bitwise-operators

How to find whether a number is odd or even, without using if condition or ternary operators in Java? This question is given by my teacher. He also give me a hint that it is possible by using a bitwise operator. Pshemo There are few ways to not use if and get behavior that will be same as if if was used, like ternary operator condition ? valueIfTrue : valueIfFalse or switch/case . But to be tricky you can also use arrays and try to figure some transformation of our value to proper array index. In this case your code could look like int number = 13; String[] trick = { "even", "odd" }; System

I have a field of type BIT in my MySQL table. I want to store statuses of the record using bit value, for example: 1 = status1 2 = status2 4 = status3 8 = status4 Each record can have many statuses at once. For status1 and status3 the value will be 1 + 4 = 5. I can query table for all records with status3 using: SELECT * FROM `table` WHERE `statuses` & 4 I have index on statuses , but EXPLAIN tells that no index is used. Can I use index in such situation? P.S. Using separate many-to-many linking table is more normalized solution, but I'd like to have more 'flat' structure for this. It would be

I need to shift a __m128i variable, (say v), by m bits, in such a way that bits move through all of the variable (So, the resulting variable represents v*2^m). What is the best way to do this?! Note that _mm_slli_epi64 shifts v0 and v1 seperately: r0 := v0 << count r1 := v1 << count so the last bits of v0 missed, but I want to move those bits to r1. Edit: I looking for a code, faster than this (m<64): r0 = v0 << m; r1 = v0 >> (64-m); r1 ^= v1 << m; r2 = v1 >> (64-m); For compile-time constant shift counts, you can get fairly good results. Otherwise not really. This is just an SSE

I would like first to convert a number to binary, then invert it bitwise. Like this: Number is 793 = 1100011001 then convert the binary value into: 0011100110 In JavaScript I can do the following: var x = 793; document.write(x.toString(2)); // gives 0011100110 This will give me the binary value of the number. But how do I invert the binary bitwise? I tried the ~ operator, but not working probably... The output is: -1100011010 MooGoo's answer is correct. Here is some information about what is happening.... Lets assume this is a 64 bit integer. 793 = 1100011001 ~793 = -794 =