boolean-logic

问题 please help me with simplifying this one. I am a bit new to these.. (A'BC') + (A'B'C) + (A'BC) + (AB'C) the book i use shows and answer, which is, Answer = A'B + B'C I tried simplifying, but I get stucked with two eXors, my simplification so far goes like this... (A'BC') + (A'B'C) + (A'BC) + (AB'C) A (BC' + B'C) + C (A'B + AB') This doesn't seem to be a write way, Please someone help me simplify this, and please show step by step, as I am sort of new.. Also I don't get how to simplify eXor

问题 My java program will allow the content of a csv file to be filtered based on a user defined logical operation. Data will be read from the content of two column csv file left right 5 10 2 6 and user will provide a logical condition operation on the command line referencing left and right. The program should filter to content of the csv files based on the outcome of the logical operation. IF ((left < right) AND (left !=10)) THEN 5 ELSE right I plan to represent the operation types as an enum

问题 I have this function that runs after a multiselect element is changed that sets an error message visibility: getVisibility(multiselect) { if ((multiselect.selectedCategories.length < 1 && !multiselect.allSelected) && this.submitted) { return 'visible' } else { return 'hidden' } } However in this line: if ((multiselect.selectedCategories.length < 1 && !multiselect.allSelected) && this.submitted) multiselect.allSelected is false, but !multiselect.allSelected is also false. picture1: picture2:

问题 I have written an if else condition which makes use of if not(!) to throw an error. However, the condition does not behave how I had expected and the error gets thrown regardless of who is the currentUser: public void findCorrectUserRole() { if (Book.name.equals("Test Answers")) { User currentUser = User.getCurrentUser() if (currentUser) { if (!currentUser.hasUserRole("Teacher") || !currentUser.hasUserRole("System Administrator")) { throw new LCEX("Sorry, only a teacher or System

问题 I was reading someone else's code and he had something like this: return val1 and val2 I tried this in the Python interpreter and it gave me the latter value on AND while OR gives me the prior value. So my question is what exactly is happening in that statement? Thanks. 回答1: An expression using and or or short-circuits when it can determine that the expression will not evaluate to True or False based on the first operand, and returns the last evaluated value: >>> 0 and 'string' 0 >>> 1 and

问题 I have an interesting question about the way PHP evaluates boolean expressions. When you have, for example, $expression = $expression1 and $expression2; or if ($expression1 and $expression2) PHP first checks if $expression1 evaluates to true . If this is not the case, then $expression2 is simply skipped to avoid unnecessary calculations. In a script I am writing, I have: if ($validator->valid("title") and $validator->valid("text")) I need to have the second statement ( $validator->valid("text

问题 I'm trying to draw a Venn diagram from a given boolean equation e.g (a AND b) AND c I want to do this on an android phone so I need to find a way to do it using Java. I found a perfect widget that does everything I am looking for in this Boolean Algebra Calculator They create perfect diagrams, I am sure it's not using Java and neither could I see their logic. I would appreciate any API, algorithm or guidance. 回答1: It uses a WolframAlpha widget to generate the Venn diagram. Luckily for you,

问题 From a sequence of TRUEs and falses, I wanted to make a function that returns TRUE whether there is a series of at least n1 TRUEs somewhere in the sequence. Here is that function: fun_1 = function(TFvec, n1){ nbT = 0 solution = -1 for (i in 1:length(x)){ if (x[i]){ nbT = nbT + 1 if (nbT == n1){ return(T) break } } else { nbT = 0 } } return (F) } Test: x = c(T,F,T,T,F,F,T,T,T,F,F,T,F,F) fun_1(x,3) # TRUE fun_1(x,4) # FALSE Then, I needed a function that returns TRUE if in a given list boolean

问题 I am working on code which creates a list and then applies both the "or" and "and" conditions to do further action: a= ["john", "carlos", "22", "70"] if (("qjohn" or "carlos") in a) and (("272" or "70") in a): print "true" else: print "not true" output: not true when I do this: a= ["john", "carlos", "22", "70"] if ("qjohn" or "cdarlos" in a) and ("272" or "d70" in a): print "true" else: print "not true" output is "true" What I am not getting is **carlos and 70** should be equal to true but it

问题 I'm trying to make a Z3 program (in Python) that generates boolean circuits that do certain tasks (e.g. adding two n-bit numbers) but the performance is terrible to the point where a brute-force search of the entire solution space would be faster. This is my first time using Z3 so I could be doing something that impacts my performance, but my code seems fine. The following is copied from my code here: from z3 import * BITLEN = 1 # Number of bits in input STEPS = 1 # How many steps to take (e