buttonclick

How to launch another aspx web page upon button click?

由 て烟熏妆下的殇ゞ 提交于 2019-11-28 09:12:33
I have an asp.net application, where the user would click a button and launch another page (within the same application). The issue I am facing is that the original page and the newly launched page should both be launched. I tried response.redirect, but that tends to unload the original page. Any suggestions? This button post to the current page while at the same time opens OtherPage.aspx in a new browser window. I think this is what you mean with ...the original page and the newly launched page should both be launched. <asp:Button ID="myBtn" runat="server" Text="Click me" onclick="myBtn_Click

Button Onclick Listener in included layouts

由 最后都变了- 提交于 2019-11-28 07:27:12
I come to you on bended knee, question in hand. I am relatively new to Android, so pardon any sacrilegious things I might say. Intro: I have several layouts in the app, that all have to include a common footer. This footer has some essential buttons for returning to the home page, logging out, etc. I managed to get this footer to appear in all the requisite pages with the help of the Include and Merge tags. The issue lies in defining on click listeners for all the buttons. Although I can define the listeners in every activity associated with screens that include the footer layout, I find that

Click event for button in loop C# WPF

由 别说谁变了你拦得住时间么 提交于 2019-11-28 05:07:06
问题 I have couple buttons which im putting in wrapPanel in loop: for (int i = 0; i < wrapWidthItems; i++) { for (int j = 0; j < wrapHeightItems; j++) { Button bnt = new Button(); bnt.Width = 50; bnt.Height = 50; bnt.Content = "Button" + i + j; bnt.Name = "Button" + i + j; bnt.Click += method here ? wrapPanelCategoryButtons.Children.Add(bnt); } } I want to know which button was clicked and do something different for each of them. For example ill have method private void buttonClicked(Button b)

how do i open contacts when i click a button defined in main.xml

由 蹲街弑〆低调 提交于 2019-11-27 15:10:28
问题 I am developing a gps tracking app in android. I am done with displaying the map n stuff. Now I want to make a button on top which when clicked would display the contacts, Then when I select the contact it should show me his or her location. Please help me with this. Thank you. 回答1: You can set an Event on Button click by setting an OnClickListener on the Button with the following code, and use Intent to call ContactPicker activity: button.setOnClickListener(new OnClickListener() { @Override

Change DialogFragment enter/exit transition at just before dismissing

由 谁说胖子不能爱 提交于 2019-11-27 10:46:05
问题 I have a DialogFragment and i set animation for enter/exit in the onActivityCreated method as below @Override public void onActivityCreated(Bundle arg0) { super.onActivityCreated(arg0); getDialog().getWindow() .getAttributes().windowAnimations = R.style.DialogAnimation; } my DialogAnimation style files is as follows <style name="DialogAnimation"> <item name="android:windowEnterAnimation">@android:anim/fade_in</item> <item name="android:windowExitAnimation">@android:anim/fade_out</item> <

How to make a button redirect to another page using jQuery or just Javascript

由 只谈情不闲聊 提交于 2019-11-27 09:16:57
问题 I am making a prototype and I want the search button to link to a sample search results page. How do I make a button redirect to another page when it is clicked using jQuery. 回答1: Without script: <form action="where-you-want-to-go"><input type="submit"></form> Better yet, since you are just going somewhere, present the user with the standard interface for "just going somewhere": <a href="where-you-want-to-go">ta da</a> Although, the context sounds like "Simulate a normal search where the user

How to launch another aspx web page upon button click?

由 寵の児 提交于 2019-11-27 05:50:12
问题 I have an asp.net application, where the user would click a button and launch another page (within the same application). The issue I am facing is that the original page and the newly launched page should both be launched. I tried response.redirect, but that tends to unload the original page. Any suggestions? 回答1: This button post to the current page while at the same time opens OtherPage.aspx in a new browser window. I think this is what you mean with ...the original page and the newly

How to capture button click event of webpage (opened inside WebBrowser Control) in WPF form?

由 风流意气都作罢 提交于 2019-11-27 03:36:26
问题 Consider a scenario where I have a WebBrowser Control in WPF application. A web page is loaded inside WebBrowser Control. The web page contains a button. The web page is of ASP.NET application. I want to capture the button click event of the webpage into WPF Form (which hosts WebBrowser Control). Is there any way to achieve this functionality ? Thanks, Tapan 回答1: Here is code that should do exactly what you want with comments to explain what is going on: public partial class MainWindow :

Get listview item position on button click

由 巧了我就是萌 提交于 2019-11-26 20:24:06
This is my listview click event: lv1.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> a, View v, int position, long id) { Object o = lv1.getItemAtPosition(position); ItemDetails obj_itemDetails = (ItemDetails)o; Toast.makeText(ListViewImagesActivity.this, "You have chosen : " + " " + obj_itemDetails.getName(), Toast.LENGTH_LONG).show(); } }); And this is my button click event: btnNxt = (Button) findViewById(R.id.btnNext); btnNxt.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { //Here I need to get that

Get listview item position on button click

由 时光毁灭记忆、已成空白 提交于 2019-11-26 08:53:26
问题 This is my listview click event: lv1.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> a, View v, int position, long id) { Object o = lv1.getItemAtPosition(position); ItemDetails obj_itemDetails = (ItemDetails)o; Toast.makeText(ListViewImagesActivity.this, \"You have chosen : \" + \" \" + obj_itemDetails.getName(), Toast.LENGTH_LONG).show(); } }); And this is my button click event: btnNxt = (Button) findViewById(R.id.btnNext); btnNxt
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