binary-search

After having searched the internet I was not able to satisfy myself that I had found a comprehensive set of situations in which a linear search would be preferable to a binary search. I am essentially wondering whether it would be possible to compile a relatively definitive list of advice (from the point of view of general programming as one might find in industry). Alternatively I would much appreciate it if it could be verified that indeed I have seen all there is to say on the subject. My list of reasons for choosing a linear search over a binary search are as follows: The list is unsorted

I am trying to tackle a classical interview problem which is basically performing a binary search on a list which first increases then decreases. Even though it's obvious that we can achieve O(log n) I couldn't figure out what is wrong the code below that I've written: #include <iostream> using namespace std; int binarySearch(int *A, int low, int high, int key) { while(low < high) { int mid = (low + high) / 2; if(key < A[mid]) { if(A[mid - 1] < A[mid] && A[mid] < A[mid + 1]) high = mid - 1; else low = mid + 1; } else if(key > A[mid]) { if(A[mid - 1] < A[mid] && A[mid] < A[mid + 1]) low = mid +

Finding the maximum or minimum value in a sequence that increases montonically and then decreases monotonically can be done in O(log n). However, if i want to check if a number exists in such a sequence, can this also be done in O(log n)? I do not think that is possible. Consider this example: 1 4 5 6 7 10 8 3 2 0. In this example, if I need to find whether the sequence contains '2', I do not have any conditions to divide the search space into half of the original search space. In the worst, case it will be O(n), as you need to check for both halves, when we are trying to search for 2. I would

It is a problem from C++ primer fifth edition problem 3.26, I don't know the difference between them ? May be the second one can avoid overflow. May be the second one can avoid overflow. Exactly. There's no guarantee that beg+end is representable; but in the second case the intermediate values, as well as the expected result, are no larger than end , so there is no danger of overflow. The second form can also be used for affine types like pointers and other random-access iterators, which can be subtracted to give a distance, but not added together. In general case the both expressions are

I am new to JAVA and Netbeans and this is what I have to do: The user can write a CD title in the input box and then remove the CD from the list by pressing the remove button. If the CD does not exist in the collection, then a message can be displayed in the outbox to state this. I have to use Collections.binarySearch() to do this. This is only a part of the whole program but I already figured out the rest of it. This is what I have done: ArrayList <String> songs = new ArrayList(); Collections.addAll(songs, "Metric - Fantasies", "\nBeatles - Abbey Road", "\nPearl Jam - Ten", "\nDoors - Alive",

Hi, what is the index of the search key if we search for 24 in the following array using binary search. array = [10,20,21,24,24,24,24,24,30,40,45] I have a doubt regarding binary search that how does it works if a array has duplicate values.Can anybody clarify... The array you proposed has the target value in the middle index, and in the most efficient implementations will return this value before the first level of recursion. This implementation would return '5' (the middle index). To understand the algorithm, just step through the code in a debugger. public class BinarySearch { public static