child-process

I am using spawn to spawn a long running process that sends output over time to stdio, and is read and processed by my nodejs script. The tricky part is that I cannot guarantee that the command sent will always be valid. How can I catch an error in spawning? Preferably this will not involve installing a global exception handler, since I don't want to handle any other exceptions. (If that's the only way, I would need to figure out when the spawned process has started up correctly and then uninstall the handler, which is a mess I'd rather not get into.) The code I want to run would be something

can someone help me about how to create multiple child processes which have the same parent in order to do "some" part of particular job? for example, an external sorting algorithm which is applied with child processes; each child process sorts a part of data and finally the parent merges them.. EDIT: Maybe I should mention the forking multiple child processes with loop.. Here is how to fork 10 children and wait for them to finish: pid_t pids[10]; int i; int n = 10; /* Start children. */ for (i = 0; i < n; ++i) { if ((pids[i] = fork()) < 0) { perror("fork"); abort(); } else if (pids[i] == 0) {

Is it possible to get the child process id from parent process id in shell script? I have a file to execute using shell script, which leads to a new process process1 (parent process). This process1 has forked another process process2 (child process). Using script, I'm able to get the pid of process1 using the command: cat /path/of/file/to/be/executed but i'm unable to fetch the pid of the child process. Just use : pgrep -P $your_process1_pid I am not sure if I understand you correctly, does this help? ps --ppid <pid of the parent> I'v written a scrpit to get all child process pids of a parent

Created a childprocess using shelljs !/usr/bin/env node require('/usr/local/lib/node_modules/shelljs/global'); fs = require("fs"); var child=exec("sudo mongod &",{async:true,silent:true}); function on_exit(){ console.log('Process Exit'); child.kill("SIGINT"); process.exit(0) } process.on('SIGINT',on_exit); process.on('exit',on_exit); Child process is still running .. after kill the parent process If you can use node's built in child_process.spawn , you're able to send a SIGINT signal to the child process: var proc = require('child_process').spawn('mongod'); proc.kill('SIGINT'); An upside to

This is similar to this question , but I wanted to flesh it out a bit. (I'm new here, if I should instead do a "bump" answer on the previous question instead, please let me know.) In WinDBG, I can use the .childdbg 1 command to tell it to break when a child process is spawned, or I can launch it with the -o command-line option. This is very useful in some situations, so it's surprising that (as far as I can see) Visual Studio doesn't support it. It seems like it ought to be pretty easy to clear the DEBUG_PROCESS_ONLY_THIS_PROCESS flag on CreateProcess(), and VS already supports debugging

I wanted to initiate a process from my python script (main.py) , specifically I want to run the below command `nohup python ./myfile.py &` and this file myfile.py should even after my main python script exits. Additionally I wish to get the pid of the new process. I tried os.spawnl* , os.exec* & subprocess.Popen methods, all are terminating my myfile.py if my main.py script exits. I may be missing something. Update: Can I use os.startfile with xdg-open ? Is it a right approach? Example a = subprocess.Popen([sys.executable, "nohup /usr/bin/python25 /long_process.py &"],\ stdout=subprocess.PIPE,