bigint

Scala Converting multiline string to BigInt

♀尐吖头ヾ 提交于 2019-12-01 18:40:26
I'm trying to parse 100 50-digit numbers from string with below piece of code: val input = """37107287533902102798797998220837590246510135740250 |46376937677490009712648124896970078050417018260538 |74324986199524741059474233309513058123726617309629""".stripMargin val list = input.split("""\n""").map(BigInt(_)) but I'm ending with "java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)". I don't have any idea why this does not work, since when string is splited, each element of list is of type String. Any help would be much appreciated. Best regards Probably you're on

SQL bigint hash to match c# int64 hash [duplicate]

依然范特西╮ 提交于 2019-12-01 16:55:19
This question already has an answer here: SQL Server varbinary bigint with BitConverter.ToInt64 values are different 1 answer I am trying to create a universal hashing alogrithim that hashes a string as a 64 bit int. I am able to hash the strings correctly: sql: select convert ( varchar(64), HASHBYTES ( 'SHA1', 'google.com' ), 2 ) returns BAEA954B95731C68AE6E45BD1E252EB4560CDC45 C# System.Security.Cryptography.SHA1 c = System.Security.Cryptography.SHA1.Create(); System.Text.StringBuilder sb = new StringBuilder(); byte[] b = c.ComputeHash(Encoding.UTF8.GetBytes("google.com")); for (int i = 0; i

How can I form a SQL Query for a HSQLDB that counts the # of rows per day using a BIGINT type for a date?

被刻印的时光 ゝ 提交于 2019-12-01 14:22:59
I have an HSQLDB, ver. 1.8.0, database with a sample schema with something like this: CREATE CACHED TABLE ENTRY (ENTRYID INTEGER GENERATED BY DEFAULT AS IDENTITY(START WITH 0) NOT NULL PRIMARY KEY, REQID VARCHAR, REVOCATIONDATE BIGINT) I would like to retrieve a row count for every date, something like this: ENTRYID DATE_COUNT REVOCATIONDATE 1 10 2014-01-01 2 5 2014-01-02 3 15 2014-01-03 The problem is that the REVOCATIONDATE is a BIGINT instead of a normal date or timestamp. This is a vendor provided DB so, assume the schema is not allowed to be changed. How can I create a SQL query that will

ID生成算法(一)——雪花算法

二次信任 提交于 2019-12-01 12:18:46
JavaScript生成有序GUID或者UUID,这时就想到了雪花算法。 原理介绍: snowFlake算法最终生成ID的结果为一个64bit大小的整数,结构如下图: 解释: 1bit。二进制中最高位为1表示负数,但是我们最终生成的ID一般都是整数,所以这个最高位固定为0。 41bit。用于记录时间戳(毫秒) 41bit可以表示2 41 -1个数字 如果只用来表示正整数(计算机中正数包含0),可以表示的数值范围是0到2 41 -1,减1是因为可表示的数值范围从0开始计算,而不是1. 即41bit可以表示2 41 -1个毫秒值转换为年为(2 41 - 1) / (1000 * 60 * 60 * 24 * 365) = 69.73年 10bit。用于记录机器ID 可以用于部署2 10 =1024个节点,包含5bit 的 datacenterId 和5bit 的workerId 5bit可以表示的最大正整数为2 5 -1=31 即可以用0、1、2、3....31这32个数字来表示不同的datacenterId 和 workerId 12bit。序列号用于记录相同毫秒内产生的不同ID 12bit可以表示的最大正整数为2 12 -1 = 4095,可以用0、1、2、3...4094这4095个数字来表示同一机器同一时间戳(毫秒)内产生的4095个ID序号 snowFlake算法可以保证

Calculating big float number fast like 0.4 ^ 100000000 ,, any ideas?

大城市里の小女人 提交于 2019-12-01 08:19:10
问题 Ehm ... I got a problem I've a certain calculation that result is over 10^-308 (the biggest value in double .net ) any way I solved this problem through a library called BIGFLOAT http://www.fractal-landscapes.co.uk/bigint.html , What ever I need to calculate something like 0.4 ^(1000 or 100000000) the problem it takes very very long time I didn't study parallel or distributed programming yet but I need a solution that is fast and understandable for me I'm going to deliver this project in next

Mysql returning incorrect bigint result by one, very strange error

无人久伴 提交于 2019-12-01 05:24:46
I really don't know what is going on here. I have a database table that looks like this: With this data: When I run this query SELECT * FROM game WHERE id = 4 in phpmyadmin I get back this result as expected: But when I make this query on it through a rest api (where gameId = 4) var query = connection.query("SELECT * FROM game WHERE id = ? ",[game.gameId],function(err,rows){ I get this result Where adminId for some reason has been subtracted by one. I really haven't a clue what is going on. I have tried dropping the table and setting it back up, has anyone experienced this before? Or know what

Sequelize 数据类型

谁说胖子不能爱 提交于 2019-12-01 05:18:11
Sequelize.STRING // VARCHAR(255) Sequelize.STRING(1234) // VARCHAR(1234) Sequelize.STRING.BINARY // VARCHAR BINARY Sequelize.TEXT // TEXT Sequelize.TEXT('tiny') // TINYTEXT Sequelize.INTEGER // INTEGER Sequelize.BIGINT // BIGINT Sequelize.BIGINT(11) // BIGINT(11) Sequelize.FLOAT // FLOAT Sequelize.FLOAT(11) // FLOAT(11) Sequelize.FLOAT(11, 12) // FLOAT(11,12) Sequelize.REAL // REAL 仅限于PostgreSQL. Sequelize.REAL(11) // REAL(11) 仅限于PostgreSQL. Sequelize.REAL(11, 12) // REAL(11,12) 仅限于PostgreSQL. Sequelize.DOUBLE // DOUBLE Sequelize.DOUBLE(11) // DOUBLE(11) Sequelize.DOUBLE(11, 12) // DOUBLE(11

MySQL5.6 PERFORMANCE_SCHEMA 说明

陌路散爱 提交于 2019-12-01 05:08:56
背景: MySQL 5.5开始新增一个数据库:PERFORMANCE_SCHEMA,主要用于收集数据库服务器性能参数。并且库里表的存储引擎均为PERFORMANCE_SCHEMA,而用户是不能创建存储引擎为PERFORMANCE_SCHEMA的表。 MySQL 5.5默认是关闭的,需要手动开启,在配置文件里添加: view source print ? 1. [mysqld] 2. performance_schema=ON 查看是否开启: view source print ? 1. mysql>show variables like 'performance_schema' ; 2. +--------------------+-------+ 3. | Variable_name | Value | 4. +--------------------+-------+ 5. | performance_schema | <strong>ON</strong> | 6. +--------------------+-------+ 从MySQL5.6开始,默认打开,本文就从MySQL5.6来说明,在数据库使用当中PERFORMANCE_SCHEMA的一些比较常用的功能。具体的信息可以查看官方文档。 相关表信息: 一:配置(setup)表: view source print ?

Convert nvarchar to bigint in Sql server 2008

≡放荡痞女 提交于 2019-12-01 02:54:47
I want insert all rows of a table into another table, and I also want convert a nvarchar field into bigint , but when I use convert(bigint, col1) SQL Server shows an error: Error converting data type nvarchar to bigint How can I fix this problem? You could try to use ISNUMERIC to determine those rows that are indeed numeric: UPDATE dbo.YourTable SET BigIntColumn = CAST(NVarcharColumn AS BIGINT) WHERE ISNUMERIC(NVarcharColumn) = 1 That would convert those rows that can be converted - the others need to be dealt with manually. You should convert bigint to nvarchar not vice versa cast(Other

Int、bigint、smallint、tinyint的区别

本秂侑毒 提交于 2019-12-01 01:29:18
Bigint :从-2^63-2^63的整型数据(所有数字)。存储大小为8个字节。Bigint已经有长度了,在mysql建表中的length,只是用于显示的位数。 Int: 从-2^31-2^31的整型数据(所有数字)。存储大小为4个字节。Int的SQL-92同义字为integer。 Smallint: 从-2^15到2^15的整型数据。存储大小为2个字节。 Tinyinit: 从0到255的整型数据。存储大小为1字节。 注释: 在支持整数值的地方支持bigint数据类型。但是,bigint用于某些特殊的情况,当整数值超过int数据类型支持的范围时,就可以采用bigint。在SQL Sever中,int数据类型是主要的整数数据类型。 在数据类型优先次序表中,bigint位于smallmoney和int之间。 只有当参数表达式是bigint数据类型时,函数才返回bigint。SQL Sever不会自动将其他整数数据类型(tinyint、smallint、int)提升bigint。 Int(M)在integer数据类型中,M表示最大显示宽度。在int(M)中,M的值跟int(M)所占存储空间并无任何关系。和数字位数也无关系int(3)、int(4)、int(8)在磁盘都是占据4 btyes的存储空间。 参考网址: https://www.imooc.com/article/41543