be a loss of precision from BigDecimals or BigIntegers. Do I really have to go into instance-testing and casting? There must be some library that does this. But I've already checked Apache Commons and Guava with no luck. Edit 1: Comments pointed this out: Comparing

Let's say I have the following two arrays: int[] a = [1,2,3,4,5]; int[] b = [8,1,3,9,4]; I would like to take the first value of array a - 1 - and see if it is contained in array b . So, I would get that the '1' from a is in b even if it is not in the same position. Once I have gone through the comparison for the first element in a , I move on to the next number in array a and continue the process until I have completely gone through the first array. I know I need to do some looping (possibly nested?) but I can't quite figure out how I stick with just the first number in array a while looping

I am writing a "Date" class for an assignment and I am having trouble doing one the of the functions. This is the header file for the class. class Date { public: Date(); // Constructor without parameters Date(int m, int d, int y); // Constructor with parameters. // accessors int GetMonth(); // returns the size of the diamond int GetDay(); int GetYear(); // mutators bool Set(int m, int d, int y); bool SetFormat(char f); // standard input and output routines void Input(); void Show(); void Increment(int numDays = 1); int Compare(const Date& d); private: int month, // month variables day, // day

For some reason I'm having some serious difficulty wrapping my mind around this problem. I need this JS function that accepts 2 arrays, compares the 2, and then returns a string of the missing element. E.g. Find the element that is missing in the currentArray that was there in the previous array. function findDeselectedItem(CurrentArray, PreviousArray){ var CurrentArrSize = CurrentArray.length; var PrevousArrSize = PreviousArray.length; // Then my brain gives up on me... // I assume you have to use for-loops, but how do you compare them?? return missingElement; } Thank in advance! I'm not

How to compare time in Objective C? if (nowTime > 9:00 PM) && (nowTime < 7:00 AM) { doSomething; } Itai Ferber If you want to get the current hour and compare it to some times, you're going to have to use NSDate , NSDateComponents , and NSCalendar . NSDateComponents *components = [[NSCalendar currentCalendar] components:NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:[NSDate date]]; NSInteger currentHour = [components hour]; NSInteger currentMinute = [components minute]; NSInteger currentSecond = [components second]; if (currentHour < 7 || (currentHour > 21 ||