chmod

linux文件权限chmod

半城伤御伤魂 提交于 2019-12-07 10:23:03
linux的文件权限通过用户,组和其它组来实现。一个文件只能属于一个用户和组, 如果其它的用户想有这个文件的权限,则可以将该用户加入这个组,一个用户可以同时属于多个组。一般来说一个应用下不要有太多的文件组和用户,最好不要用 ROOT执行角本,这样权限都放放大,比较不安全 Linux下很重视权限,权限包括读,写,执行。所以即使Linux下染了病毒,也不一定中病毒,其实就是这个权限的问题。初学者在Linux执行 命令是会感觉比较累,每次都是要用su来切换用户,其实这也是Linux保护数据的一种模式。当然建议,用户登入是不要直接用root用户登入。如果知道 root登录命令的话。 Linux下有用户跟群组的观念。往往分为三个部分,持该文件的用户(user),跟持该文件同组的用户(group),剩下的其他用户(other)。一个用户可以属于很多个群组。Linux下表示权限有两种方式: 一种是八进制表示法(十位表示法,不是说八进制有十位,而是 三个八进制位,再加一个最高位共十位 ), 另外一种十二位二进制表示法(十二个二进制位)。 先介绍第一种: 是三种模式,三个属组,就构成了9位。-代表无权限,r代表只读,w代表写的权限,x则代表执行。所以就有下面的组合。将-视为0,x视为1,w视 为2,r视为4.这种组合根据该位是否有这个数来确定,就确定如下的9种组合方式。刚好,总的权值0

Clearcase protect -chmod +x recursively all *.exe

自作多情 提交于 2019-12-07 08:30:43
问题 I am trying to recursively change all .exe in a directory. I did a bit more digging before posting and ended up finding what I needed. Will post with my answer just on case anyone can used this information. Hope that is alright I am new here. ct find . -all -name *.bat -print -exec "cleartool protect -chmod +x -file ""%CLEARCASE_PN%""" 回答1: When you consider the man page of cleartool find, and the additional examples of cleartool find -all generally for quite lengthy search, especially for

How to convert an input of 3 octal numbers into CHMOD permissions into Binary?

旧时模样 提交于 2019-12-07 06:08:36
I am trying to create a program that takes input from the user using the command line of 3 octal number, for example 5, 2, 6 or 5,2,6 and convert them into 3 sets of 3 digit binary numbers, like 101 010 110, and also print out those corresponding CHMOD permissions like r-x -w- rw-. I am having a lot of trouble splicing these numbers apart with substring into 3 separate numbers of 5 2 and 6. I also need the program to convert from the set of binary digits into 3 numerical digits and permissions. And from the permissions into digits and binary. Here is what I have so far: import java.util

CentOS7 Xftp 上传文件 错误

杀马特。学长 韩版系。学妹 提交于 2019-12-07 03:45:45
上传文件显示 错误 ,详情提示: xftp permission is not allowed 修改权限 chmod chmod 777 目标文件夹 参考资料 Linux chmod命令 https://www.runoob.com/linux/linux-comm-chmod.html 来源: CSDN 作者: 笑虾 链接: https://blog.csdn.net/jx520/article/details/90356512

Is chmod 757 safe?

心已入冬 提交于 2019-12-07 03:32:10
问题 As i am on a shared host , i want to add a image hosting script and it seems that with 755 it doesnt allow me to upload images, so i changed the folder to 757 , is it safe to chmod to 757? 回答1: In a word, no. In two words, "hell. no!" Let's interpret 757: that would be owner: read write execute groups that have permissions on the file: read - execute the rest of the freaking world: read write execute now, consider someone malicious uploading a short shell script: #!/bin/sh -- rm -rf / Update

chmod - protect users' file being accessed so only owner can access?

我与影子孤独终老i 提交于 2019-12-06 20:24:48
问题 How to set chmod, so that ONLY owner of the file can read, write and execute? (other users cannot read, write, and execute) 回答1: chmod 600 filename will do it; or chmod 700 if it is an executable. Another way that is less cryptic is: chmod go-rwx filename The "g" is for group The "o" is for others The "-" is for removing permissions The "r" is for read-permission The "w" is for write-permission The "x" is for execute permission. 回答2: You can do the following command on the file: chmod 744

chmod - replicate user permissions to group/world

折月煮酒 提交于 2019-12-06 16:55:53
I have a need to make some folders/files (recursive) have the same permissions as that of the user. So: 0755 -> 0777 0644 -> 0666 How can I do so? Perhaps a little secret command I do know of? If there is no easy way then perhaps I would need to create a loop and test/assign. Ultimately I only need to deal with 3 types: Folders should be 777, most files 666, executables 777. find can do the work of finding files with a given permission set and running the smallest possible number of chmod invocations necessary to cover them. find . \ '(' -perm -0700 -exec chmod 0777 '{}' + ')' -o \ '(' -perm

Hive on Google Cloud wants permissions on /tmp, but no way to change permissions

坚强是说给别人听的谎言 提交于 2019-12-06 16:18:41
I'm trying to run Hive on a Google Cloud, where Hadoop was installed by click-to-deploy . Hive seems to instal just fine, but when I run hive I get the following erroneous output: Logging initialized using configuration in jar:file:/home/michael_w_sherman_gmail_com/apache-hive-0.14.0-bin/l ib/hive-common-0.14.0.jar!/hive-log4j.properties SLF4J: Class path contains multiple SLF4J bindings. SLF4J: Found binding in [jar:file:/home/hadoop/hadoop-install/share/hadoop/common/lib/slf4j-log4j12-1.7.5.jar! /org/slf4j/impl/StaticLoggerBinder.class] SLF4J: Found binding in [jar:file:/home/michael_w

linux中的文件权限chmod

泄露秘密 提交于 2019-12-06 15:11:09
linux中的文件权限chmod ​ 还是GPU集群那点事儿,集群之间磁盘互相挂载,普通用户也可以操作/cu02_nfs、/cu04_nfs文件夹,这就牵扯到权限的问题,去google发现所谓的777和754,刚好可以记录下。 1. 命令 首先给出两个命令 chmod 777 文件 chmod -R 777 文件夹 功能:将文件/文件夹的读写运行权限赋予给 文件/文件夹所有者 (7) 、 同组的用户 (7)、 其他组用户 (7) chmod 754 文件 chmod -R 754 文件夹 功能:文件/文件夹的 读写运行 权限赋予 文件所有者 ,把 读和运行 的权限赋予 群组用户 ,把 读 的权限赋予其他用户 注意: -R 是文件夹迭代的意思 2. 具体介绍 下面具体介绍chmod命令。 Linux系统中,每个用户的角色和权限划分的很细致也很严格,每个文件(目录)都设有访问许可权限,利用这种机制来决定某个用户通过某种方式对文件(目录)进行读、写、执行等操作。 操作文件或目录的用户,有3种不同类型: 文件所有者 、 群组用户 、 其他用户 。 最高位表示文件所有者的权限值,中间位表示群组用户的权限值,最低位则表示其他用户的权限值 ,所以,chmod 777中, 三个数字7分别对应上面三种用户,权限值都为7 。 文件或目录的权限又分为3种:只读、只写、可执行。 权限 权限数值 二进制

putty免密登录

不羁的心 提交于 2019-12-06 14:23:45
1.打开生成密钥的工具(在搜索栏里搜索putty),点击Run PuTTYgen 2.点击Generate生成密钥 2.点击save private key 保存私钥 3.将公钥复制到所需登录的虚拟机上的~/.ssh/authorized_keys中 4.如果虚拟机上还没有~/.ssh/authorized_keys的话则手动创建 5.设置权限 chmod 700 ~/.ssh/ chmod +x ~/.ssh/authorized_keys 6.登录时记得在这里加上私钥保存的路径 7.结束。 来源: https://www.cnblogs.com/lyz-2019-12-05/p/11989657.html