binary-search

Find zero points with recursion

浪子不回头ぞ 提交于 2019-12-12 10:25:32
问题 I want to find the zero points of a sine function. The parameter is a interval [a,b]. I have to it similar to binary search. Implement a function that searches for null points in the sinus function in a interval between a and b. The search-interval[lower limit, upper limit] should be halved until lower limit and upper limit are less then 0.0001 away from each other. Here is my code: public class Aufg3 { public static void main(String[] args) { System.out.println(zeropoint(5,8)); } private

How to perform a binary search of a text file

╄→尐↘猪︶ㄣ 提交于 2019-12-12 09:38:26
问题 I have a big text file (5Mb) that I use in my Android application. I create the file as a list of pre-sorted Strings, and the file doesn't change once it is created. How can I perform a binary search on the contents of this file, without reading line-by-line to find the matching String? 回答1: Since the content of the file does not change, you can break the file into multiple pieces. Say A-G, H-N, 0-T and U-Z. This allows you to check the first character and immediately be able to cut the

problem with binarysearch algorithm

一世执手 提交于 2019-12-12 06:56:32
问题 the code below belongs to binary search algorithm,user enter numbers in textbox1 and enter the number that he want to fing with binarysearch in textbox2.i have a problem with it,that is when i enter for example 15,21 in textbox1 and enter 15 in textbox2 and put brakpoint on the line i commented below,and i understood that it doesnt put the number in textbox2 in searchnums(commented),for more explanation i comment in code.thanks in advance public void button1_Click(object sender, EventArgs e)

Optimize Binary Search

天大地大妈咪最大 提交于 2019-12-12 04:22:00
问题 I am new to python, and very much enthusiastic to learn algorithm. I have written sample code for Binary search, can any one suggest how can i achieve same result in more pythonic way (Optimize the code, or using Bisect if any way possible)? def bee_search(alist, target): sort_list = sorted(alist) while len(sort_list) >= 1: end = len(sort_list) middle = int((0 + end)/2) if target == sort_list[middle]: print "Found it", str(sort_list[middle]) break elif target > sort_list[middle]: sort_list =

Binary search warning in CFArrayBSearchValues

久未见 提交于 2019-12-12 02:34:14
问题 i'm using CFArrayBSearchValues . Ref: http://developer.apple.com/library/mac/documentation/CoreFoundation/Reference/CFArrayRef/Reference/reference.html#//apple_ref/doc/uid/20001192-CH201-F10956 It works successfully but compiler show me a warning on first parameter: CFIndex indexResult = CFArrayBSearchValues( m_Locations, CFRangeMake(0, [m_Locations count]), data, PGPlaceDataCompare, nil); CFArrayBSearch expect as first parameter an CFArrayRef . My m_Locations is an NSMutableArray . How to

Finding roots of a function with binary search and recursion

左心房为你撑大大i 提交于 2019-12-12 02:27:49
问题 Could someone explain, please, why we need a difference between max and min to be less than error (of the root of the cubic equation)? What is the logic behind it? And why we need to return min? Here's the code: #include <stdio.h> #include <stdlib.h> double func(double x) { return x * x * x + 2 * x * x - 2; } double zeroFinder(double min, double max, double error) { if ((max - min) < error) { return min; } double x = (max + min) / 2; if (func(x) < 0) { min = x; } else { max = x; } return

Go recursive binary search

大兔子大兔子 提交于 2019-12-12 00:56:03
问题 I know that Go has a sort package that contains search functions, but this is for educational purposes. I've been trying to implement a binary search algorithm in Go but I haven't been able to get it to work. Here is my code: package main import "fmt" func BinarySearch(data []int, target int, low int, high int) (index int, found bool) { mid := (high + low) / 2 if low > high { index = -1 found = false } else { if target < data[mid] { BinarySearch(data, target, low, mid - 1) } else if target >

Binary search to find last element in sorted list that is less then specific value

て烟熏妆下的殇ゞ 提交于 2019-12-11 23:49:39
问题 I am searching through a dictionary of messages, that contain unixtimes, with length N, where I want to find maximum number of messages (I call this the frequency) that is inside an arbitrary 24 hour (86400 seconds) time slot. That means that if there are five messages with an unixtime within 24 hours of one I want 5. I want to accomplish this with binary search, but I am a little bit in the wild on how I can implement that as best, and if I can use some binarysearch library. This is how I do

Trouble with Binary Search

亡梦爱人 提交于 2019-12-11 21:34:21
问题 there. I am trying to have a binary search of a text file. I am comparing text file one to text file two. However, My binary algorith seems to not work nd print out the element it has found. My text file 2 is a sorted list and my textfile1 is the key. I need some guidance on how to figure this problem out. Here is my code: bool binary_search(const vector<string>& sorted_vec, const vector<string>& key) { size_t mid, left = 0; size_t right = sorted_vec.size(); // one position passed the right

Binary string search in Python 3.x

懵懂的女人 提交于 2019-12-11 20:11:36
问题 I am having trouble getting this binary sort to work. I get syntax errors at lower_bound and in other places. I know it is something obvious but I am getting to the desk flipping point. Can someone help me to get this to run clearly, I know this is basic stuff but I am fairly new to this. def main(): sortNames() binarySearch() def sortNames(): global names names = ["Chris Rich", "Ava Fischer", "Bob White", "Danielle Porter", "Gordon Pike", "Hannah Beauregard", "Matt Hoyle", "Ross Harrison",