codeigniter

问题 I'm trying to set session data for users when they log in to my website. So if the user exists in db, I set a session data like : $this->session->set_userdata('user_exists','1'); Now every time i want to check if user exists and is logged i do: if($this->session->userdata('user_exists')){ //do somenthing for logged user } Now I'm wondering if this means that user is logged and exists in the database since he logged and I set him a session param, is this true? Or I'll get security problems? NB

问题 I'm trying to set session data for users when they log in to my website. So if the user exists in db, I set a session data like : $this->session->set_userdata('user_exists','1'); Now every time i want to check if user exists and is logged i do: if($this->session->userdata('user_exists')){ //do somenthing for logged user } Now I'm wondering if this means that user is logged and exists in the database since he logged and I set him a session param, is this true? Or I'll get security problems? NB

问题 I'm trying to wrap my head around this, but I seem to go in circles. I'm trying to list a users topics one by one, with the quotes belonging to that specific topic underneath. If that makes sense. I have 3 tables, like so: [USERS] user_id username [TOPICS] topic_id user_id topic_name [QUOTES] quote_id topic_id quote_name I want to be able to do something like this in my view: Username: Thomas Topic 1: Whatever Quotes: One quote, another quote, and a third quote, all belonging to Topic 1.

问题 I'm trying to wrap my head around this, but I seem to go in circles. I'm trying to list a users topics one by one, with the quotes belonging to that specific topic underneath. If that makes sense. I have 3 tables, like so: [USERS] user_id username [TOPICS] topic_id user_id topic_name [QUOTES] quote_id topic_id quote_name I want to be able to do something like this in my view: Username: Thomas Topic 1: Whatever Quotes: One quote, another quote, and a third quote, all belonging to Topic 1.

问题 I'm using a search system, in PHP, that adds the text searched to an array and put it inside a cookie using json_encode(). The problem is: I need to check if the cookie already exists and, if not, create it. I'm using the following code to simply verify if it exists but without success: { $search = $this->input->post('search_text'); $types = $this->input->post('search_type'); $checkboxes = ""; if(!empty($types)) { foreach($types as $v) $checkboxes = $v.","; } //cookie $this->load->helper(

问题 I have a Table in MYSql called companies and each companies has a type say type 1, type 2 type 3, example : id company_name company_type =============================== 1 test1 3 2 xyz 2 3 ashdasdjk 2 4 test 4 1 5 test 3 6 ahsdkjsg 1 7 TCS 2 and so on ... now i want to write a query to fetch results such that i get 20 companies of type 1, 20 companies of type 2 and 20 companies of type 3... i mean i want to fetch maximum of 20 companies of each type I am using Codeigniter.. 回答1: select * from

问题 I'm new to CodeIgniter, I've tried to read the documentation of CI but I still can't solve my problem, maybe someone here can help fix my problem. Here is my code: In my controller class Registration extends CI_Controller{ function __construct(){ parent::__construct(); $this->load->model('registration_model','rmod'); } function ambil() { $gender = $this->input->post('kelamin'); $tinggi = $this->input->post('height'); $berat = $this->input->post('weight'); $weight = $this->rmod->ambilBeratPria

问题 Here is the code I used for uploading an image. $this->load->library('upload'); $ext = pathinfo($file_name, PATHINFO_EXTENSION); $img_name = now() . "." . $ext; $imgConfig['upload_path'] = $this->image_path; $imgConfig['file_name'] = $img_name; $imgConfig['max_size'] = '2048'; $imgConfig['allowed_types'] = 'jpg|png|bmp'; $imgConfig['overwrite'] = FALSE; $this->upload->initialize($imgConfig); if ($this->upload->do_upload("image_url")) { $this->Playlist_model->update_playlist($insert_id, array(

问题 I have a problem with printing my data. In my program, i get the data which was in object and put in an array. say array1[$id] = dataobject. the whole array1 then will be put to array2['list'] like array2['list'] = array1; the problem is how do i get the data such as the id, name and description.. here's the print_r of the whole array: this is actually the result of the array, i am not sure how to access this. i want to foreach and get the name and print them: Array ( [list] => Array ( [0] =>

问题 I am using the default codeIgniter mail class, which is very slow for me to send the email, it takes me up to 3 seconds to from start to finish. Can I do something to make the user think it is faster. I know that sending email takes time, but can I show the result to the user first, and send to later or something other workaround? Thanks. 回答1: It won't be the class that is slow, it will be the SMTP mail server you are trying to connect to that sends the email that is making the page lag.