child-process | 易学教程

Command line application: How to attach a child process to xcode debugger?

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问题 I'm currently making a command line app in C in which many child process is created. So I need to debug this children code. I have created a child process on Xcode as follow. (see the break point and running cursor.) After executing some statements, I get xcode to attach GBN(885) to the xcode debugger as shown in below figure. It doesn't work. How can I attach the child process to xcode debugger? Thank you in advance. 回答1: Google and Apple developer page are really silent on this issue and

How to debug child Node.JS process in Visual Studio Code?

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How to debug child Node.JS process in VS Code? Here is the example of the code that I'm trying to debug: var spawn = require('child_process').spawn; var scriptPath = './child-script.js'; var runner_ = spawn('node', [scriptPath]); Benjamin Pasero You can easily add a new launch configuration to launch.json that allows you to attach to a running node instance with a specific port: { "name": "Attach to Node", "type": "node", "address": "localhost", "port": 5870, } Just make sure you fork/spawn your node process with the --debug or --debug-brk argument. In your launch configuration add

nodejs/express - stream stdout instantly to the client

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问题 I spawned the following child: var spw = spawn('ping', ['-n','10', '127.0.0.1']) and I would like to receive the ping results on the client side ( browser ) one by one , not as a whole. So far I tried this: app.get('/path', function(req, res) { ... spw.stdout.on('data', function (data) { var str = data.toString(); res.write(str + "\n"); }); ... } and that: ... spw.stdout.pipe(res); ... In both cases browser waits 10 of the pings to complete, and then prints the result as a whole. I would like

How to fetch the details from mongo db and send or store in object in nodejs Fork method

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问题 Here I am using fork method to do some calculation in node js. I have followed by the answer in link.It worked as expected and had started to do calculation. Here how can I get the details from the mongodb in child file.I am using mongoose for mongodb. My sample code is below main.js var childprocess = require('child_process'); var child = childprocess .fork(__dirname + '/childpage'); child.on('message', function(m) { // Receive results from child process console.log('received: ' + m); });

kill all child_process when node process is killed

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问题 How do i make sure all child_process are killed when the parent process is killed. I have something like the below one. Even when the node process is kill i see that FFMPEG continues to run and the out.avi is generated. How can i stop FFMPEG from running after the node process exits. var args = "ffmpeg -i in.avi out.avi" child_process.exec(args , function(err, stdout,stderr){}); child_process.exec(args , function(err, stdout,stderr){}); 回答1: You need to listen for the process exit event and

Terminating zombie child processes forked from socket server

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问题 Disclaimer I am well aware that PHP might not have been the best choice in this case for a socket server. Please refrain from suggesting different languages/platforms - believe me - I've heard it from all directions. Working in a Unix environment and using PHP 5.2.17 , my situation is as follows - I have constructed a socket server in PHP that communicates with flash clients. My first hurtle was that each incoming connection blocked the sequential connections until it had finished being

How to wait for a child process to finish in Node.js?

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I'm running a Python script through a child process in Node.js, like this: require('child_process').exec('python celulas.py', function (error, stdout, stderr) { child.stdout.pipe(process.stdout); }); but Node doesn't wait for it to finish. How can I wait for the process to finish? EDIT: Is it possible to do this by running the child process in a module I call from the main script? Frederic Nault You should use exec-sync That allow your script to wait that you exec is done really easy to use: var execSync = require('exec-sync'); var user = execSync('python celulas.py'); Take a look at: https:/

node.js child_process.spawn no stdout unless 'inherit'

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I'm trying to capture the stdout from a spawn ed child_process in node.js (0.10.29). Right now I'm just trying with ping The following code doesn't print (but does ping) var exec = require('child_process').exec; var spawn = require('child_process').spawn; var util = require('util') var ping = spawn('ping', ['127.0.0.1'], {stdio: 'pipe'}); ping.stdout.on('data', function(data){ util.print(data); }) ping.stderr.on('data', function(data){ util.print(data); }) If I change stdio: 'pipe' to stdio: 'inherit' and get rid of the stdout/stderr hooks like so: var ping = spawn('ping', ['127.0.0.2'],

Trap signal in child background process

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I am unable to trap a signal when running in a child / background process. Here is my simple bash script : #!/bin/bash echo "in child" trap "got_signal" SIGINT function got_signal { echo "trapped" exit 0 } while [ true ]; do sleep 2 done When running this and later do kill -SIGINT (pid) Everything works as expected, it prints 'trapped' and exits. Now, if I start the same script from a parent script like this : #!/bin/bash echo "starting the child" ./child.sh & Then the child does not trap the signal anymore.... ? After changing to use SIGTERM instead of SIGINT, it seems to be working correctly

kill all child_process when node process is killed

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How do i make sure all child_process are killed when the parent process is killed. I have something like the below one. Even when the node process is kill i see that FFMPEG continues to run and the out.avi is generated. How can i stop FFMPEG from running after the node process exits. var args = "ffmpeg -i in.avi out.avi" child_process.exec(args , function(err, stdout,stderr){}); child_process.exec(args , function(err, stdout,stderr){}); You need to listen for the process exit event and kill the child processes then. This should work for you: var args = "ffmpeg -i in.avi out.avi" var a = child