binary-search-tree

Difference between binary search and binary search tree?

北战南征 提交于 2019-12-02 15:13:19
What is the difference between binary search and binary search tree? Are they the same? Reading the internet it seems the second is only for trees (up to 2 children nodes) and binary search doesn't follow this rule. I didn't quite get it. Binary Search Trees A node in a binary tree is a data structure that has an element, and a reference to two other binary trees, typically called the left and right subtrees. I.e., a node presents an interface like this: Node: element (an element of some type) left (a binary tree, or NULL) right (a binary tree, or NULL) A binary search tree is a binary tree (i

Real world examples of tree structures

怎甘沉沦 提交于 2019-12-02 14:19:35
I'm looking for some examples of tree structures that are used in commercial/free software projects, modern or old. I can see examples on wikipedia, but I am looking for more concrete examples and how they're used. For example primary keys in databases are (from what I've read) stored in BST structure or a variation of the BST (feel free to correct me on this) My question isn't limited Binary Search Trees (BSTs), it can include any variation such as red-black, AVL and so on. dirkgently Is it okay if the examples are a tad bit generic i.e. relate to graphs and not necessarily to trees? If it is

BST insert not working

六月ゝ 毕业季﹏ 提交于 2019-12-02 10:21:15
I was trying to implement a code for binary search trees. Problem is following code is not working but it works if I pass double pointer to insert funcion like insert(struct bst** node, data). I think it should also work with passing single pointers. Can anyone explain what is the error here ? void insert(struct bst* node, int data ) { if (node == NULL) { printf("here with %d\n",data); node = (struct bst*)malloc(sizeof(struct bst)); node->data = data; node->left = NULL; node->right = NULL; } if(data < node->data) { insert(node->left,data); } else if(data > node->data) { insert(node->right,data

A complete Binary Search Tree with level order insert in Java

喜你入骨 提交于 2019-12-02 09:55:49
We got an assignment where we need to code: A Binary Search Tree The Tree has to be complete , not perfect (which means all nodes which are not on the lowest level or second lowest level should have 2 children, while the nodes on the lowest level should be as far left as possible) We need to insert to the tree in level order So if I have an Array with elements {0, 1, 2, 3, 4, 5, 6, 7} the root should be 4 , with 2, 1, 3, 0 on the left side, and 6, 5, 7 on the right side. The level order insert would be: 4, 2, 6, 1, 3, 5, 7, 0 Just taking the middle of the Array and put it as root doesn't work.

Why is the root always null in this method insert method for binary tree

岁酱吖の 提交于 2019-12-02 09:25:43
Iam trying to implement a recursive insert node method for BST class public void insertNode(Node r, Node n) { if(r == null) { System.out.println("r=n"+ n.data); r = n; } else { System.out.println("r=! null finding place in tree for "+ n.data); if(n.data <= r.data) { if(r.left == null) r.left = n; else insertNode(r.left, n); } else { if(r.right == null) r.right = n; else insertNode(r.right, n); } } } Im trying to invoke this method like so: int[] arrTree = {34, 2, 56, 12, 44, 39, 56, 1}; BT t = new BT(); for (int i = 0; i < arrTree.length; i++) { //System.out.println("Tree Root = "+ t.getRoot()

Delete an element from a binary search tree in F#

眉间皱痕 提交于 2019-12-02 08:00:22
问题 I'm trying to write a method to delete an element from a BST. So far, this is what I have. I'm not sure if I'm on the right track or if there is a better way to do it by using pattern matching to match the different delete cases ie: no children, 1 child, 2 children. type 'a bst = NL | BinTree of 'a * 'a bst * 'a bst;; let rec smallest = function | NL -> failwith "tree is empty" | BinTree(m, lst, rst) -> if lst = NL then BinTree(m, lst, rst) else smallest lst;; let rec smallest2 = function |

How to find height of BST iteratively?

夙愿已清 提交于 2019-12-02 07:51:26
public void HeightIterative() { int counter = 0; int counter2 = 0; TreeNode current=root; if(current != null) { while(current.LeftNode!=null) { counter++; current = current.LeftNode; } while(current.RightNode!=null) { counter2++; current = current.RightNode; } } int res = 1+Math.Max(counter, counter2); Console.WriteLine("The Height Of Tree Is: "+res); } I wrote iterative method, to calculate height of tree. but in some cases its not working properly. As in case: 10 1 2 3 4 5 18 17 16 15 14 13 what's the problem. according to this sequence height of tree is 6 where as my code is showing 5. You

How can I specify the range of a random number?

江枫思渺然 提交于 2019-12-02 07:47:40
I have binary search tree code that inserts numbers randomly. I can modify size each time, but I want to modify the range of numbers, for example: I want the random number be just one digit or just 2 digits. How can I do that? public static void main( String[ ] args ) { BinarySearchTree bst = new BinarySearchTree( ); Random random = new Random( System.currentTimeMillis() ); int[] randoms = new int[1000]; Random randGen = new Random(); for(int i = 0; i < randoms.length; i++) { bst.insert( random.nextInt( randoms.length ) ); } System.out.println( "\n sorted :" ); bst.inorderTraversal( ); bst

Balanced binary tree python

感情迁移 提交于 2019-12-02 07:45:35
# stack_depth is initialised to 0 def find_in_tree(node, find_condition, stack_depth): assert (stack_depth < max_stack_depth), 'Deeper than max depth' stack_depth += 1 result = [] if find_condition(node): result += [node] for child_node in node.children: result.extend(find_in_tree(child_node, find_condition, stack_depth)) return result I need help understanding this piece of code. The question i want to answer is The Python function above searches the contents of a balanced binary tree. If an upper limit of 1,000,000 nodes is assumed what should the max_stack_depth constant be set to? From

Height of binary search tree in constant time

微笑、不失礼 提交于 2019-12-02 05:01:42
I need to fine the height of a binary search tree with a time of O(1) the only way i could think to do this is to put a check in the add and remove methods incrementing a global counter is there any other way? O(1) time suggests that you should already have the height when it is requested. The best way is it to keep/update the correct value whenever a new node is added/deleted . You are doing it in a right way , however it increases the complexity on addition and deletion. You can do it number of ways , like keep the depth value along with the node in tree etc. class Node{ int depth; Object