average

In Python, how to get the sum and average while in a loop

风格不统一 提交于 2019-12-01 13:16:42
问题 I've managed to implement a loop but keep getting a syntax error when I try the sum function. I need the numbers input by the user to be totalled and the average given as well. This has to be outputted to the user. Could you please guide me on where to go from here, thank you. This is what I've done so far: while 1: NumCalc = input ("Enter Number :") if NumCalc == "done": break 回答1: This is what you can do if you want to compute the sum and the mean after the loop ends: nums = [] while 1:

Comparing the MD5 results of split files against the MD5 of the whole

試著忘記壹切 提交于 2019-12-01 12:16:52
I have a situation where I have one VERY large file that I'm using the linux "split" command to break into smaller parts. Later I use the linux "cat" command to bring the parts all back together again. In the interim, however, I'm curious... If I get an MD5 fingerprint on the large file before splitting it, then later get the MD5 fingerprints on all the independent file parts that result from the split command, is there a way to take the independent fingerprints and somehow deduce that the sum or average (or whatever you like to all it) of their parts is equal to the fingerprint of the single

Comparing the MD5 results of split files against the MD5 of the whole

[亡魂溺海] 提交于 2019-12-01 10:55:07
问题 I have a situation where I have one VERY large file that I'm using the linux "split" command to break into smaller parts. Later I use the linux "cat" command to bring the parts all back together again. In the interim, however, I'm curious... If I get an MD5 fingerprint on the large file before splitting it, then later get the MD5 fingerprints on all the independent file parts that result from the split command, is there a way to take the independent fingerprints and somehow deduce that the

C++: Mean Median and Mode

♀尐吖头ヾ 提交于 2019-12-01 10:34:19
I've recently created a C++ program to find the mean median and mode of an array of values. I realize this would be much better to do within a class. However, my function to generate the mean is not spitting out the right number, although I'm pretty certain the logic is fine. Also, I was able to modify a snipbit from something I found online to create a function that generates the mode, or at least the 1st most occurring values it can find, that I was able to implement. However, I am not 100% sure of how to wrap my head around what is actually happening within the function. A better

required: double [] found: no arguments

和自甴很熟 提交于 2019-12-01 09:39:36
Code: ArrayList <Integer> marks = new ArrayList(); String output = "Class average:" + calculateAverage() + "\n" + "Maximum mark:" + calculateMaximum() + "\n" +"Minimum mark:" + calculateMinimum() + "\n" + "Range of marks:" + range; analyzeTextArea.setText(output); private double calculateAverage(double [] marks) { double sum = 0; for (int i=0; i< marks.length; i++) { sum += marks[i]; } return sum / marks.length; } Disregard the other things inside the string (minimum, maximum, and range) but for this line, String output = "Class average:" + calculateAverage() + "\n" + "Maximum mark:" +

C++: Mean Median and Mode

拜拜、爱过 提交于 2019-12-01 07:34:18
问题 I've recently created a C++ program to find the mean median and mode of an array of values. I realize this would be much better to do within a class. However, my function to generate the mean is not spitting out the right number, although I'm pretty certain the logic is fine. Also, I was able to modify a snipbit from something I found online to create a function that generates the mode, or at least the 1st most occurring values it can find, that I was able to implement. However, I am not 100%

Find the average of an NSMutableArray with valueForKeyPath

╄→尐↘猪︶ㄣ 提交于 2019-12-01 06:01:44
Currently I'm trying to find a compact way to average a matrix . The obvious solution is to sum the matrix, then divide by the number of elements. I have, however, come across a method on the apple developer website that claims this can be done in a simpler way using valueForKeyPath. This is linked here: http://developer.apple.com/library/ios/#documentation/cocoa/conceptual/KeyValueCoding/Articles/CollectionOperators.html Here is the example I'm currently working on to try and get it to work: -(void)arrayAverager { NSMutableArray *myArray = [NSMutableArray arrayWithCapacity:25]; [myArray

django aggregation to lower resolution using grouping by a date range

你。 提交于 2019-12-01 05:52:12
horrible title, but let me explain: i've got this django model containing a timestamp (date) and the attribute to log - f.e. the number of users consuming some ressource - (value). class Viewers(models.Model): date = models.DateTimeField() value = models.IntegerField() for each 10seconds the table contains the number of users. something like this: | date | value | |------|-------| | t1 | 15 | | t2 | 18 | | t3 | 27 | | t4 | 25 | | .. | .. | | t30 | 38 | | t31 | 36 | | .. | .. | now i want to generate different statistics from this data, each with another resolution. f.e. for a chart of the last

Find the average of an NSMutableArray with valueForKeyPath

拜拜、爱过 提交于 2019-12-01 03:58:42
问题 Currently I'm trying to find a compact way to average a matrix . The obvious solution is to sum the matrix, then divide by the number of elements. I have, however, come across a method on the apple developer website that claims this can be done in a simpler way using valueForKeyPath. This is linked here: http://developer.apple.com/library/ios/#documentation/cocoa/conceptual/KeyValueCoding/Articles/CollectionOperators.html Here is the example I'm currently working on to try and get it to work:

“circular” mean in R

ⅰ亾dé卋堺 提交于 2019-12-01 03:31:28
Given a dataset of months, how do I calculate the "average" month, taking into account that months are circular? months = c(1,1,1,2,3,5,7,9,11,12,12,12) mean(months) ## [1] 6.333333 In this dummy example, the mean should be in January or December. I see that there are packages for circular statistics, but I'm not sure whether they suit my needs here. I think months <- c(1,1,1,2,3,5,7,9,11,12,12,12) library("CircStats") conv <- 2*pi/12 ## months -> radians Now convert from months to radians, compute the circular mean, and convert back to months. I'm subtracting 1 here assuming that January is