cell | 易学教程

html 基础篇

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HTML 概述 HTML是英文Hyper Text Mark-up Language(超文本标记语言)的缩写，他是一种制作万维网页面标准语言（标记）。相当于定义统一的一套规则，大家都来遵守他，这样就可以让浏览器根据标记语言的规则去解释它。浏览器负责将标签翻译成用户“看得懂”的格式，呈现给用户！(例：djangomoan模版引擎) html 基本组成部分 <!DOCTYPE html> 声明浏览器显示规则 <html> 说明这个是一个网页。告诉浏览器这个网页的开始和结束。他包含了之后的两个元素。<head>和</head>|<body>和</body> <head> 是元信息和网站的标题元信息一般是不显示出来的,但是记录了你这个HTML文件的很多有用的信息 </head> <body> 是浏览器呈现出来的，用户看到的页面效果。也就是说这里是网页的主体。也就是body的身体之意 </body> </html> html文档类型 DOCTYPE 标签 -- 定义了标准文档的类型 DOCTYPE标签是单独出现的说明：文档类型，会使浏览器使用相应标准加载网页并显示文档类型定义在HTML文档的第一行，在html标签之前文档不定义DOCTYPE，浏览器将无法获知HTML或XHTML文档的类型，因此会进入混乱模式，详见：浏览器模式引用网址：http://www.dreamdu.com

Matrix Game（尼姆博弈变形）

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Given an m x n matrix, where m denotes the number of rows and n denotes the number of columns and in each cell a pile of stones is given. For example, let there be a 2 x 3 matrix, and the piles are 2 3 8 5 2 7 That means that in cell(1, 1) there is a pile with 2 stones, in cell(1, 2) there is a pile with 3 stones and so on. Now Alice and Bob are playing a strange game in this matrix. Alice starts first and they alternate turns. In each turn a player selects a row, and can draw any number of stones from any number of cells in that row. But he/she must draw at least one stone. For example, if

Codeforces H. Kilani and the Game（多源BFS）

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题目描述： Kilani and the Game time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Kilani is playing a game with his friends. This game can be represented as a grid of size n × m , where each cell is either empty or blocked, and every player has one or more castles in some cells (there are no two castles in one cell). The game is played in rounds. In each round players expand turn by turn: firstly, the first player expands, then the second player expands and so on. The expansion happens as follows: for each castle the player owns now, he

webapi 导入excel处理数据

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参考资料　　　　 https://blog.csdn.net/pan_junbiao/article/details/82935992 　　　　　 https://www.cnblogs.com/dansediao/p/5482467.html 　　　　　 https://www.cnblogs.com/shiyh/p/7478241.html excel转成datatable工具类 using System; using System.Collections.Generic; using System.Data; using System.IO; using System.Reflection; using NPOI.HSSF.UserModel; using NPOI.SS.UserModel; using NPOI.SS.Util; using NPOI.XSSF.UserModel; namespace ELearning.Common.Extensions { public static class ExcelHelp { /// <summary> /// Id的列号 /// </summary> private const int EXCEL_COL_PLAT_FORM_INDUSTRY = 14; //获取列名委托方法 public delegate string

How do I change a single value in a data.frame?

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问题 Could anyone explain how to change a single cell in a data.frame to something else. Basically I just want to rename that one cell, not all cells which matches it. I can´t use the edit() command because it will screw up my script since im using the data.frame on several occasions. Thanks in advance 回答1: data.frame[row_number, column_number] = new_value For example, if x is your data.frame: x[1, 4] = 5 回答2: To change a cell value using a column name, one can use iris$Sepal.Length[3]=999 回答3: In

java 解析上传的Excel文件

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java poi解析上传的Excel文件 package com.zhl.push.Utils; /** * @Author TAO * @ClassName ExcelData * @Description TODO * @Date 2019/1/9 15:02 * @Version 1.0 */ import org.apache.poi.hssf.usermodel.HSSFDataFormat; import org.apache.poi.hssf.usermodel.HSSFDateUtil; import org.apache.poi.hssf.usermodel.HSSFWorkbook; import org.apache.poi.ss.usermodel.*; import org.apache.poi.xssf.usermodel.XSSFWorkbook; import org.springframework.web.multipart.MultipartFile; import java.io.ByteArrayInputStream; import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.InputStream; import java.text

using ipdb to debug python code in one cell (jupyter or Ipython)

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问题 I'm using jupyter (or Ipython) notebook with firefox, and want to debug some python code in the cell. I am using 'import ipdb; ipdb.set_trace()' as kind of breakpoint, for example my cell has the following code: a=4 import ipdb; ipdb.set_trace() b=5 print a print b which after execution with Shift+Enter gives me this error: -------------------------------------------------------------------------- MultipleInstanceError Traceback (most recent call last) <ipython-input-1-f2b356251c56> in

Want to create a cool static UI but : “Static table views are only valid…”

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So I'm creating a View like : For this I'm trying to use a Storyboard in wich I add 2 TableViews (both as 'Static Cells') and then I manually add my Cell content directly from the storyboard... In my storyboard it looks great but when I build I get : en.lproj/MainStoryboard.storyboard: error: Illegal Configuration: Static table views are only valid when embedded in UITableViewController instances If you guys have any ideas on this issue. Thanks ! Add a UITableViewController to your view. It should hold a UITableView. Define this as a static table view, and make it grouped. Add two sections.

Excel cell from which a Function is called [duplicate]

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This question already has an answer here: How to get address of cell which calls a VBA Functions in a Excel sheet 1 answer How can I get the cell where my VBA Function is called from? In other words, what is the VBA equivalent for INDIRECT(ROW(), COLUMN()) ? I'm not looking for ActiveCell . What I want to do is have a simple function ThisRow_Col(rColumn As String) return the column X of the row it's called from. Say in B2 I call =ThisRow_Col("A"), it should return the value of A2. This should work regardless of which cell active. EDIT : Thanks Charles for the answer: Application.Caller . The

javascript,xml,xslt,html动态表单框架样例

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1.文件说明 tpl.xml:表单域及内容数据文件,引用tpl.xsl tpl.xslt:表单域呈现控制脚本,引用tpl.js tpl.js:表单域呈现辅助控制标本 tpl.html:客户端html页面. 2.运行效果将tpl.xml,tpl.xslt,tpl.xsl,tpl.js,tpl.html放置在同一目录下.在浏览器中运行tpl.html即可. 3.文件内容 tpl.xml ----------------------------------------------------------------------------------------------------- <?xml version="1.0" encoding="utf-8" ?> <?xml-stylesheet href="tpl.xslt" type="text/xsl" ?> <tpl id="guid"> <table > <cell index = "1" name="c1" datasource="yes/no" value="no"/> <cell index = "2" name="c2" datasource="" value="333"/> <cell index = "3" name="c3" datasource="" value="444"/> <cell index =