average

问题 I want to calculate the average slope or gradient at each iteration in such a matrix. a=[ 10 9 8 7 6 5 5; 9 9 8 7 8 5 5; 8 8 7 7 5 5 5; 7 7 7 6 5 5 5; 6 6 6.6 5 5 5 5; 6 6 6.1 5 5 5 5; 6.3 5 5 5 5 5 5] Where I am wanting to find the slope or gradient between the a(1,1) position during each step and at each point that boarders a value of 5. Each iteration the position of the 5's changes and so do the other values. After doing so I will then average the slope. I haven't encountered a problem

问题 I have a temporal database and I want to perform the temporal aggregation via average function on time series data by using data in time sequence of following: Hourly average of HH= (HH-1):51, HH:01, HH:11, HH:21, HH:31, HH:41. Moreover, aforementioned values are instantaneous values. Sample data: ambtemp ddate_ttime 1 -1.42 2007-09-28 23:39:09 2 -1.24 2007-09-28 23:41:09 3 -1.28 2007-09-28 23:43:09 4 -1.28 2007-09-28 23:45:09 5 -1.24 2007-09-28 23:47:09 6 -1.42 2007-09-28 23:49:09 7 -1.68

问题 I am building an app using Phonegap and JQuery. The app stores ( using window.localStorage ) a set of times (no more than 10) in the format. HH:MM:SS.mm There are a number of 'Zero' times in the list eg '00:00:00.00' which iphonegap, javascript eliminate using.. function removeA(arr){ var what, a= arguments, L= a.length, ax; while(L> 1 && arr.length){ what= a[--L]; while((ax= arr.indexOf(what))!= -1){ arr.splice(ax, 1); } } return arr; } scores.sort(); removeA(scores,'00:00:00.00'); so that i

问题 I have a problem. I need to get average length from this list: (1 (2 3 4) 5 (6 7) 8 (9)) . It should be 2. And I have no idea where to start... I tried to get (1 2 3 4 5 6 7 8 9) from (1 (2 3 4) 5 (6 7) 8 (9)) but I failed, because (reduce #'append list-name) isn't working. I have idea how to calculate this but I need to get all lists inside (1 (2 3 4) 5 (6 7) 8 (9)) like this: list1 = (1 5 8) list2 = (2 3 4) list3 = (6 7) list4 = (9) But I don't know how. Can u give me some help? 回答1: (defun

问题 This script uses php and mysql to compute a one minute rolling average to reduce the impact of outliers on the my data (one minute = 6 10-second rows). It computes everything correctly, but is not efficient enough to do more than 150 rows at a time. I'd like to do as many rows as I can at a time, possibly between 5-10,000 as my table is over 150,000 and I input approximately 8,000 rows per day. Does anyone have any suggestions as to how I can make this script run more efficiently? Thanks! <

问题 I am attempting to find the average case time complexity, not amortized analysis, of a binary counter. As I am not entirely confident in my time complexity analyzing skills, I would like to confirm that my average case analysis of the pseudocode provided below is correct. Let k be the length of the array. Increment(Array) i = 0 while i < k and Array[i] == 1 Array[i] = o i = i + 1 if i < k Array[i] = 1 In order to find the average time taken, I find the average amount of bits flipped per run.

问题 I'm trying to find the average of a 'ratings' column for all the data that has the same 'VenueId'. I have it working with raw code but need to adapt it in Sequelize. The working raw code is SELECT venueId, AVG(rating) AS average FROM reviews GROUP BY VenueId The code I've tried is Review.findAll({ order: [[Sequelize.fn('AVG', Sequelize.col('rating'))]] }).then(function(Venues) {}) I'm getting an error: Executing (default): SELECT id, review, rating, createdAt, updatedAt, VenueId FROM Reviews

问题 date daily weekly monthly 1 11 88 2 12 3 45 44 4 54 5 45 6 45 66 7 77 8 78 9 71 99 88 For empty data points in weekly column , the plot is ploting values from monthly column. Monthly column plot and daily column plot are perfect. suggest something more than set datafile missing ' ' and set datafile separator "\t" 回答1: Alas, Gnuplot doesn't support field based data files, the only current solution is is to preprocess the file. awk is well suited for the task (note if the file contains hard

问题 I have a separated .txt file in which there is a list of "students" with their own mark on the side that goes from 0 to 10, here is an example on how the .txt looks like: Mark 2 Elen 3 Luke 7 Elen 9 Jhon 5 Mark 4 Elen 10 Luke 1 Jhon 1 Jhon 7 Elen 5 Mark 3 Mark 7 What I want to do is calculating the Average of each student (expressed in double ) so that the output would look like this: Mark: 4.0 Elen: 6.75 Luke: 4.0 Jhon: 4.33 Here is what I've come up with, for now I've only managed to use

问题 I am working with a dataset that has temperature readings once an hour, 24 hrs a day for 100+ years. I want to get an average temperature for each day to reduce the size of my dataset. The headings look like this: YR MO DA HR MN TEMP 1943 6 19 10 0 73 1943 6 19 11 0 72 1943 6 19 12 0 76 1943 6 19 13 0 78 1943 6 19 14 0 81 1943 6 19 15 0 85 1943 6 19 16 0 85 1943 6 19 17 0 86 1943 6 19 18 0 86 1943 6 19 19 0 87 etc for 600,000+ data points. How can I run a nested function to calculate daily