broadcastreceiver

问题 I have a receiver class listening on several actions but it can not catch the android.intent.action.BOOT_COMPLETED action. What I am doing wrong? here is my manifest file: <uses-sdk android:minSdkVersion="7" /> <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> <!--<receiver android:name=".OtherReceiver"> <intent-filter> <action android:name="android.intent.action.BOOT_COMPLETED" /> </intent-filter> </receiver>--> <receiver android:name="com.myApp.AppReceiver"

问题 I would like my app to be informed when a headset/headphones is disconnected from an iOS device after a period of idle time long enough for the app to have been cleaned up (and thus might not be running) similar to how a BroadcastReceiver works in android. I suspect it's not possible but would appreciate any ideas. I have looked into local and push notifications and the NSNotificationCenter. Push notifications aren't appropriate because events happen on the device. It only seems possible to

问题 We can remove an ordered broadcast with abortBroadcast() , is there a way to completely remove a sticky ordered broadcast ? 回答1: removeStickyBroadcast is exactly what you need: public abstract void removeStickyBroadcast (Intent intent) Since : API Level 1 Remove the data previously sent with sendStickyBroadcast(Intent) , so that it is as if the sticky broadcast had never happened. You must hold the BROADCAST_STICKY permission in order to use this API. If you do not hold that permission,

问题 I have a flashlight app with a widget. The widget is used to turn the flashlight on and off and does not display main activity or anything. After a few hours, however, the widget does nothing. I mean if you click it, nothing happens. I have two classes to accomplish this a Provider and a Receiver . Provider: public class WidgetProvider extends AppWidgetProvider { @ Override public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) { Intent receiver = new

问题 I hope to find some help here because I'm not familiar with BroadcastReceivers in Android. This piece of code opens a WebView redirect you to a login page and receives the login token once a URL change is detected. After that, the Activity is closed. @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_login); mLoginWebView = (WebView) findViewById(R.id.webview_login); redirectUrl = getString(R.string.app_redirect

问题 I am missing something here and I hope someone can help me out. I am setting up an alarm using the following: AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE); Intent broadcast_intent = new Intent(this, AlarmBroadcastReceiver.class); PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, broadcast_intent, 0); broadcast_intent.putExtra("test", "ValueReceived"); //data to pass Date date = someVariable.getDateTime(); long triggerAtTime = date.getTime();

问题 I am getting this exception in my below given code. i don't have any idea what is wrong with this code. Please help me out to get rid of this exception. 05-23 23:33:49.853: E/BroadcastReceiver(26895): BroadcastReceiver trying to return result during a non-ordered broadcast 05-23 23:33:49.853: E/BroadcastReceiver(26895): java.lang.RuntimeException: BroadcastReceiver trying to return result during a non-ordered broadcast 05-23 23:33:49.853: E/BroadcastReceiver(26895): at android.content

问题 Is there a way to broadcast data from one widget to other widgets? Similar to a BroadcastReceiver on Android or NSNotificationCenter on iOS. Specifically, I'm trying to detect when a Navigator pops or pushes a new view. I added navigatorObservers to MaterialApp. And when a widget comes back to the foreground, I want to be able to notify it by broadcasting changes from didPush and didPop with the actual route that's in the current foreground 回答1: Navigator.push returns a Future that will

问题 i am new to Android and trying to understand the communication between apps. I am trying to write 3 little apps which can communicate with each other. If you want to sent a message to everybody you just use an implicit broadcast. implicit Intent intent.setAction("com.example.myChatMessage") if you want to adress only 1 specifc receiver i did it with explicite Intent intent.setComponent("com.example.test.android.broadcastreceiver.b", "com.example.test.android.broadcastreceiver.b

问题 I have a broadcast receiver and I am trying to show a toast message from it, is this possible ? This code doesn't show the toast but it print the log message in the logcat. Is there some idiotic thing I am doing or what is my problem ? @Override public void onReceive(Context context, Intent intent) { Log.v("log", "this is shown"); Toast.makeText(context, "this is not shown" , Toast.LENGTH_LONG); } 回答1: Call the show() method for the Toast . 回答2: you forgot to call show() on the Toast ..