cell

CSCI 3136

最后都变了- 提交于 2020-02-13 20:32:03
Project 1 CSCI 3136: Principles of Programming Languages Due February 17, 2020 Assignments are due on the due date by 23:59 AST. Since this is a programming assignment, this cover page does not need to be submitted. Plagiarism in assignment answers will not be tolerated. By submitting their answers to this assignment, the authors named above declare that its content is their original work and that they did not use any sources for its preparation other than the class notes, the textbook, and ones explicitly acknowledged in the answers. Any suspected act of plagiarism will be reported to the

【Hbase】hbase java api 增删改查

倖福魔咒の 提交于 2020-02-13 01:02:07
几个主要 Hbase API 类和数据模型之间的对应关系: java类 HBase 数据模型 Admin 数据库(DataBase) HBaseConfiguration Table 表(Table) HTableDescriptor 列簇(Column Family) HColumnDescriptor Put 列修饰符(Column Qualifier) Get Delete Result Scan ResultScanner 基本增删除改查demo package com . study . follow . hbase ; import org . apache . hadoop . conf . Configuration ; import org . apache . hadoop . hbase . * ; import org . apache . hadoop . hbase . client . * ; import org . apache . hadoop . hbase . util . Bytes ; import java . io . IOException ; /** * @author: honey * @date: 2020/2/8 */ public class HbaseDemoTest { static Configuration

longAdd

梦想的初衷 提交于 2020-02-12 20:58:21
一、LongAdder简介 https://segmentfault.com/a/1190000015865714 JDK1.8时,java.util.concurrent.atomic包中提供了一个新的原子类:LongAdder。 根据Oracle官方文档的介绍,LongAdder在高并发的场景下会比它的前辈————AtomicLong 具有更好的性能,代价是消耗更多的内存空间: clipboard.png 那么,问题来了: 为什么要引入LongAdder? AtomicLong在高并发的场景下有什么问题吗? 如果低并发环境下,LongAdder和AtomicLong性能差不多,那LongAdder是否就可以替代AtomicLong了? 为什么要引入LongAdder? 我们知道,AtomicLong是利用了底层的CAS操作来提供并发性的,比如addAndGet方法: clipboard.png 上述方法调用了Unsafe类的getAndAddLong方法,该方法是个native方法,它的逻辑是采用自旋的方式不断更新目标值,直到更新成功。 在并发量较低的环境下,线程冲突的概率比较小,自旋的次数不会很多。但是,高并发环境下,N个线程同时进行自旋操作,会出现大量失败并不断自旋的情况,此时AtomicLong的自旋会成为瓶颈。 这就是LongAdder引入的初衷—

Anaconda和jupyter notebook

柔情痞子 提交于 2020-02-12 19:49:23
- Anaconda是一个集成环境(基于机器学习和数据分析的开发环境) - 基于浏览器的一种可视化开发工具:jupyter notebook - 可以在指定目录的终端中录入jupyter notebook指令,然后启动服务。 - cell是分为不同模式的: - Code:编写python代码 - markDown:编写笔记 - 快捷键: - 添加cell:a,b - 删除cell:x - 执行:shift+enter - tab: - 切换cell的模式: - m - y - 打开帮助文档:shift+tab 来源: https://www.cnblogs.com/zhang-da/p/12300371.html

低功耗设计技术--门控电源(Power/Ground Gating)--Power Switching Cell

瘦欲@ 提交于 2020-02-12 16:54:47
本文转自:自己的微信公众号《集成电路设计及EDA教程》 概念: Power/Ground Gating是集成电路中通过关掉那些不使用的模块的电源或者地来降低电路漏电功耗的低功耗设计方法。该方法能降低电路在空闲状态下的静态功耗,还能测试Iddq。 理论: 在电路中的某些模块进入休眠或者空闲模式时,我们可以使用之前讲过的Clock Gating技术来降低它们的动态功耗,但是无法降低它们的静态功耗。而Power/Ground Gating技术可以在它们休眠的时候完全关掉它们的电源从而消除它们的静态功耗。 理想情况下,Power gating可以完全消除电路的静态功耗,可实际电路中Power gating只能完全关掉dynamic的power消耗,而leakage却只会减少,不会消失,因为power gating技术仍需要加入一些Always On的Cell(比如switching cell、isolate cell和retention cell,它们都是一直开启的,它们的电源不能被关断,会带来leakage)。 如下图所示为采用了Power gating的电路动态功耗与静态功耗在active模式以及sleep模式下功耗的变化曲线。 Power gating中用到的几种Cell 接下来将对几种Cell分别介绍。 由于内容非常多,非常详细,所以本推文先介绍第一个--Power

Codeforces Round #192 (Div. 2)

孤者浪人 提交于 2020-02-12 16:13:50
A. Cakeminator time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given a rectangular cake, represented as an r × c grid. Each cell either has an evil strawberry, or is empty. For example, a 3 × 4 cake may look as follows: The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains at least one cake cell that has not been eaten before, and eats all the cake cells there. He may decide to eat any number of times. Please output the maximum number

[Codeforces Round #192 (Div. 2)] D. Biridian Forest

故事扮演 提交于 2020-02-12 16:09:50
D. Biridian Forest time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You're a mikemon breeder currently in the middle of your journey to become a mikemon master. Your current obstacle is go through the infamous Biridian Forest. The forest The Biridian Forest is a two-dimensional grid consisting of r rows and c columns. Each cell in Biridian Forest may contain a tree, or may be vacant. A vacant cell may be occupied by zero or more mikemon breeders (there may also be breeders other than you in the forest). Mikemon breeders (including

【iOS知识学习】_iOS动态改变TableView Cell高度

雨燕双飞 提交于 2020-02-12 04:15:55
在做tableView的时候,我们有时候须要依据cell的高度动态来调整。近期在网上看到一段代码不错。跟大家Share一下。 在 -( UITableViewCell *)tableView:( UITableView *)tableView cellForRowAtIndexPath:( NSIndexPath *)indexPath{ 类中获取cell的高度: CGSize boundSize = CGSizeMake(216, CGFLOAT_MAX); cell.textLabel.text = @"12345678900123456789"; cell.userInteractionEnabled = NO; cell.textLabel.numberOfLines = 0; CGSize requiredSize = [cell.textLabel.text sizeWithFont:[UIFont systemFontOfSize:13] constrainedToSize:boundSize lineBreakMode:UILineBreakModeWordWrap]; CGRect rect = cell.frame; rect.size.height = requiredSize.height+5; cell.frame = rect;

openpyxl(python操作Excel)

半城伤御伤魂 提交于 2020-02-11 15:47:58
一、安装 >>> pip install openpyxl import openpyxl 二、常用操作 1、创建与保存一个工作簿 wb = openpyxl.Workbook() wb.save("sample.xlsx") 2、获取第一个工作表(将工作看成一个二维数组) ws = wb.activews.titlews["A1"] = 520ws.append([1, 2, 3]) 3、打开一个工作簿 wb = openpyxl.load_workbook("sample.xlsx") 4、获取工作表名称列表,再通过工作表名称获取工作表对象 sheetnames = wb.sheetnames or wb.get_sheet_names() # ["sheet", "example", "maoyan"] example = wb.get_sheet_by_name("example") or wb["example"] 5、创建和删除工作表 wb.create_sheet(index=0, title="example") # index:工作表位置 title:工作表名称 wb.remove_sheet(wb["example"]) # 需要传入一个工作表对象 6、定位单元格 example["A1"] # 获取单元格对象 example["A"] # 获取单元格元组(列)

Codeforces Round #301 (Div. 2)(A,【模拟】B,【贪心构造】C,【DFS】)

淺唱寂寞╮ 提交于 2020-02-10 05:21:00
A. Combination Lock time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock. The combination lock is represented by n rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards