c51

printf() results in gibberish

你说的曾经没有我的故事 提交于 2019-12-01 12:07:56
I have this code: unsigned char *command = "0000"; unsigned char foo = (hex_char_to_int(command[0]) << 4) | hex_char_to_int(command[1]); unsigned char bar = (hex_char_to_int(command[2]) << 4) | hex_char_to_int(command[3]); printf("foo: %02x, bar: %02x\r\n", foo, bar); It uses this function: unsigned char hex_char_to_int(unsigned char ch) { switch (ch){ case '0': return 0; case '1': return 1; case '2': return 2; case '3': return 3; case '4': return 4; case '5': return 5; case '6': return 6; case '7': return 7; case '8': return 8; case '9': return 9; case 'A': return 0xA; case 'B': return 0xB;

printf() results in gibberish

笑着哭i 提交于 2019-12-01 10:55:41
问题 I have this code: unsigned char *command = "0000"; unsigned char foo = (hex_char_to_int(command[0]) << 4) | hex_char_to_int(command[1]); unsigned char bar = (hex_char_to_int(command[2]) << 4) | hex_char_to_int(command[3]); printf("foo: %02x, bar: %02x\r\n", foo, bar); It uses this function: unsigned char hex_char_to_int(unsigned char ch) { switch (ch){ case '0': return 0; case '1': return 1; case '2': return 2; case '3': return 3; case '4': return 4; case '5': return 5; case '6': return 6;