circular-reference | 易学教程

How jQuery data() breaks circular reference

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问题 I have read an why it's better and how it's implemented. But what i don't really understand is how does it break the circular reference? . how does it break the reference circle? $(div1).data('item', div2); $(div2).data('item', div1); like example, the divs above point to each other, how is it prevented? I have a hunch, but i just want to make sure if my hunch is right. 回答1: The circular reference problem happens in some browsers when you put a reference to a DOM object on a DOM object as a

Resolving Circular References (C#)

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I'm having a couple of problems with circular reference/dependency that I've been sitting on all day. Something must be wrong with my thought process, I just don't get it. Here are my projects: Flip.Main (ASP.NET MVC) Flip.Domain (C# DLL) Flip.Services (C# DLL) Flip.Utility (C# DLL) Current References/Dependencies: Flip.Main -> Flip.Domain, Flip.Services, Flip.Utility Flip.Services -> Flip.Domain, Flip.Utility Flip.Domain -> Flip.Utility I wanted to structure my project in a way that my services project has all services, my domain project the model, repository and 'fluent' extensions to query

Javascript Deep Clone Object with Circular References

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问题 I have copied the function below from an existing answer by Dmitriy Pichugin. This function can deep clone an object without any circular references- it works. function deepClone( obj ) { if( !obj || true == obj ) //this also handles boolean as true and false return obj; var objType = typeof( obj ); if( "number" == objType || "string" == objType ) // add your immutables here return obj; var result = Array.isArray( obj ) ? [] : !obj.constructor ? {} : new obj.constructor(); if( obj instanceof

Circular reference in C++ without pointers

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Is there a way to define circular references without using pointers? I need to have somthing like this: struct A; struct B { A a; }; struct A { B b; }; Thanks! You can use references instead struct A; struct B { A& a; }; struct A { B b; }; But no it's not possible to create a circular reference without some level of indirection. What your sample is doing is not even creating a circular reference, it's attempting to create a recursive definition. The result would be a structure of infinite size and hence not legal. No, there's not. Such structure would have infinite size. You can use smart

How to prevent a self-referencing table from becoming circular

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This is a pretty common problem but I haven't yet found the exact question and answer I'm looking for. I have one table that has a FK pointing to its own PK, to enable an arbitrarily deep hierarchy, like the classic tblEmployee that has a column Manager that is a FK with the PK tblEmployee.EmployeeID. Let's say in my app, the user Creates new employees Alice and Dave, with no manager because they're the CEO and President. So tblEmployee.Manager is NULL for those two records. Create new employee Bob, with Alice as manager. Then create Charles with Bob as his manager. Their Manager fields

Converting circular structure to JSON — Any way to find what field it is complaining about?

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问题 I'm trying to stringify(...) an object in Chrome, and I keep getting a "Converting circular structure to JSON" message, despite the fact that (as far as I know) no such structure exists. I've been over the code a dozen times and can't find any circular references whatsoever. Is there any way to get Chrome to tell me what it's bitching about beyond this painfully useless error message? 回答1: Pardon me if this is too obvious. At the time of writing, I dont know what you have tried. insert

How to deal with circular references?

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If I have those two projects: MyCompany.ERP.Billing MyCompany.ERP.Financial Billing asks/sends information to Financial and vice-versa. Both are too big so I don't want to put them in a single project. Visual Studio doesn't allow circular references. How would you deal with that? devnull Extract interfaces from your classes and put them into a core project referenced from both Billing and Financial projects. You can then use those interfaces to share data between assemblies. This only allows you to pass objects between those 2 assemblies, but you can't create objects from the other since you

How to avoid circular unit reference?

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Imagine the following two classes of a chess game: TChessBoard = class private FBoard : array [1..8, 1..8] of TChessPiece; ... end; TChessPiece = class abstract public procedure GetMoveTargets (BoardPos : TPoint; Board : TChessBoard; MoveTargetList : TList <TPoint>); ... end; I want the two classes to be defined in two separate units ChessBoard.pas and ChessPiece.pas . How can I avoid the circular unit reference that I run into here (each unit is needed in the other unit's interface section)? Change the unit that defines TChessPiece to look like the following: TYPE tBaseChessBoard = class;

c# : Utility to find circular references / compile in correct order?

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doers anyone know of a good utility or program to interrogate a solution or a directory for all projects and tell you where circular references are and possible compile in order.. I remember see one a while ago but i can't find it anywhere.. NDepend is an excellent tool that will do this and a lot more. Maybe it's overkill for what you want, but there's a trial version so have a look... I know this is a late answer, but I found using GraemeF and tsilb's answers both showed no dependency between the two assemblies. It looks like if you reverse the order of dependencies ( Assembly A references B

scala: circular reference while creating object?

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I accidentally ran into a situation like this (the example is simplified to isolate the problem): abstract class Element(val other: Element) case object First extends Element(Second) case object Second extends Element(First) object Main { def main(arguments: Array[String]) { val e1 = First val e2 = Second println("e1: "+e1+" e1.other: "+e1.other) println("e2: "+e2+" e2.other: "+e2.other) } } Anyone would like to guess the output? :-) e1: First e1.other: Second e2: Second e2.other: null The output makes kind of sense. Apparently at the time the Second object is created, the First one does not