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问题 I need to set byte value as method parameter. I have boolean variable isGenerated , that determines the logic to be executed within this method. But I can pass directly boolean as byte parameter this is not allowed and can't be cast in java. So the solution I have now looks like this: myObj.setIsVisible(isGenerated ? (byte)1 : (byte)0); But it seems odd for me. Maybe some better solution exists to do this? 回答1: your solution is correct. if you like you may avoid one cast by doing it the

问题 I have a .net 3.5 application that will be dealing with a large number of images. I need to check that the image extension is correct, the image height and width, and the PPI. I do not want to load the entire image into a .net image or bitmap, this will take to long and be to resource intensive. I can not use third party plug-ins or dlls, and of course it needs to be done yesterday. So, I am reading the initial bytes of the files, checking the "magic" numbers to make sure the image extension

问题 I need to convert numerical values into byte arrays. For example, to convert a long to a byte array, I have this method: public static byte[] longToBytes(long l) { ByteBuffer buff = ByteBuffer.allocate(8); buff.order(ByteOrder.BIG_ENDIAN); buff.putLong(l); return buff.array(); } It's pretty straightforward - take a long, allocate an array that can hold it, and throw it in there. Regardless of what the value of l is, I will get an 8 byte array back that I can then process and use as intended.

问题 I have 2 bytes: byte b1 = 0x5a; byte b2 = 0x25; How do I get 0x5a25 ? 回答1: It can be done using bitwise operators '<<' and '|' public int Combine(byte b1, byte b2) { int combined = b1 << 8 | b2; return combined; } Usage example: [Test] public void Test() { byte b1 = 0x5a; byte b2 = 0x25; var combine = Combine(b1, b2); Assert.That(combine, Is.EqualTo(0x5a25)); } 回答2: Using bit operators: (b1 << 8) | b2 or just as effective (b1 << 8) + b2 回答3: A more explicit solution (also one that might be

问题 I want to store a 64bit (8 byte) big integer to a nodejs buffer object in big endian format. The problem about this task is that nodejs buffer only supports writing 32bit integers as maximum (with buf.write32UInt32BE(value, offset)). So I thought, why can't we just split the 64bit integer? var buf = new Buffer(8); buf.fill(0) // clear all bytes of the buffer console.log(buf); // outputs <Buffer 00 00 00 00 00 00 00 00> var int = 0xffff; // as dezimal: 65535 buf.write32UInt32BE(0xff, 4); //

问题 Is there an easy way to bit-reflect a byte variable in Delphi so that the most significant bit (MSB) gets the least significant bit (LSB) and vice versa? 回答1: In code you can do it like this: function ReverseBits(b: Byte): Byte; var i: Integer; begin Result := 0; for i := 1 to 8 do begin Result := (Result shl 1) or (b and 1); b := b shr 1; end; end; But a lookup table would be much more efficient, and only consume 256 bytes of memory. function ReverseBits(b: Byte): Byte; inline; const Table:

问题 I have a ByteBuffer that can hold a maximum of (4 + size ) bytes (that is, an integer followed by size characters). However, the number of characters written to the ByteBuffer , may be smaller than size . So I was wondering, is there anyway to determine how many characters were written to the ByteBuffer and not just the total size of it? limit , position and such don't SEEM to be what I am after. Thanks for your help! 回答1: After you've written to the ByteBuffer, the number of bytes you've

问题 I am trying to convert an int into three bytes representing that int (big endian). I'm sure it has something to do with bit-wise and and bit shifting. But I have no idea how to go about doing it. For example: int myInt; // some code byte b1, b2 , b3; // b1 is most significant, then b2 then b3. *Note, I am aware that an int is 4 bytes and the three bytes have a chance of over/underflowing. 回答1: To get the least significant byte: b3 = myInt & 0xFF; The 2nd least significant byte: b2 = (myInt >>

问题 I'm trying to develop a tool that read a binary file, makes some changes and save it. What I'm trying to do is make a list of each line in the file, work with several lines and then join the list again. This is what I tried: file = open('myFile.exe', 'r+b') aList = [] for line in f: aList.append(line) #Here im going to mutate some lines. new_file = ''.join(aList) and give me this error: TypeError: sequence item 0: expected str instance, bytes found which makes sense because I'm working with

问题 I'm trying to simply convert a byte received from fget into binary. I know the value of the first byte was 49 based on printing the value. I now need to convert this into its binary value. unsigned char byte = 49;// Read from file unsigned char mask = 1; // Bit mask unsigned char bits[8]; // Extract the bits for (int i = 0; i < 8; i++) { // Mask each bit in the byte and store it bits[i] = byte & (mask << i); } // For debug purposes, lets print the received data for (int i = 0; i < 8; i++) {