binary-search-tree

问题 Can anyone please explain the difference between binary tree and binary search tree with an example ? 回答1: Binary tree: Tree where each node has up to two leaves 1 / \ 2 3 Binary search tree: Used for searching . A binary tree where the left child contains only nodes with values less than the parent node, and where the right child only contains nodes with values greater than or equal to the parent. 2 / \ 1 3 回答2: Binary Tree is a specialized form of tree with two child (left child and right

问题 What are the advantages of binary search trees over hash tables? Hash tables can look up any element in Theta(1) time and it is just as easy to add an element....but I\'m not sure of the advantages going the other way around. 回答1: Remember that Binary Search Trees (reference-based) are memory-efficient. They do not reserve more memory than they need to. For instance, if a hash function has a range R(h) = 0...100 , then you need to allocate an array of 100 (pointers-to) elements, even if you

问题 I\'m working on a project for class that involves generics. public interface Keyable <T> {public String getKey();} public interface DataElement extends Comparable<Keyable<DataElement>>, Keyable<DataElement>, Serializable {...} public class Course implements DataElement {...} public interface SearchTree<K extends Comparable<Keyable<K>> & Keyable<K>> extends Serializable {...} public class MySearchTree implements SearchTree<Course> { ... private class Node { public Course data; public Node left

问题 Given a node in a BST, how does one find the next higher key? 回答1: The general way depends on whether you have a parent link in your nodes or not. If you store the parent link Then you pick: The leftmost child of the right child, if your current node has a right child. If the right child has no left child, the right child is your inorder successor. Navigate up the parent ancestor nodes, and when you find a parent whose left child is the node you're currently at, the parent is the inorder

问题 What is the difference between a heap and BST? When to use a heap and when to use a BST? If you want to get the elements in a sorted fashion, is BST better over heap? 回答1: Summary Type BST (*) Heap Insert average log(n) 1 Insert worst log(n) log(n) or n (***) Find any worst log(n) n Find max worst 1 (**) 1 Create worst n log(n) n Delete worst log(n) log(n) All average times on this table are the same as their worst times except for Insert. * : everywhere in this answer, BST == Balanced BST,

问题 I read on here of an exercise in interviews known as validating a binary search tree. How exactly does this work? What would one be looking for in validating a binary search tree? I have written a basic search tree, but never heard of this concept. 回答1: Actually that is the mistake everybody does in an interview. Leftchild must be checked against (minLimitof node,node.value) Rightchild must be checked against (node.value,MaxLimit of node) IsValidBST(root,-infinity,infinity); bool IsValidBST

问题 Given the following problem: \"Store the largest 5000 numbers from a stream of numbers\" The solution which springs to mind is a binary search tree maintaining a count of the number of nodes in the tree and a reference to the smallest node once the count reaches 5000. When the count reaches 5000, each new number to add can be compared to the smallest item in the tree. If greater, the new number can be added then the smallest removed and the new smallest calculated (which should be very simple

问题 Why is std::map implemented as a red-black tree? There are several balanced binary search trees (BSTs) out there. What were design trade-offs in choosing a red-black tree? 回答1: Probably the two most common self balancing tree algorithms are Red-Black trees and AVL trees. To balance the tree after an insertion/update both algorithms use the notion of rotations where the nodes of the tree are rotated to perform the re-balancing. While in both algorithms the insert/delete operations are O(log n)