channel

I'm currently struggling with lifetimes in Rust (1.0), especially when it comes to passing structs via channels. How would I get this simple example to compile: use std::sync::mpsc::{Receiver, Sender}; use std::sync::mpsc; use std::thread::spawn; use std::io; use std::io::prelude::*; struct Message<'a> { text: &'a str, } fn main() { let (tx, rx): (Sender<Message>, Receiver<Message>) = mpsc::channel(); let _handle_receive = spawn(move || { for message in rx.iter() { println!("{}", message.text); } }); let stdin = io::stdin(); for line in stdin.lock().lines() { let message = Message { text:

I have a struct that holds a channel that is not initialized. When I write into it, the routine is blocking as expected but the reader is never notified that something is in the pipe. I am surprised that there is no error and I am wondering what is doing Go. In the example bellow, neither the message pushed nor got it are printed. (Uncomment the intialization and it will work like a charm) type MyStruct struct { over chan bool } func main() { nonInitialized := &MyStruct{} // nonInitialized.over = make(chan bool) go func() { for i := 0; i < 10; i++ { select { case <-nonInitialized.over: fmt

Given the following simple Go program package main import ( "fmt" ) func total(ch chan int) { res := 0 for iter := range ch { res += iter } ch <- res } func main() { ch := make(chan int) go total(ch) ch <- 1 ch <- 2 ch <- 3 fmt.Println("Total is ", <-ch) } I am wondering if someone can enlighten me as to why I get throw: all goroutines are asleep - deadlock! thank you As you never close the ch channel, the range loop will never finish. You can't send back the result on the same channel. A solution is to use a different one. Your program could be adapted like this : package main import ( "fmt"

When looking through some Golang code I found the following: ch := make(chan int) I looked up in a online tutorial how Golang Channels work: https://tour.golang.org/concurrency/2 But I find this example unclear. Can someone give me a easy explanation and an example of the use of channels? chan is a channel in Golang. In simple word you can think it as a box in which you put a item at one end and then pick it from other end.(order does not matter) Something like Unbuffered Channels Buffered Channel This is the small code I have written for you to understand channels. Now change order of go

In my C# (3.5) application I need to get the average color values for the red, green and blue channels of a bitmap. Preferably without using an external library. Can this be done? If so, how? Thanks in advance. Trying to make things a little more precise: Each pixel in the bitmap has a certain RGB color value. I'd like to get the average RGB values for all pixels in the image. The fastest way is by using unsafe code: BitmapData srcData = bm.LockBits( new Rectangle(0, 0, bm.Width, bm.Height), ImageLockMode.ReadOnly, PixelFormat.Format32bppArgb); int stride = srcData.Stride; IntPtr Scan0 =