bitset

The Standard Library class template std::bitset<N> has a constructor (C++11 and onwards, unsigned long argument before C++11) constexpr bitset(unsigned long long) noexcept Contrary to many best-practice guidelines, this single-argument constructor is not marked as explicit . What is the rationale behind this? TemplateRex Explicit construction The main objection against an explicit constructor is that copy-initialization from unsigned integers no longer works constexpr auto N = 64; std::bitset<N> b(0xDEADC0DE); // OK, direct initialization std::bitset<N> b = 0xDEADC0DE; // ERROR, copy

Why is this program showing the following output ? #include <bitset> ... { std::bitset<8> b1(01100100); std::cout<<b1<<std::endl; std::bitset<8> b2(11111111); std::cout<<b2<<std::endl; //see, this variable //has been assigned //the value 11111111 //whereas, during //execution, it takes //the value 11000111 std::cout << "b1 & b2: " << (b1 & b2) << '\n'; std::cout << "b1 | b2: " << (b1 | b2) << '\n'; std::cout << "b1 ^ b2: " << (b1 ^ b2) << '\n'; } This is the OUTPUT: 01000000 11000111 b1 & b2: 01000000 b1 | b2: 11000111 b1 ^ b2: 10000111 First, I thought there is something wrong with the header

今天在学习Java核心技术第九章集合框架中的BitSet时，遇到了这个算法。Eratosthenes筛子算法时一个查找素数的方法，这并不是查找素数的最好方法，但是测试编译程序性能的一种流行的基准。 一、BitSet位集 　　 BitSet类用于存放一个位序列，它将位包装在字节里，比使用Boolean对象的ArrayList更加高效。 　　BitSet类的常用方法有 　　　　　BitSet(int initialCapacity) 创建一个位集，规定了它的容量。 index从0开始，长度会随需要增加。 　　　　　int length() 返回位集的而逻辑长度，即位集的最高设置位的索引 + 1. 　　　　　boolean get(int bit) 获得一个位 　　　　　void set(int bit) 设置一个位为true 　　　　　void clear(int bit) 清除一个位为false 　　　　　void and(BitSet set) 两个位集相“与” 　　　　　void or(BitSet set) 两个位集“或” 　　　　　void xorBitSet set)　两个位集“异或” 　　　　　void andNot(BitSet set)　清除这个位集中对应另一个位集中设置的位 二、Eratosthenes筛子算法 　　本算法的思想如下 　　1

In Java 8 the below code converts integer 3 to bitset and prints {0, 1} meaning the bit representation of 3 has ones at positions 0 and 1 that is 11 . System.out.println(BitSet.valueOf(new long[]{3})); I'm interested in converting a BigInteger or long with large value, say 10000000 into the corresponding BitSet and then back - having the BitSet object (bit representation) convert it to BigInteger ( long ). I'm also wondering which representation occupies more memory for various values of integer numbers? Willem Van Onsem You can use the BigInteger.toByteArray() and BitSet.toByteArray() for

How to Write a program which will take 001010101110000100100 ...., 011100010001000011000 ...., 000000000010000000000100 .... as input (bit) and the output will be OR of these 3. OR = 0 0 = 0, 0 1 = 1, 1 0 = 1, 1 1 = 1, if sombody has a sample program that would be helpful too. Do we need to store the values in bit array from byte? This should work ( update: bug fixed): public static BitSet or(final String... args){ final BitSet temp = createBitset(args[0]); for(int i = 1; i < args.length; i++){ temp.or(createBitset(args[i])); } return temp; } private static BitSet createBitset(final String

由于之前的 洛谷月赛 20191109 中我bitset不熟，直接导致了T3 \(70 \sim 100pts \rightarrow 50pts\) 。复习一下bitset。 一、概念 A bitset stores bits. 因此，bitset可以理解为一个bool数组，但是速度更快，可以直接像一个整数一样进行位运算，或者统计1的个数等。 二、声明与初始化 bitset声明，传入的变量n为bitset长度： #include <bitset> bitset <n> b; // 全为0 bitset <n> b(u); // 从unsigned long型变量u复制而来 bitset <n> b(s); // 从string对象s复制而来 bitset <n> b(s, pos, m); // 从string对象s的[pos, pos+m]复制而来 使用unsigned long初始化的几个例子： bitset<16> bitvec1(0xffff); // bits 0 ... 15 are set to 1 // bitvec2 same size as initializer bitset<32> bitvec2(0xffff); // bits 0 ... 15 are set to 1; 16 ... 31 are 0 // on a 32-bit machine,

简介 BitSet是C++中的一个类库，可以很方便的管理一系列的bit位。 我们可以用其做一个bool类型的数组。 使用方法 构造函数 bitset<len> a(string("1111")) bitset<len> b(16) //会转换为二进制 若len小于其二进制长度，从头开始取 不要传入包含其他字符(非0 1)的字符串 可用操作符 << 左移 >> 右移 == != ^ 按位异或 | 按位或 & 按位与 ~ 按位取反 可用函数 .count() 返回1的个数 .size() 返回bitset长度 .text(int i) 返回 bitset[i] == 1 ? .set() 全置为1 .set(int i) .reset() 全置为0 .reset(int i) .flip() 按位取反 .flip(int i) 来源： https://www.cnblogs.com/woxiaosade/p/11828961.html

Example NOTE: that i am only concerned about letters. so bitset 000001 would be a or A . I have a string named s with the value "abc" . I take each char of the string and convert it to binary value through the use of bitset . e.g bitset <6> b1 = s[0]; //a bitset <6> b2 = s[1]; //b bitset <6> b3 = s[2]; //c then i want to put the results into an array of strings . The name of the array is arr (and each string of the array will represent the binary value of each char ) e.g arr[0] //will hold the value of char 'a' in binary form which is 000001 arr[1] //will hold the value of char 'b' in binary