c++17

问题 I would like to know if there is any difference the following two types of std::vector initialization in C++11 and later. std::vector<int> v1 {1, 2, 3, 4, 5}; std::vector<int> v2 = {1, 2, 3, 4, 5}; Here is a complete code example that works fine. #include <iostream> #include <vector> int main() { std::vector<int> v1 {1, 2, 3, 4, 5}; std::vector<int> v2 = {1, 2, 3, 4, 5}; std::cout << v1.size() << '\n'; std::cout << v2.size() << '\n'; } I see both initializations leading to identical results.

问题 This question already has answers here : Why do I have to access template base class members through the this pointer? (3 answers) Closed 7 months ago . I have the following code which compiles successfully in c++14. template<class T, class ...Args> class B { public: using AbcData = int; }; template<typename ...Args> class D : public B<float, Args...> { public: AbcData m_abc; }; But when compiled in c++17, it gives the following error. error C2061: syntax error: identifier 'AbcData' What is

问题 This question already has answers here : Why do I have to access template base class members through the this pointer? (3 answers) Closed 7 months ago . I have the following code which compiles successfully in c++14. template<class T, class ...Args> class B { public: using AbcData = int; }; template<typename ...Args> class D : public B<float, Args...> { public: AbcData m_abc; }; But when compiled in c++17, it gives the following error. error C2061: syntax error: identifier 'AbcData' What is

问题 #include<bits/stdc++.h> using namespace std; class Heap { vector <int> v; int length; public: void create(vector <int> v, int s); void display(); }; void Heap::create(vector <int> v, int s) { length=s+1; for(int i=1;i<=s;i++) { this->v[i]=v[i-1]; } int temp; int j; for(int i=2;i<length;i++) { temp=v[i]; j=i; while(j>1&&temp>v[j/2]) { swap(v[j],v[j/2]); j=j/2; } if(j==1) { v[j]=temp; } } } void Heap::display() { for(int i=1;i<length;i++) { cout<<v[i]<<"\t"; } cout<<endl; } int main() { vector

问题 #include<bits/stdc++.h> using namespace std; class Heap { vector <int> v; int length; public: void create(vector <int> v, int s); void display(); }; void Heap::create(vector <int> v, int s) { length=s+1; for(int i=1;i<=s;i++) { this->v[i]=v[i-1]; } int temp; int j; for(int i=2;i<length;i++) { temp=v[i]; j=i; while(j>1&&temp>v[j/2]) { swap(v[j],v[j/2]); j=j/2; } if(j==1) { v[j]=temp; } } } void Heap::display() { for(int i=1;i<length;i++) { cout<<v[i]<<"\t"; } cout<<endl; } int main() { vector

问题 #include<bits/stdc++.h> using namespace std; class Heap { vector <int> v; int length; public: void create(vector <int> v, int s); void display(); }; void Heap::create(vector <int> v, int s) { length=s+1; for(int i=1;i<=s;i++) { this->v[i]=v[i-1]; } int temp; int j; for(int i=2;i<length;i++) { temp=v[i]; j=i; while(j>1&&temp>v[j/2]) { swap(v[j],v[j/2]); j=j/2; } if(j==1) { v[j]=temp; } } } void Heap::display() { for(int i=1;i<length;i++) { cout<<v[i]<<"\t"; } cout<<endl; } int main() { vector

问题 I'm working in Visual Studio 2017. In my current solution, I have 2 active projects. The 2nd project depends on the 1st project and my 2nd project is my startup application. When I run or compile my 2nd project, there is already a compiled executable of my 1st project that is within my solutions directory... Here is the directory hierarchy of my solutions - projects: "SolutionName/Project1/" This contains the source code for Project1 "SolutionName/Project2/" This contains the source code for

问题 template<typename...T> void func(T...args){ } int main(){ func(1,2.0,'c'); } Consider the above code, there's a rule that applied to it to deduce these template arguments for this function template (call). It is: temp.deduct.call#1 For a function parameter pack that occurs at the end of the parameter-declaration-list, deduction is performed for each remaining argument of the call, taking the type P of the declarator-id of the function parameter pack as the corresponding function template

问题 template<typename...T> void func(T...args){ } int main(){ func(1,2.0,'c'); } Consider the above code, there's a rule that applied to it to deduce these template arguments for this function template (call). It is: temp.deduct.call#1 For a function parameter pack that occurs at the end of the parameter-declaration-list, deduction is performed for each remaining argument of the call, taking the type P of the declarator-id of the function parameter pack as the corresponding function template

问题 template<typename...T> void func(T...args){ } int main(){ func(1,2.0,'c'); } Consider the above code, there's a rule that applied to it to deduce these template arguments for this function template (call). It is: temp.deduct.call#1 For a function parameter pack that occurs at the end of the parameter-declaration-list, deduction is performed for each remaining argument of the call, taking the type P of the declarator-id of the function parameter pack as the corresponding function template