click | 易学教程

PhantomJS .click() not working

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问题 This code does not work: var page = require('webpage').create(); page.open('http://www.ebay.com/', function() { console.log('Page loaded'); page.includeJs('http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js', function() { console.log('jQuery included'); page.render('C:/beforeclick.jpeg'); console.log('Render 1'); page.evaluate(function() { $('.btn-prim').click(); }); page.render('C:/afterclick.jpeg'); console.log('Render 2'); }); }); In fact $('.btn-prim').click() does not work,

javascript simulate mouse click on specific position

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I need to now how to fire a mouse click event on a button automatically. I have this but doesn't work :( window.setInterval(function() { simulateClick(); }, 2000); function simulateClick() { var evt = document.createEvent("MouseEvents"); evt.initMouseEvent("click", false, false, window, 0, 684, 571, 684, 508, false, false, false, false, 0, null); var a; a.dispatchEvent(evt); } Thanks in advance Oscar If all you want to do is click a button, button elements have a click method that can be invoked: <input type="button" id="theButton" onclick="javascript:alert('The button was clicked!');" value=

Bootstrap 增删改查

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var InitiateEditableDataTable = function () { return { init: function () { //Datatable Initiating var oTable = $('#editabledatatable').dataTable({ "aLengthMenu": [ [5, 15, 20, 100, -1], [5, 15, 20, 100, "All"] ], "iDisplayLength": 5, "sPaginationType": "bootstrap", "sDom": "Tflt<'row DTTTFooter'<'col-sm-6'i><'col-sm-6'p>>", "oTableTools": { "aButtons": [ "copy", "print", { "sExtends": "collection", "sButtonText": "Save <i class=\"fa fa-angle-down\"></i>", "aButtons": ["csv", "xls", "pdf"] }], "sSwfPath": "assets/swf/copy_csv_xls_pdf.swf" }, "language": { "search": "", "sLengthMenu": "_MENU_",

jQuery on button click not working

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问题 I am using jquery mobile click function, however, it is not working. Here is an example of the button that I have, and it is contained within a grid: <div class="ui-block-c"><a class="request" data-role="button" data-id="\"'+json[i].num+'\" data-type="3" data-icon="plus" data-iconpos="right">Test</a></div> jQuery function: $('.request').on('click', function() { alert("hi"); }); How do I fix this? 回答1: It looks like you are adding this element dynamically, so you'll need to use a delegated

jQuery AjaxUpload, have to click button twice?

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I am using the AjaxUpload plugin with jQuery, and everything is working fine for the most part, but I have to click my button twice to get it to execute. I'm guessing this is a scope issue... or(?) still learning... Here is my code: $(".upload-button").live("click", function(event) { event.preventDefault(); var currentId = $(this).closest("div").attr("id").replace("slide-", ""); new AjaxUpload($(this), { action: "./php/upload.php", name: 'userfile', autoSubmit: true, onSubmit: function(file , ext) { }, onComplete: function(file, response) { // enable upload button // this.enable(); $("#slide-"

Jquery if its the first time element is being clicked

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问题 I need my script to do something on the first time an element is clicked and continue to do something different on click 2,3,4 and so on $('selector').click(function() { //I would realy like this variable to be updated var click = 0; if (click === 0) { do this var click = 1; } else { do this } });//end click really I think it should rely on the variables but I can't think of how to update the variable from here on out any help would be awesome. 回答1: Have a look at jQuery's .data() method.

Fire button click event using a key combination in c#

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I've created custom button derived from a normal .Net button and have added the following property to add a short cut key combination: public Keys ShortCutKey { get; set; } I want this combination to fire the click event of the button but have no idea how to implement this when the button is placed on a form. I know the standard way of doing a button shortcut is to use the & before the short cut character but I need to use a key combination. Any ideas? Many Thanks Override the form's ProcessCmdKey() method to detect shortcut keystrokes. Like this: private bool findShortCut(Control

How can I get the position of the item within a listview when I click on a specific view?

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As the title says I want to know the exact position of the item when I click on a view that is inside the item. Suppose I have the following code within the getView() method from ArrayAdapter: ... holder = new ViewHolder (); holder.iconAction = (ImageView)convertView.findViewById (R.id.download_item_iconAction); holder.iconAction.setOnClickListener (new View.OnClickListener(){ @Override public void onClick (View v){ //Item X is clicked } }); ... Within onClick() I know the view that is clicked, v, but I don't know the position of the item. Let's do a trick. I'm going to save the position in a

Click detection in a 2D isometric grid?

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I've been doing web development for years now and I'm slowly getting myself involved with game development and for my current project I've got this isometric map, where I need to use an algorithm to detect which field is being clicked on. This is all in the browser with Javascript by the way. The map It looks like this and I've added some numbers to show you the structure of the fields (tiles) and their IDs. All the fields have a center point (array of x,y) which the four corners are based on when drawn. As you can see it's not a diamond shape, but a zig-zag map and there's no angle (top-down

Tracking visitor IP/Clicks in PHP

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I am trying to write a script or more like come up with a simple logic to track clicks or visits. I don't need to track each page, just as long as they land on the homepage is where I want to store it as 1 click. First of all, is it safe to say that tracking by IP is far from accurate because many users can be under the same IP? Currently my logic to do this is set a cookie on client side with a flag when they land on the homepage for the first time. At that point, I would update the database with 1 unqiue click as unique. Then each time this same visitor visits, the homepage would check for