compare

Many thanks for reading. Apologies for what I'm sure is a simple task. I have a dataframe: (Edited: Added extra column not to be included in comparison) b = c(5, 6, 7, 8, 10, 11) c = c('david','alan','pete', 'ben', 'richard', 'edd') d = c('alex','edd','ben','pete','raymond', 'alan') df = data.frame(b, c, d) df b c d 1 5 david alex 2 6 alan edd 3 7 pete ben 4 8 ben pete 5 10 richard raymond 6 11 edd alan I want to compare the group of columns c and d with the group of columns d and c . That is, for one row, I want to compare the combined values in c and d with the combined values in d and c for

notepad++的最新版本和compare插件的压缩包。安装完notepad++之后，解压插件文件，将解压得到的.dll文件剪切到notepad++安装路径的plugins中。再次打开软件---插件---compare.OK.所需软件地址及其插件的压缩文件地址如下链接。 https://pan.baidu.com/s/1CA1gB_lK8Rj5_reVxVzEXA 来源： 51CTO 作者： lillian_trip 链接： https://blog.51cto.com/xiaoqiaoya/2115177

Suppose you have two closures of type (Int)->() in Swift 3 and test to see if they are the same as each other: typealias Baz = (Int)->() let closure1:Baz = { print("foo \($0)") } let closure2:Baz = { print("bar \($0)") } if(closure1 == closure2) { print("equal") } This fails to compile, giving the message: Binary operator '==' cannot be applied to two '(Int)->()' operands OK, well, how then can we compare two closures of the same type, to see if they are the same? I'm pretty sure there is no way to determine if two closures are equal. Obviously, a logical equality check is out of the question.

Happens if at least one of the values (values == value in RowFilter, value in entry) is a decimal. Here's a failing test: @Test public void testRowFilterNumberMixCore() { TestEntry entry = new TestEntry(1.2f); RowFilter filter = RowFilter.numberFilter(ComparisonType.AFTER, 1, 0); assertTrue(entry + "must be included " + filter, filter.include(entry)); } The output is: junit.framework.AssertionFailedError: [entry: 1.2] must be included [RowFilter: ComparisonType = AFTER, comparableValue: 1, comparableClass: class java.lang.Integer] The reason is that NumberFilter falls back to comparing the

In my understanding, sys.float_info.max is the largest possible float value. However, it seems that comparing such large values fail . import math import sys m = sys.float_info.max # type 'float' m == m # True m < m # False m > m # False m == m-1.0 # True m < m-1.0 # False m > m-1.0 # False m == m-1e100 # True m < m-1e100 # False m > m-1e100 # False m == m-1e300 # False m > m-1e300 # True m < m-1e300 # False I assume that's because of the limited precision? If so, in what numerical range can i operate safely? The above code was run with Python 3.5.2. On a typical machine running Python, there

i have a lot of string which contains also number like : LOD140IXAL COMP 1X240GG I would like to put whitespace between numbers and word if there isn't. the number could be every where in the string. One way to do this is using regular expressions. Replacing the following monster with a single space should do the trick: "(?<=[A-Za-z])(?=[0-9])|(?<=[0-9])(?=[A-Za-z])" When applied to your example ( LOD140IXAL COMP 1X240GG ), it produces LODIXAL COMP 1 X 240 MG . In a nutshell, the regex looks for a letter immediately followed by a digit, or a digit immediately followed by a letter, and inserts

这里开始讲Dart语法中最重要的元素之一：方法，Dart里面的方法跟java还是有很大的不同 方法 Dart是一种真正的面向对象语言，因此即使是函数也是对象并且具有类型Function。 这意味着函数可以分配给变量或作为参数传递给其他函数。 您也可以像调用函数一样调用Dart类的实例。 bool isNoble(int atomicNumber) { return _nobleGases[atomicNumber] != null; } bool isNoble(int atomicNumber) => _nobleGases[atomicNumber] != null; 这是一个标准的方法，其中返回类型是可以省略的，Dart会自动推断，而它下面的那个方法则是一个方法的简写版 可选参数和必选参数 函数可以有两种类型的参数：必需和可选。首先列出所需参数，然后列出任何可选参数。命名的可选参数也可以标记为@required。当我们调用一个方法的时候，我们可以给方法填上一个默认值，例如： //这是一个可选参数的的方法 optionalFunction({int a = 1 ,int b =2}){ return a+b; } //在调用的时候我可以选择传一个参数，也可以选择不传 main(){ optionalFunction(a:4); optionalFunction(a:4,b:1)