byte

问题 I have already wrote a program to this , bits working only if bit array length is multiples of 8 . Can some one help me to get bit array of 5 bits converted into byte both functions work only when it have bit array in multiple of 8 . public static byte[] BitArrayToByteArray(BitArray bits) { byte[] ret = new byte[bits.Length / 8]; bits.CopyTo(ret, 0); return ret; } public static byte[] ToByteArray(this BitArray bits) { int numBytes = bits.Count / 8; if (bits.Count % 8 != 0) numBytes++; byte[]

问题 I want to send iPhone image to server database. I wrote following code. I am getting data mismatch exception and not able to resolve it. Could anyone please help me out. Code on iPhone side: - (void) uploadUserInfo:(NSString*)userId profilePic:(UIImage*)profilePic { __block ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL: [NSURL URLWithString:[NSString stringWithFormat:@"%@/%d/uploadUserInfo?cultureDetect=false", dataUrl, currentAppID]]]; [request setPostValue:userId forKey:

问题 In Python, I am aware certain methods exist in python 3 that can create a new integer from an existing byte array. However, I am looking for a way to create a reference to a byte array, as an integer. Such that, if the reference is changed, then the underlying byte array is also changed. In C, this would be done like the following: int main(void) { unsigned char bytes[4] = {1, 0, 0, 0}; int* int_ref = (int*)bytes; *int_ref += 59; printf("bytes is now %u %u %u %u\n", bytes[0], bytes[1], bytes

问题 Hey Friends, I'm trying to implement a java "hash" function in ruby. Here's the java side: import java.nio.charset.Charset; import java.security.MessageDigest; /** * @return most significant 8 bytes of the MD5 hash of the string, as a long */ protected long hash(String value) { byte[] md5hash; md5hash = md5Digest.digest(value.getBytes(Charset.forName("UTF8"))); long hash = 0L; for (int i = 0; i < 8; i++) { hash = hash << 8 | md5hash[i] & 0x00000000000000FFL; } return hash; } So far, my best

问题 I want to create a byte using an integer. For example I have an integer of 4, I want to create a byte with a value of 4. When I do something like byte test = 134; I get an byte value of -122 wheras I want a byte value of simply 134 so that i can convert this to ascii later on. I am unsure of how to achieve this but would welcome any help that can be provided. Thanks. 回答1: In Java byte s are interpreted as signed (along with int s, short s, and long s). The unsigned byte value of 134 is bit

问题 I'm attempting to use ReadProcessMemory to read a dynamic amount of bytes into an array and then return it. I simply can't get it to work properly. My current code is... byte *Application::readMemory(DWORD address, int length) { byte *buffer = new byte[length]; SIZE_T bytesRead; ReadProcessMemory(piProcessInfo.hProcess, (void *)address, &buffer, length, &bytesRead); return buffer; } Any help would be appreciated. 回答1: Shouldn't it be ReadProcessMemory(piProcessInfo.hProcess, (void *)address,

问题 By following exactly this question and the solution as well, I still cannot solve the problem. I still get " Data too long for column 'id' at row 1" public static byte[] asBytes(UUID uuid) { ByteBuffer bb = ByteBuffer.wrap(new byte[16]); bb.putLong(uuid.getMostSignificantBits()); bb.putLong(uuid.getLeastSignificantBits()); return bb.array(); } UUID id= UUID.randomUUID(); InsertQueryBuilder runner = new InsertQueryBuilder("test_table") .addField("id", asBytes(id)); return getConnection()

问题 I have two values v1 and v2 of types T1 and T2 respectively, with sizeof(T1)>sizeof(T2). Both types are plain-old-data. Now, I want to replace the k'th, k+1'th, ... k+sizeof(T2)-1'th bytes of v1 with the bytes of v2. C++ doesn't offer this functionality inherently in the language, nor to my knowledge in the standard library (at least, not directly). What would be the best approach to implementing this generically? i.e. implementing: template<typename T1, typename T2> void replace_bytes(T1& v1

问题 What I am trying to do is get input from the user and store it in a byte array. Please note, I must store var1 variable in a byte array and not a list. Console.Write("Enter a number: "); byte var1 = byte.Parse(Console.ReadLine()); byte[] byteArray = new byte[] {}; byteArray[0] = var1; 回答1: Arrays are fixed in size, you must specifiy the size of the array when you create it. In your example you told it to make an array of size 0 by putting the {} after the byte[] . Instead remove the {} and

问题 I use net-snmp-5.5-1.x86.exe for Win32 I need set IP addreess to hex format, separated by whitespace using NET-SNMP set command. For example, an IP address 192.168.100.100 converted to Hex format is 0xC0A86464 192.168.100.100 > 0xC0A86464 The correctly set value should return the following value when check with snmpget: xxx-xxx-xxx-MIB::docsDevServerAddress.0 = Hex-STRING: C0 A8 64 64 I tried snmpset -v 1 -c private 192.168.100.5 docsDevServerAddress.0 x 0xC0 A8 64 64 But when I using this