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getResources() or create own static class?

匿名 (未验证) 提交于 2019-12-03 09:05:37
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I noticed myself constantly typing: someVar = getResources().getString(R.string.someString); I have several XML files that I am parsing and building and in order to make sure that the files stay consistent, I have placed the tag names in the res/values/strings.xml file. The same handles are used throughout several activities, and some of those activities extend ListActivity while others do not so creating a simple super class which houses these variables ( ex: public class thisClass extends thatClass {...} public class thatClass { package

Cannot find 'resource' in class org.apache.maven.plugins.shade.resource.ManifestResourceTransformer

匿名 (未验证) 提交于 2019-12-03 09:02:45
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: when my use maven-shade-plugin package a execute jar, then Failed, and print error message: Cannot find 'resource' in class org.apache.maven.plugins.shade.resource.ManifestResourceTransformer follow is my config: <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-shade-plugin</artifactId> <version>3.0.0</version> <executions> <execution> <phase>package</phase> <goals> <goal>shade</goal> </goals> <configuration> <transformers> <transformer implementation="org.apache.maven.plugins.shade.resource.ManifestResourceTransformer"

Async socket client using TcpClient class C#

匿名 (未验证) 提交于 2019-12-03 08:57:35
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have implemented a socket client using TcpClient class. So I can send and receive data, everything works good. But I ask some of the guru's out there :) Is there something wrong with my implementation? maybe there is a better way of doing things. In particular, how do I handle disconnects? Is there some indicator (or maybe I can write one myself) that tells me that socket has disconnected? I also have looked into async await features of Socket class, but can't wrap my head around "SocketAsyncEventArgs", why is it there in the first place.

Overriding other __rmul__ with your class&#039;s __mul__

匿名 (未验证) 提交于 2019-12-03 08:52:47
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: In Python, is it possible for your class's __rmul__ method to override another class's __mul__ method, without making changes to the other class? This question arises since I'm writing a class for a certain type of linear operator, and I want it to be able to multiply numpy arrays using the multiplication syntax. Here is a minimal example illustrating the issue: import numpy as np class AbstractMatrix(object): def __init__(self): self.data = np.array([[1, 2],[3, 4]]) def __mul__(self, other): return np.dot(self.data, other) def __rmul__(self

What happens when you have the same class twice in a war deployed in tomcat?

匿名 (未验证) 提交于 2019-12-03 08:46:08
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: What happens when you have the same compiled class twice in a war deployed in tomcat? (I know it's not a good practice and so on, but what happens behind the scene?) Are there chances of nasty side-effects? 回答1: I would expect the behaviour is the same as anywhere else you have that situation. The first class found by the class loader will be used, the other will be ignored. 回答2: If you have one class is in WEB-INF/classes and the other in a jar, the one in WEB-INF/classes will have priority. If the two classes are in a jar, then one of them

How to put a directory first on the classpath with Spring Boot?

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am building my Spring Boot application using Maven, so I can start it with: java - jar myjar - 1.0 - SNAPSHOT . jar -- spring . profiles . active = prod I want to have a directory first on the classpath that would allow me to place some files on the filesystem without having to unzip the jar to change them. I have tried using loader.path , but it does not seem to work. java - Dloader . path = "config/*" - jar myjar - 1.0 - SNAPSHOT . jar -- spring . profiles . active = prod The config dir is a subdirectory of where the jar is

Issue with setting value for Python class inherited from multiprocessing.Process

匿名 (未验证) 提交于 2019-12-03 07:50:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Why this code import multiprocessing import time class Bot(multiprocessing.Process): def __init__(self): self.val = 0 multiprocessing.Process.__init__(self) def setVal(self): self.val = 99 def run(self): while True: print 'IN: ', self.val time.sleep(2) if __name__ == '__main__': bot = Bot() bot.start() bot.setVal() while True: print 'OUT: ', bot.val time.sleep(2) gives following output? OUT: 99 IN: 0 OUT: 99 IN: 0 OUT: 99 IN: 0 OUT: 99 IN: 0 OUT: 99 IN: 0 OUT: 99 IN: 0 ... As you may guess i expect to get all 99, IN and OUT. But i do not.

How to create a Dataset from custom class Person?

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I was trying to create a Dataset in Java, so I write the following code: public Dataset createDataset(){ List<Person> list = new ArrayList<>(); list.add(new Person("name", 10, 10.0)); Dataset<Person> dateset = sqlContext.createDataset(list, Encoders.bean(Person.class)); return dataset; } Person class is an inner class. Spark however throws the following exception: org.apache.spark.sql.AnalysisException: Unable to generate an encoder for inner class `....` without access to the scope that this class was defined in. Try moving this class out

Starting JavaFX from Main method of class which doesn&#039;t extend Application

匿名 (未验证) 提交于 2019-12-03 02:50:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm having problem to start a JavaFX Application from a Main method of a class which doesn't extend javafx.application.Application In my application there is the MainApp.java which should start the overriden method start() in the MainUIController.java , which extends Applciation When I start the Main method from the MainUIController.java everything works fine. MainApp.java public class MainApp { public static void main(String[] args) { PersonJDBCTemplate jdbc = connect(); MainUIController mUIc = new MainUIController(jdbc); mUIc.start(new

error: anachronistic old-style base class initializer

匿名 (未验证) 提交于 2019-12-03 02:47:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: The following code produces the subsequent compilation error on all versions of GCC that I've tried, in C++98, C++11 and C++14 modes: struct T { T(void* x) : (x) {} }; // main.cpp: In constructor 'T::T(void*)': // main.cpp:3:18: error: anachronistic old-style base class initializer [-fpermissive] // T(void* x) : (x) {} // ^ // main.cpp:3:16: error: unnamed initializer for 'T', which has no base classes // T(void* x) : (x) {} Sure, it's clearly broken code because I'm not actually initialising anything. But why is it a base-class initialiser