boxing

Will Boxing and Unboxing happen in Array?

若如初见. 提交于 2019-11-29 13:13:13
I'm new to programming, As per MSDN , Boxing is the process of converting a value type to the type object or to any interface type implemented by this value type. When the CLR boxes a value type, it wraps the value inside a System.Object and stores it on the managed heap. Unboxing extracts the value type from the object. Boxing is implicit; unboxing is explicit. I knew We can store any objects in an arraylist, because system.object is a base for all all types. Boxing and unboxing happens in array list. I agree with that. Will boxing and unboxing happens in an array? Because We can create

How does the mechanism behind the creation of boxed traits work?

这一生的挚爱 提交于 2019-11-29 10:57:49
I'm having trouble understanding how values of boxed traits come into existence. Consider the following code: trait Fooer { fn foo(&self); } impl Fooer for i32 { fn foo(&self) { println!("Fooer on i32!"); } } fn main() { let a = Box::new(32); // works, creates a Box<i32> let b = Box::<i32>::new(32); // works, creates a Box<i32> let c = Box::<Fooer>::new(32); // doesn't work let d: Box<Fooer> = Box::new(32); // works, creates a Box<Fooer> let e: Box<Fooer> = Box::<i32>::new(32); // works, creates a Box<Fooer> } Obviously, variant a and b work, trivially. However, variant c does not, probably

Comparing primitive to wrapper object with == behaviour unexplained

只谈情不闲聊 提交于 2019-11-29 10:53:45
问题 I have a piece of code which I need to understand: public static void main(String[] args) { Character c = new Character('a'); Character cy = new Character('a'); char cx = 'a'; System.out.println(c == cx); System.out.println(cx == cy); System.out.println(c == cy); } Output: true true false I am unable to understand why only the third statement is failing. EDIT: This question is different to the .equals vs == question as this about primitive versus object comparison. 回答1: c and cy refer to

Reference equality of value types

不打扰是莪最后的温柔 提交于 2019-11-29 10:47:59
问题 I have made some ref keyword tests and there is one think I can't understand: static void Test(ref int a, ref int b) { Console.WriteLine(Int32.ReferenceEquals(a,b)); } static void Main(string[] args) { int a = 4; Test(ref a, ref a); Console.ReadLine(); } Why does this code display False ? I know that int is a value type but here it should pass references to the same object. 回答1: Why does this code display False ? Because int a and int b are being boxed when you call object.ReferenceEquals.

When does a using-statement box its argument, when it's a struct?

一笑奈何 提交于 2019-11-29 04:40:13
I have some questions about the following code: using System; namespace ConsoleApplication2 { public struct Disposable : IDisposable { public void Dispose() { } } class Program { static void Main(string[] args) { using (Test()) { } } static Disposable Test() { return new Disposable(); } } } My questions are: Will the using-statement that operates on the Disposable struct, returned from Test() box the struct, or not? How can I find the answer myself? To try to find out myself, I inspected the IL produced by the above code, and here's the IL for the Main(...) method: .method private hidebysig

boxing and unboxing in int and string

左心房为你撑大大i 提交于 2019-11-29 04:22:27
I am little bit confused in boxing and unboxing. According to its definition Boxing is implicit conversion of ValueTypes to Reference Types (Object). UnBoxing is explicit conversion of Reference Types (Object) to its equivalent ValueTypes. the best example for describing this is int i = 123; object o = i; // boxing and o = 123; i = (int)o; // unboxing But my question is that whether int is value type and string is reference type so int i = 123; string s = i.ToString(); and s = "123"; i = (int)s; Is this an example of boxing and unboxing or not??? Calling ToString is not boxing. It creates a

Is there a built-in Java method to box an array?

不羁岁月 提交于 2019-11-29 02:58:33
Is there a standard method I can use in place of this custom method? public static Byte[] box(byte[] byteArray) { Byte[] box = new Byte[byteArray.length]; for (int i = 0; i < box.length; i++) { box[i] = byteArray[i]; } return box; } Joachim Sauer No, there is no such method in the JDK. As it's often the case, however, Apache Commons Lang provides such a method . Enter Java 8, and you can do following (boxing): int [] ints = ... Integer[] boxedInts = IntStream.of(ints).boxed().toArray(Integer[]::new); However, this only works for int[] , long[] , and double[] . This will not work for byte[] .

Why does calling an explicit interface implementation on a value type cause it to be boxed?

╄→гoц情女王★ 提交于 2019-11-29 00:40:32
问题 My question is somewhat related to this one: How does a generic constraint prevent boxing of a value type with an implicitly implemented interface?, but different because it shouldn't need a constraint to do this because it's not generic at all. I have the code interface I { void F(); } struct C : I { void I.F() {} } static class P { static void Main() { C x; ((I)x).F(); } } The main method compiles to this: IL_0000: ldloc.0 IL_0001: box C IL_0006: callvirt instance void I::F() IL_000b: ret

####关于Arrays.asList(T)这个API

久未见 提交于 2019-11-28 20:29:23
####关于Arrays.asList(T)这个API 参考: https://docs.oracle.com/javase/tutorial/java/generics/why.html https://docs.oracle.com/javase/tutorial/java/data/autoboxing.html 所以会研究这个问题,是因为在写代码的时候遇到了这个,很反直觉. 同样都是{120,130}竟然返回了不同的类型. public static void main(String[] args) { Integer[] pangs = {120, 130}; int[] fats = {120, 130}; List<Integer> pangList = Arrays.asList(pangs); List<int[]> fatsList = Arrays.asList(fats); } Auto boxing is the automatic conversion that the Java compiler makes, between the primitive types and their corresponding object wrapper classes . Generic Types A generic type is a generic

How does a generic constraint prevent boxing of a value type with an implicitly implemented interface?

♀尐吖头ヾ 提交于 2019-11-28 19:41:28
My question is somewhat related to this one: Explicitly implemented interface and generic constraint . My question, however, is how the compiler enables a generic constraint to eliminate the need for boxing a value type that explicitly implements an interface. I guess my question boils down to two parts: What is going on with the behind-the-scenes CLR implementation that requires a value type to be boxed when accessing an explicitly implemented interface member, and What happens with a generic constraint that removes this requirement? Some example code: internal struct TestStruct : IEquatable