bitset

问题 How can I initialize a boost::dynamic_bitset from std::bitset ? The simplest solution is a for loop: for(int i=0;i<bitset_size;i++) my_dynamic_bitset[i] = my_bitset[i]; Is there any shorter or faster way to do this? 来源： https://stackoverflow.com/questions/32326934/how-to-initialize-a-boostdynamic-bitset-from-stdbitset

问题 My assignment is to compress a DNA sequence. First enconding using a = 00 c = 01 g = 10 t = 11. I have to read in from a file the sequence and covert to my encoding. i know i have to use the bitSet class in java, but I'm having issues with how to implement. How do I ensure my encoding is used and the letters are not converted to actual binary. this is the prompt: Develop space efficient Java code for two kinds of compressed encodings of this file of data. (N's are to be ignored). Convert

问题 This question already has answers here : Floating Point to Binary Value(C++) (11 answers) Closed 4 years ago . I am working on a project of converting any real number into binary using IEEE 754 format. My first trial is using the bitset library type for conversion of the number then i can worry about dividing the whole number into sign bit, exponent and mantissa. int foo; cin >> foo; bitset<32> my_bit(foo); As it turns out, bitset will do with signed integers only. How do i include floating

问题 Hi I'm trying to read string from txt file and transform it into binary file which is bitset<12> string form. int main() { using namespace std; std::ifstream f("fruit.txt"); std::ofstream out("result.txt"); std::hash<std::string>hash_fn; int words_in_file = 0; std::string str; while (f >> str){ ++words_in_file; std::bitset<12>* bin_str = new std::bitset<12>[3000]; int temp_hash[sizeof(f)]; std::size_t str_hash = hash_fn(str); temp_hash[words_in_file] = (unsigned int)str_hash; bin_str[words_in

问题 I'm using Redis to create an algorithm for claiming unused integers from a range. My solution is based on the answer I got for this SO question. This solution uses BITPOS and BITSET , and to avoid race conditions, I also use WATCH / MULTI / EXEC . In order to test the concurrency aspects I created a bash script that concurrently attempts to find a free number 10 times in parallel, to investigate the possible outcomes of the EXEC command. What I found was that EXEC never returned null, even

问题 How to compute the memory of new BitSet(n) in C++. What memory takes the new BitSet(1024) in Java. But it seems the formula for Java is different. I want to compute the memory spent for new BitSet(100000) , could you please help? 回答1: BitSet are packed into arrays of "words." A word is (in the current implementation) a long. The single bits inside will be retrieved / set uses masking; therefore it internally packs 64 bits in one single long value, and uses an array of longs to hold all the

问题 I have a 7-byte/56-bit bitset that upon construction sets the first bit to one: boost::dynamic_bitset<> b(56, 1); After construction, I'd like to place an integer value (say 2019) into bits 4 through 15. I'm curious if there is a simple way within boost to do this without bitwise operations? Basically, I want to set a range of bits to an integer value that I know is small enough to fit into those bits. Thanks for any advice. 回答1: The boost::dynamic_bitset<> offers much less functionality. I

问题 When I am compiling this code, I always get this error. Here dna is set to char. I want the bit value in the bitset to be converted to a char and the char to a int. If this is not the right way, please guide. for (std::size_t i = 0; i < myString.size(); ++i) { std::bitset<8> y(myString[i]); dna = y.to_string<char>(); binary = dna; cout << binary << " "; while ( binary >= 10) { for(int i = 0; i <= 100; ++i) { // loops length of array a[i] = binary % 10; binary = binary / 10; } } } 回答1: y.to

问题 I have a BitSet, which needs to be converted to a Byte[]. However, by using BitSet.toByteArray(), I don't get the correct output. I have tried converting the Byte[] to its binary form in order to check whether the Bitset and the binary form of the Byte[] are similiar. public static void generate() { BitSet temp1 = new BitSet(64); for (int i = 0; i < 64; i++) { if(i % 8 != 0 && i < 23) { temp1.set(i, true); } } StringBuilder s = new StringBuilder(); for (int i = 0; i < 64; i++) { s.append

问题 I want to use a bit array in Python that I could use like the standard bitset from C++. Example: #include<bitset> int main() { std::bitset<100> numBits; } However, I don't know if there is something similar in Python, preferably built-in. 回答1: Thre is nothing built-in for that. If you need such a data structure in order to have a proper output of bytes, with the correct bits set, such as for a network protocol, a binary file structure or hardware control, sequencing a list of True and False