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Implicit typecasting not working if passing integer value as argument in java

。_饼干妹妹 提交于 2019-12-12 02:15:34
问题 In the following code , implicit typecasting for an integer value 9 take place and assigned to variable of byte datatype which is of size 8 bits. class Demo1 { public static void main(String args[]) { byte b=9; System.out.println(b); } } The code happily compiled and executed . but when i wrote the following code it gave me compilation error class Demo2 { void func1(byte b) { System.out.println(b); } public static void main(String[] args) { Demo2 d1=new Demo2(); d1.func1(9); } } please

Calculate size in Hex Bytes

蹲街弑〆低调 提交于 2019-12-12 01:53:26
问题 what is the proper way to calculate the size in hex bytes of a code segment. I am given: IP = 0848 CS = 1488 DS = 1808 SS = 1C80 ES = 1F88 The practice exercise I am working on asks what is the size (in hex bytes) of the code segment and gives these choices: A. 3800 B. 1488 C. 0830 D. 0380 E. none of the above The correct answer is A. 3800, but I haven't a clue as to how to calculate this. 回答1: How to calculate the length: Note CS. Find the segment register that's nearest to it, but greater.

How to convert byte string with non-printable chars to hexadecimal in python? [duplicate]

﹥>﹥吖頭↗ 提交于 2019-12-12 01:42:16
问题 This question already has answers here : What's the correct way to convert bytes to a hex string in Python 3? (9 answers) Closed 3 years ago . I have an ANSI string Ď–ór˙rXüď\ő‡íQl7 and I need to convert it to hexadecimal like this: 06cf96f30a7258fcef5cf587ed51156c37 (converted with XVI32). The problem is that Python cannot encode all characters correctly (some of them are incorrectly displayed even here, on Stack Overflow) so I have to deal with them with a byte string. So the above string

C++: a scalable number class - bitset<1>* or unsigned char*

試著忘記壹切 提交于 2019-12-12 01:06:53
问题 I'm planning on creating a number class. The purpose is to hold any amount of numbers without worrying about getting too much (like with int, or long). But at the same time not USING too much. For example: If I have data that only really needs 1-10, I don't need a int (4 bytes), a short(2 bytes) or even a char(1 byte). So why allocate so much? If i want to hold data that requires an extremely large amount (only integers in this scenario) like past the billions, I cannot. My goal is to create

Encryption in Java while Decryption method is known

断了今生、忘了曾经 提交于 2019-12-12 00:48:47
问题 I try to make encryption and decryption mechanism in Java. I have found some code for decrypting but I don't know how to encrypt. What encryption method will be compatible with decryption method like this: private byte[] padKey(byte[] key) { byte[] paddedKey = new byte[32]; System.arraycopy(key, 0, paddedKey, 0, key.length); return paddedKey; } private byte[] unpad(byte[] data) { byte[] unpaddedData = new byte[data.length - data[data.length - 1]]; System.arraycopy(data, 0, unpaddedData, 0,

Writing multiple variable types to a text file using ofstream

随声附和 提交于 2019-12-11 23:35:48
问题 I just want to write a simple text file: ofstream test; test.clear(); test.open("test.txt",ios::out); float var = 132.26; BYTE var2[2]; var2[0] = 45; var2[1] = 55; test << var << (BYTE)var2[0] << (BYTE)var2[1]; test.close(); But in the output file I get: 132.26-7 I don't get what the problem is... 回答1: BYTE is nothing but an alias for unsigned char. By default, when you output a char in a stream, it is converted to its ASCII character. In the ASCII table, the character 45 is '-' and the

Fast way to swap endianness using opencl

末鹿安然 提交于 2019-12-11 19:44:53
问题 I'm reading and writing lots of FITS and DNG images which may contain data of an endianness different from my platform and/or opencl device. Currently I swap the byte order in the host's memory if necessary which is very slow and requires an extra step. Is there a fast way to pass a buffer of int/float/short having wrong endianess to an opencl-kernel? Using an extra kernel run just for fixing the endianess would be ok; using some overheadless auto-fixing-read/-write operation would be perfect

Convert the bytes of byte array to bits and store in Integer array

馋奶兔 提交于 2019-12-11 19:34:01
问题 I have bytes in a byte array. I need to store the bit value of each byte in an integer array . For example , the byte array is byte HexToBin[] = {(byte)0x9A, (byte)0xFF,(byte) 0x05,(byte) 0x16}; then the integer array should have a = [10011010111111110000010100010110] I have tried the following code, where i was able to print the binary value of each byte (s2) but i couldnot store in integer array allBits. byte hexToBin[] = {(byte)0x9A, (byte)0xFF,(byte) 0x05,(byte) 0x16}; int[] allBits = new

XML Invalid byte 1 of 1-byte UTF-8 sequence

。_饼干妹妹 提交于 2019-12-11 17:51:59
问题 I have a program that takes two xml files and merge into one, while I'm doing this, I managed to convert from "and " to "and ’". Not talking about why I'm doing this, here's the code snippet, removing " ’ " error no longer exist that's why I paste it here. convertedString = replace(convertedString, (String)"and ", (String)"and ’"); convertedString = replace(convertedString, (String)""", (String)"\\\""); convertedString = StringEscapeUtils.unescapeHtml(convertedString); with printDocument

C# How to extract bytes from byte array? With known starting byte

别等时光非礼了梦想. 提交于 2019-12-11 17:38:58
问题 I need to get specific bytes from a byte array. I know the content of the first byte I want and I need x bytes after that. For example, I have byte [] readbuffer { 0, 1, 2, 0x55, 3, 4, 5, 6}; byte [] results = new byte[30]; and I need the 3 bytes that appear after "0x55" byte results == {ox55aa, 3, 4, 5} I'm using: Array.copy(readbuffer, "need the index of 0x55" ,results, 0, 3); I need to find the index of 0x55 PS: 0x55 is in an aleatory position in the array. PS2: I forgot to mention before