bigint

What to do when you need integers larger than 20 digits on mysql?

▼魔方 西西 提交于 2019-11-26 21:33:46
问题 Seems like BIGINT is the biggest integer available on MySQL, right? What to do when you need to store a BIGINT(80) for example? Why in some cases, like somewhere in the Twitter API docs, they recommend us to store these large integers as varchar ? Which is the real reason behind the choice of using one type over another? 回答1: Big integers aren't actually limited to 20 digits, they're limited to the numbers that can be expressed in 64 bits (for example, the number 99,999,999,999,999,999,999 is

mysql 树形结构查询(存储过程)

喜欢而已 提交于 2019-11-26 19:04:25
就用数据数据库表地址数据(中国地区) 来说吧(用Windows 请使用 gbk !!) 可直接运行(去除注解) 存储过程: DELIMITER // drop procedure if exists findLChild // /* iid 递归父节点 , layer 允许递归深度 */ CREATE PROCEDURE findLChild(iid bigint ( 20 ),layer bigint ( 20 )) BEGIN /* 创建接受查询的临时表 */ create temporary table if not exists tmp_table(id bigint ( 20 ),name varchar ( 50 )) ENGINE = InnoDB DEFAULT CHARSET = utf8; /* 最高允许递归数 */ SET @@max_sp_recursion_depth = 99 ; call iterative(iid,layer); /* 核心数据收集 */ select * from tmp_table ; /* 展现 */ drop temporary table if exists tmp_table ; /* 删除临时表 */ END ; // DELIMITER ; DELIMITER // drop procedure if exists

Efficient 128-bit addition using carry flag

心不动则不痛 提交于 2019-11-26 18:49:26
I'm using a 128 bit integer counter in the very inner loops of my C++ code. (Irrelevant background: The actual application is evaluating finite difference equations on a regular grid, which involves repetitively incrementing large integers, and even 64 bits isn't enough precision because small rounding accumulates enough to affect the answers.) I've represented the integer as two 64 bit unsigned longs. I now need to increment those values by a 128 bit constant. This isn't hard, but you have to manually catch the carry from the low word to the high word. I have working code something like this:

Is there a 128 bit integer in gcc?

喜夏-厌秋 提交于 2019-11-26 17:58:40
I want a 128 bit integer because I want to store results of multiplication of two 64 bit numbers. Is there any such thing in gcc 4.4 and above? A 128-bit integer type is only ever available on 64-bit targets , so you need to check for availability even if you have already detected a recent GCC version. In theory gcc could support TImode integers on machines where it would take 4x 32-bit registers to hold one, but I don't think there are any cases where it does. GCC 4.6 and later has a __int128 / unsigned __int128 defined as a built-in type. Use #ifdef __SIZEOF_INT128__ to detect it. GCC 4.1

Big integer in C or C++ [closed]

。_饼干妹妹 提交于 2019-11-26 17:29:28
问题 I was working on a factorial program, and the program didn't work when trying to find the factorial of 1000. I think big integers are the solution; how do they work? (In either C or C++) 回答1: GMP can do bigint operations for both C and C++. The documentation on that site is a good introduction, if you use the C++ classes they behave almost exactly like built-in primitive types. 回答2: Look for the GMP. See the other question regarding this topic: Handling very large Integers C++ Big Integer 来源:

SqlServer中SubString与CharIndex函数的使用 SubString和CharIndex结合使用

笑着哭i 提交于 2019-11-26 17:28:56
一、CharIndex 1:CharIndex语法: CharIndex(expression1,expression2[,start_location]) 2:参数 expression1 一个表达式,其中包含要查找的字符的序列。expression1是一个字符串数据类别的表达式。 expression2 一个表达式,通常是一个为指定序列搜索的列。expression2属于字符串数据类别. start_location 开始在expression2中搜索expression1时的字符位置。如果start_location未被指定、是一个负数或零,则将从espression2的开头开始搜索。start_location可以是bigint类型。 3:返回类型 如果expression2的数据类型为varchar(max),nvarchar(max)或varbinnary(max),则为bigint,否则为int。 4:备注 如果在expression2内找不到expression1,则charindex返回0. charindex将根据输入的排序规则执行比较操作。若要以指定排序规则进行比较,则可以使用collate将显式排序规则应用于输入值。 返回的开始位置从1开始,而非从0开始。 5:例子 select charindex('A','BADF',1) : 2 select

node.js is there any proper way to parse JSON with large numbers? (long, bigint, int64)

别等时光非礼了梦想. 提交于 2019-11-26 16:49:47
问题 When I parse this little piece of JSON { "value" : 9223372036854775807 } that's what I get { hello: 9223372036854776000 } Is there any way to parse it properly? 回答1: Not with built-in JSON.parse. You'll need to parse it manually and treat values as string (if you want to do arithmetics with them there is bignumber.js) You can use Douglas Crockford JSON.js library as a base for your parser. EDIT: I created a package for you :) var JSONbig = require('json-bigint'); var json = '{ "value" :

What is the simplest way of implementing bigint in C?

╄→尐↘猪︶ㄣ 提交于 2019-11-26 15:21:01
I am trying to calculate 100! I am looking for the simplest way to accomplish this using C. I have read around but have not found a concrete answer. If you must know, I program in Xcode in Mac os X. Thanks! If you're looking for a simple library, libtommath (from libtomcrypt) is probably what you want. If you're looking to write a simple implementation yourself (either as a learning exercise or because you only need a very limited subset of bigint functionality and don't want to tack on a dependency to a large library, namespace pollution, etc.), then I might suggest the following for your

How to use long id in Rails applications?

时光毁灭记忆、已成空白 提交于 2019-11-26 12:04:05
问题 How can I change the (default) type for ActiveRecord\'s IDs? int is not long enough, I would prefer long. I was surprised that there is no :long for the migrations - does one just use some decimal? 回答1: Credits to http://moeffju.net/blog/using-bigint-columns-in-rails-migrations class CreateDemo < ActiveRecord::Migration def self.up create_table :demo, :id => false do |t| t.integer :id, :limit => 8 end end end See the option :id => false which disables the automatic creation of the id field

Efficient 128-bit addition using carry flag

这一生的挚爱 提交于 2019-11-26 06:37:14
问题 I\'m using a 128 bit integer counter in the very inner loops of my C++ code. (Irrelevant background: The actual application is evaluating finite difference equations on a regular grid, which involves repetitively incrementing large integers, and even 64 bits isn\'t enough precision because small rounding accumulates enough to affect the answers.) I\'ve represented the integer as two 64 bit unsigned longs. I now need to increment those values by a 128 bit constant. This isn\'t hard, but you